Volume of Equilibrium Mixture of Substances A and B Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume at Equilibrium = (1+Degree of Dissociation*(Number of Moles Products at Equilibrium-1))*Volume of Solution
Veq = (1+𝝰*(y-1))*V
This formula uses 4 Variables
Variables Used
Volume at Equilibrium - (Measured in Cubic Meter) - Volume at Equilibrium is the volume of substances A and B at equilibrium stage during the chemical reaction.
Degree of Dissociation - The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.
Number of Moles Products at Equilibrium - Number of moles products at equilibrium is the total number of moles of products in a chemical reaction which are present during equilibrium.
Volume of Solution - (Measured in Cubic Meter) - The Volume of Solution gives the volume of the solution in liters.
STEP 1: Convert Input(s) to Base Unit
Degree of Dissociation: 0.35 --> No Conversion Required
Number of Moles Products at Equilibrium: 40 --> No Conversion Required
Volume of Solution: 450 Liter --> 0.45 Cubic Meter (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Veq = (1+𝝰*(y-1))*V --> (1+0.35*(40-1))*0.45
Evaluating ... ...
Veq = 6.5925
STEP 3: Convert Result to Output's Unit
6.5925 Cubic Meter -->6592.5 Liter (Check conversion ​here)
FINAL ANSWER
6592.5 Liter <-- Volume at Equilibrium
(Calculation completed in 00.004 seconds)

Credits

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Created by Akshada Kulkarni
National Institute of Information Technology (NIIT), Neemrana
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University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA
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Relation between Vapour Density and Degree of Dissociation Calculators

Initial Vapour Density
​ LaTeX ​ Go Initial Vapour Density = (Total Moles at Equilibrium*Equilibrium Vapour Density)/Initial Number of Moles
Molecular Weight of Substance given Initial Vapour Density
​ LaTeX ​ Go Molecular Weight = Initial Vapour Density*Volume of Solution
Volume of Solution given Initial Vapour Density
​ LaTeX ​ Go Volume of Solution = Molecular Weight/Initial Vapour Density
Initial Vapour Density given Molecular Weight
​ LaTeX ​ Go Initial Vapour Density = Molecular Weight/Volume of Solution

Volume of Equilibrium Mixture of Substances A and B Formula

​LaTeX ​Go
Volume at Equilibrium = (1+Degree of Dissociation*(Number of Moles Products at Equilibrium-1))*Volume of Solution
Veq = (1+𝝰*(y-1))*V

What is a mole?

A mole is defined as the mass of the substance which consists of the equal quantity of basic units. A mole fraction indicates the number of chemical elements. A mole is defined as 6.02214076 × 10^23 of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

How to Calculate Volume of Equilibrium Mixture of Substances A and B?

Volume of Equilibrium Mixture of Substances A and B calculator uses Volume at Equilibrium = (1+Degree of Dissociation*(Number of Moles Products at Equilibrium-1))*Volume of Solution to calculate the Volume at Equilibrium, The Volume of equilibrium mixture of substances A and B formula is defined as is the number of moles of substances A and B at equilibrium with the volume of the solution of the chemical reaction. Volume at Equilibrium is denoted by Veq symbol.

How to calculate Volume of Equilibrium Mixture of Substances A and B using this online calculator? To use this online calculator for Volume of Equilibrium Mixture of Substances A and B, enter Degree of Dissociation (𝝰), Number of Moles Products at Equilibrium (y) & Volume of Solution (V) and hit the calculate button. Here is how the Volume of Equilibrium Mixture of Substances A and B calculation can be explained with given input values -> 6.6E+6 = (1+0.35*(40-1))*0.45.

FAQ

What is Volume of Equilibrium Mixture of Substances A and B?
The Volume of equilibrium mixture of substances A and B formula is defined as is the number of moles of substances A and B at equilibrium with the volume of the solution of the chemical reaction and is represented as Veq = (1+𝝰*(y-1))*V or Volume at Equilibrium = (1+Degree of Dissociation*(Number of Moles Products at Equilibrium-1))*Volume of Solution. The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration, Number of moles products at equilibrium is the total number of moles of products in a chemical reaction which are present during equilibrium & The Volume of Solution gives the volume of the solution in liters.
How to calculate Volume of Equilibrium Mixture of Substances A and B?
The Volume of equilibrium mixture of substances A and B formula is defined as is the number of moles of substances A and B at equilibrium with the volume of the solution of the chemical reaction is calculated using Volume at Equilibrium = (1+Degree of Dissociation*(Number of Moles Products at Equilibrium-1))*Volume of Solution. To calculate Volume of Equilibrium Mixture of Substances A and B, you need Degree of Dissociation (𝝰), Number of Moles Products at Equilibrium (y) & Volume of Solution (V). With our tool, you need to enter the respective value for Degree of Dissociation, Number of Moles Products at Equilibrium & Volume of Solution and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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