What is a Snub Dodecahedron?
In geometry, the Snub Dodecahedron, or snub icosidodecahedron, is an Archimedean solid, one of thirteen convex isogonal non-prismatic solids constructed by two or more types of regular polygon faces. The Snub Dodecahedron has 92 faces (the most of the 13 Archimedean solids): 12 are pentagons and the other 80 are equilateral triangles. It also has 150 edges, and 60 vertices. Each vertex is identical in such a way that, 4 equilateral triangular faces and 1 pentagonal face are joining together at each vertex. It has two distinct forms, which are mirror images (or "enantiomorphs") of each other. The union of both forms is a compound of two Snub Dodecahedra, and the convex hull of both forms is a truncated icosidodecahedron.
How to Calculate Volume of Snub Dodecahedron given Total Surface Area?
Volume of Snub Dodecahedron given Total Surface Area calculator uses Volume of Snub Dodecahedron = (((12*((3*[phi])+1))*((([phi]/2+sqrt([phi]-5/27)/2)^(1/3)+([phi]/2-sqrt([phi]-5/27)/2)^(1/3))^2)-(((36*[phi])+7)*(([phi]/2+sqrt([phi]-5/27)/2)^(1/3)+([phi]/2-sqrt([phi]-5/27)/2)^(1/3))))-((53*[phi])+6))/(6*(3-(([phi]/2+sqrt([phi]-5/27)/2)^(1/3)+([phi]/2-sqrt([phi]-5/27)/2)^(1/3))^2)^(3/2))*(sqrt(Total Surface Area of Snub Dodecahedron/((20*sqrt(3))+(3*sqrt(25+(10*sqrt(5)))))))^3 to calculate the Volume of Snub Dodecahedron, Volume of Snub Dodecahedron given Total Surface Area formula is defined as the total quantity of three dimensional space enclosed by the surface of the Snub Dodecahedron, and calculated using the total surface area of the Snub Dodecahedron. Volume of Snub Dodecahedron is denoted by V symbol.
How to calculate Volume of Snub Dodecahedron given Total Surface Area using this online calculator? To use this online calculator for Volume of Snub Dodecahedron given Total Surface Area, enter Total Surface Area of Snub Dodecahedron (TSA) and hit the calculate button. Here is how the Volume of Snub Dodecahedron given Total Surface Area calculation can be explained with given input values -> 37324.38 = (((12*((3*[phi])+1))*((([phi]/2+sqrt([phi]-5/27)/2)^(1/3)+([phi]/2-sqrt([phi]-5/27)/2)^(1/3))^2)-(((36*[phi])+7)*(([phi]/2+sqrt([phi]-5/27)/2)^(1/3)+([phi]/2-sqrt([phi]-5/27)/2)^(1/3))))-((53*[phi])+6))/(6*(3-(([phi]/2+sqrt([phi]-5/27)/2)^(1/3)+([phi]/2-sqrt([phi]-5/27)/2)^(1/3))^2)^(3/2))*(sqrt(5500/((20*sqrt(3))+(3*sqrt(25+(10*sqrt(5)))))))^3.