Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed) Calculator

✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted [P]			+10% -10%
✖Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it.ⓘ Resistance Underground AC [R]			+10% -10%
✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%
✖Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.ⓘ Phase Difference [Φ]			+10% -10%

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed) [V]

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Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume Of Conductor = (8*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)
V = (8*(P^2)*R*A*L)/(P_loss*(V_m^2)*(cos(Φ))^2)
This formula uses 1 Functions, 8 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)

Variables Used

Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistance Underground AC - (Measured in Ohm) - Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

STEP 1: Convert Input(s) to Base Unit

Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistance Underground AC: 5 Ohm --> 5 Ohm No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V = (8*(P^2)*R*A*L)/(P_loss*(V_m^2)*(cos(Φ))^2) --> (8*(300^2)*5*1.28*24)/(2.67*(230^2)*(cos(0.5235987755982))^2)

Evaluating ... ...

V = 1043.98802064527

STEP 3: Convert Result to Output's Unit

1043.98802064527 Cubic Meter --> No Conversion Required

FINAL ANSWER

1043.98802064527 ≈ 1043.988 Cubic Meter <-- Volume Of Conductor

(Calculation completed in 00.004 seconds)

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< Wire Parameters Calculators

Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)

Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))

Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))

Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))

Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed) Formula

LaTeX Go

What is the volume of conductor material in 1-phase 2-wire Mid-point Earthed system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed)?

Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed) calculator uses Volume Of Conductor = (8*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2) to calculate the Volume Of Conductor, The Volume of Conductor Material using Resistance (1-phase 2-wire Mid-point Earthed) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire Mid-point Earthed underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed), enter Power Transmitted (P), Resistance Underground AC (R), Area of Underground AC Wire (A), Length of Underground AC Wire (L), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) and hit the calculate button. Here is how the Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 1043.988 = (8*(300^2)*5*1.28*24)/(2.67*(230^2)*(cos(0.5235987755982))^2).

FAQ

What is Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed)?

The Volume of Conductor Material using Resistance (1-phase 2-wire Mid-point Earthed) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire Mid-point Earthed underground system and is represented as V = (8*(P^2)*R*A*L)/(P_loss*(V_m^2)*(cos(Φ))^2) or Volume Of Conductor = (8*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Length of Underground AC Wire is the total length of the wire from one end to other end, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

How to calculate Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed)?

The Volume of Conductor Material using Resistance (1-phase 2-wire Mid-point Earthed) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire Mid-point Earthed underground system is calculated using Volume Of Conductor = (8*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2). To calculate Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed), you need Power Transmitted (P), Resistance Underground AC (R), Area of Underground AC Wire (A), Length of Underground AC Wire (L), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ). With our tool, you need to enter the respective value for Power Transmitted, Resistance Underground AC, Area of Underground AC Wire, Length of Underground AC Wire, Line Losses, Maximum Voltage Underground AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Volume Of Conductor?

In this formula, Volume Of Conductor uses Power Transmitted, Resistance Underground AC, Area of Underground AC Wire, Length of Underground AC Wire, Line Losses, Maximum Voltage Underground AC & Phase Difference. We can use 3 other way(s) to calculate the same, which is/are as follows -

Volume Of Conductor = 8*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2
Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)

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