Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume Solution

STEP 0: Pre-Calculation Summary
Formula Used
Work done in Thermodynamic Process = (Initial Pressure of System*Initial Volume of System-Final Pressure of System*Final Volume of System)/((Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume)-1)
W = (Pi*Vi-Pf*Vf)/((Cp molar/Cv molar)-1)
This formula uses 7 Variables
Variables Used
Work done in Thermodynamic Process - (Measured in Joule) - Work done in Thermodynamic Process is done when a force that is applied to an object moves that object.
Initial Pressure of System - (Measured in Pascal) - Initial Pressure of System is the total initial pressure exerted by the molecules inside the system.
Initial Volume of System - (Measured in Cubic Meter) - Initial Volume of System is the volume occupied by the molecules of the sytem initially before the process has started.
Final Pressure of System - (Measured in Pascal) - Final Pressure of System is the total final pressure exerted by the molecules inside the system.
Final Volume of System - (Measured in Cubic Meter) - Final Volume of System is the volume occupied by the molecules of the system when thermodynamic process has taken place.
Molar Specific Heat Capacity at Constant Pressure - (Measured in Joule Per Kelvin Per Mole) - Molar Specific Heat Capacity at Constant Pressure, (of a gas) is the amount of heat required to raise the temperature of 1 mol of the gas by 1 °C at the constant pressure.
Molar Specific Heat Capacity at Constant Volume - (Measured in Joule Per Kelvin Per Mole) - Molar Specific Heat Capacity at Constant Volume, (of a gas) is the amount of heat required to raise the temperature of 1 mol of the gas by 1 °C at the constant volume.
STEP 1: Convert Input(s) to Base Unit
Initial Pressure of System: 65 Pascal --> 65 Pascal No Conversion Required
Initial Volume of System: 11 Cubic Meter --> 11 Cubic Meter No Conversion Required
Final Pressure of System: 18.43 Pascal --> 18.43 Pascal No Conversion Required
Final Volume of System: 13 Cubic Meter --> 13 Cubic Meter No Conversion Required
Molar Specific Heat Capacity at Constant Pressure: 122 Joule Per Kelvin Per Mole --> 122 Joule Per Kelvin Per Mole No Conversion Required
Molar Specific Heat Capacity at Constant Volume: 103 Joule Per Kelvin Per Mole --> 103 Joule Per Kelvin Per Mole No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
W = (Pi*Vi-Pf*Vf)/((Cp molar/Cv molar)-1) --> (65*11-18.43*13)/((122/103)-1)
Evaluating ... ...
W = 2577.22263157895
STEP 3: Convert Result to Output's Unit
2577.22263157895 Joule --> No Conversion Required
FINAL ANSWER
2577.22263157895 2577.223 Joule <-- Work done in Thermodynamic Process
(Calculation completed in 00.004 seconds)

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Ideal Gas Calculators

Heat Transfer in Isochoric Process
​ Go Heat Transferred in Thermodynamic Process = Number of Moles of Ideal Gas*Molar Specific Heat Capacity at Constant Volume*Temperature Difference
Change in Internal Energy of System
​ Go Change in Internal Energy = Number of Moles of Ideal Gas*Molar Specific Heat Capacity at Constant Volume*Temperature Difference
Enthalpy of System
​ Go System Enthalpy = Number of Moles of Ideal Gas*Molar Specific Heat Capacity at Constant Pressure*Temperature Difference
Specific Heat Capacity at Constant Pressure
​ Go Molar Specific Heat Capacity at Constant Pressure = [R]+Specific Molar Heat Capacity at Constant Volume

Basic Formulas of Thermodynamics Calculators

Total Number of Variables in System
​ LaTeX ​ Go Total Number of Variables in System = Number of Phases*(Number of Components in System-1)+2
Number of Components
​ LaTeX ​ Go Number of Components in System = Degree of Freedom+Number of Phases-2
Degree of Freedom
​ LaTeX ​ Go Degree of Freedom = Number of Components in System-Number of Phases+2
Number of Phases
​ LaTeX ​ Go Number of Phases = Number of Components in System-Degree of Freedom+2

Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume Formula

​Go
Work done in Thermodynamic Process = (Initial Pressure of System*Initial Volume of System-Final Pressure of System*Final Volume of System)/((Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume)-1)
W = (Pi*Vi-Pf*Vf)/((Cp molar/Cv molar)-1)

What is an Adiabatic Process?

