Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS) Calculator

✖Current Overhead AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Overhead AC [I]			+10% -10%
✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Overhead AC Wire is the total length of the wire from one end to other end.ⓘ Length of Overhead AC Wire [L]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Overhead AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%

✖Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line.ⓘ Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS) [V]

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Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume of Conductor = (4*(Current Overhead AC^2)*Resistivity*(Length of Overhead AC Wire^2))/(Line Losses)
V = (4*(I^2)*ρ*(L^2))/(P_loss)
This formula uses 5 Variables

Variables Used

Volume of Conductor - (Measured in Cubic Meter) - Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line.
Current Overhead AC - (Measured in Ampere) - Current Overhead AC is defined as the current flowing through the overhead ac supply wire.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Overhead AC Wire - (Measured in Meter) - Length of Overhead AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Overhead AC line when in use.

STEP 1: Convert Input(s) to Base Unit

Current Overhead AC: 6.9 Ampere --> 6.9 Ampere No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Overhead AC Wire: 10.63 Meter --> 10.63 Meter No Conversion Required
Line Losses: 8.23 Watt --> 8.23 Watt No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V = (4*(I^2)*ρ*(L^2))/(P_loss) --> (4*(6.9^2)*1.7E-05*(10.63^2))/(8.23)

Evaluating ... ...

V = 0.0444502070245444

STEP 3: Convert Result to Output's Unit

0.0444502070245444 Cubic Meter --> No Conversion Required

FINAL ANSWER

0.0444502070245444 ≈ 0.04445 Cubic Meter <-- Volume of Conductor

(Calculation completed in 00.004 seconds)

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< Wire Parameters Calculators

Length of Wire using Area of X-Section(Single Phase Two Wire Mid-Point Earthed OS)

LaTeX Go Length of Overhead AC Wire = (Area of Overhead AC Wire*Maximum Voltage Overhead AC^2*Line Losses*cos(Phase Difference)^2)/(Resistivity*Power Transmitted^2)

Line Losses using Area of X-Section(Single Phase Two Wire Mid-Point Earthed OS)

LaTeX Go Line Losses = (Length of Overhead AC Wire*Resistivity*Power Transmitted^2)/(Area of Overhead AC Wire*Maximum Voltage Overhead AC^2*cos(Phase Difference)^2)

Area of X-Section(Single Phase Two Wire Mid-Point Earthed)

LaTeX Go Area of Overhead AC Wire = (Power Transmitted^2*Resistivity*Length of Overhead AC Wire)/(((cos(Phase Difference))^2)*Line Losses*Voltage Overhead AC^2)

Constant (Single Phase Two Wire Mid-Point Earthed)

LaTeX Go Constant Overhead AC = (4*Power Transmitted^2*Resistivity*Length of Overhead AC Wire)/(Line Losses*Voltage Overhead AC^2)

Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS) Formula

LaTeX Go

Volume of Conductor = (4*(Current Overhead AC^2)*Resistivity*(Length of Overhead AC Wire^2))/(Line Losses)
V = (4*(I^2)*ρ*(L^2))/(P_loss)

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 1/2cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is 2v_m so that r.m.s. value of voltage between them is √2v_m.

How to Calculate Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS)?

Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS) calculator uses Volume of Conductor = (4*(Current Overhead AC^2)*Resistivity*(Length of Overhead AC Wire^2))/(Line Losses) to calculate the Volume of Conductor, The Volume of Conductor Material using Load Current (single Phase two Wire Mid-Point OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire mid-point earthed overhead system. Volume of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS) using this online calculator? To use this online calculator for Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS), enter Current Overhead AC (I), Resistivity (ρ), Length of Overhead AC Wire (L) & Line Losses (P_loss) and hit the calculate button. Here is how the Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS) calculation can be explained with given input values -> 0.04445 = (4*(6.9^2)*1.7E-05*(10.63^2))/(8.23).

FAQ

What is Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS)?

The Volume of Conductor Material using Load Current (single Phase two Wire Mid-Point OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire mid-point earthed overhead system and is represented as V = (4*(I^2)*ρ*(L^2))/(P_loss) or Volume of Conductor = (4*(Current Overhead AC^2)*Resistivity*(Length of Overhead AC Wire^2))/(Line Losses). Current Overhead AC is defined as the current flowing through the overhead ac supply wire, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Overhead AC Wire is the total length of the wire from one end to other end & Line Losses is defined as the total losses occurring in an Overhead AC line when in use.

How to calculate Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS)?

The Volume of Conductor Material using Load Current (single Phase two Wire Mid-Point OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire mid-point earthed overhead system is calculated using Volume of Conductor = (4*(Current Overhead AC^2)*Resistivity*(Length of Overhead AC Wire^2))/(Line Losses). To calculate Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS), you need Current Overhead AC (I), Resistivity (ρ), Length of Overhead AC Wire (L) & Line Losses (P_loss). With our tool, you need to enter the respective value for Current Overhead AC, Resistivity, Length of Overhead AC Wire & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Volume of Conductor?

In this formula, Volume of Conductor uses Current Overhead AC, Resistivity, Length of Overhead AC Wire & Line Losses. We can use 1 other way(s) to calculate the same, which is/are as follows -

Volume of Conductor = (2*Resistivity*Power Transmitted^2*Length of Overhead AC Wire^2)/(Line Losses*Maximum Voltage Overhead AC*cos(Phase Difference)^2)

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