In thermodynamics, an adiabatic process is a type of thermodynamic process which occurs without transferring heat or mass between the system and its surroundings. Unlike an isothermal process, an adiabatic process transfers energy to the surroundings only as work.

How to Calculate Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume?

Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume calculator uses Work done in Thermodynamic Process = (Initial Pressure of System*Initial Volume of System-Final Pressure of System*Final Volume of System)/((Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume)-1) to calculate the Work done in Thermodynamic Process, Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume computes the work required to take an ideal gas system from initial state to final state without any heat transfer. Work done in Thermodynamic Process is denoted by W symbol.

How to calculate Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume using this online calculator? To use this online calculator for Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume, enter Initial Pressure of System (Pi), Initial Volume of System (Vi), Final Pressure of System (Pf), Final Volume of System (Vf), Molar Specific Heat Capacity at Constant Pressure (Cp molar) & Molar Specific Heat Capacity at Constant Volume (Cv molar) and hit the calculate button. Here is how the Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume calculation can be explained with given input values -> 2577.223 = (65*11-18.43*13)/((122/103)-1).

FAQ

What is Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume?
Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume computes the work required to take an ideal gas system from initial state to final state without any heat transfer and is represented as W = (Pi*Vi-Pf*Vf)/((Cp molar/Cv molar)-1) or Work done in Thermodynamic Process = (Initial Pressure of System*Initial Volume of System-Final Pressure of System*Final Volume of System)/((Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume)-1). Initial Pressure of System is the total initial pressure exerted by the molecules inside the system, Initial Volume of System is the volume occupied by the molecules of the sytem initially before the process has started, Final Pressure of System is the total final pressure exerted by the molecules inside the system, Final Volume of System is the volume occupied by the molecules of the system when thermodynamic process has taken place, Molar Specific Heat Capacity at Constant Pressure, (of a gas) is the amount of heat required to raise the temperature of 1 mol of the gas by 1 °C at the constant pressure & Molar Specific Heat Capacity at Constant Volume, (of a gas) is the amount of heat required to raise the temperature of 1 mol of the gas by 1 °C at the constant volume.
How to calculate Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume?
Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume computes the work required to take an ideal gas system from initial state to final state without any heat transfer is calculated using Work done in Thermodynamic Process = (Initial Pressure of System*Initial Volume of System-Final Pressure of System*Final Volume of System)/((Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume)-1). To calculate Work Done in Adiabatic Process using Specific Heat Capacity at Constant Pressure and Volume, you need Initial Pressure of System (Pi), Initial Volume of System (Vi), Final Pressure of System (Pf), Final Volume of System (Vf), Molar Specific Heat Capacity at Constant Pressure (Cp molar) & Molar Specific Heat Capacity at Constant Volume (Cv molar). With our tool, you need to enter the respective value for Initial Pressure of System, Initial Volume of System, Final Pressure of System, Final Volume of System, Molar Specific Heat Capacity at Constant Pressure & Molar Specific Heat Capacity at Constant Volume and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Work done in Thermodynamic Process?
In this formula, Work done in Thermodynamic Process uses Initial Pressure of System, Initial Volume of System, Final Pressure of System, Final Volume of System, Molar Specific Heat Capacity at Constant Pressure & Molar Specific Heat Capacity at Constant Volume. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Work done in Thermodynamic Process = [R]*Temperature of Gas*ln(Initial Pressure of System/Final Pressure of System)
  • Work done in Thermodynamic Process = Number of Moles of Ideal Gas*[R]*Temperature of Gas*ln(Final Volume of System/Initial Volume of System)
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