Volume of Conductor Material using Load Current (2 Phase 4 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = (Current Underground AC*Length of Underground AC Wire)^2*4*Resistivity/Line Losses
V = (I*L)^2*4*ρ/Ploss
This formula uses 5 Variables
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
STEP 1: Convert Input(s) to Base Unit
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = (I*L)^2*4*ρ/Ploss --> (9*24)^2*4*1.7E-05/2.67
Evaluating ... ...
V = 1.18824269662921
STEP 3: Convert Result to Output's Unit
1.18824269662921 Cubic Meter --> No Conversion Required
FINAL ANSWER
1.18824269662921 1.188243 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.004 seconds)

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Wire Parameters Calculators

Length using Area of X-Section (2 Phase 4 Wire US)
​ LaTeX ​ Go Length of Underground AC Wire = (Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)/(4*Resistivity*(Power Transmitted^2))
Line Losses using Area of X-Section (2 Phase 4 Wire US)
​ LaTeX ​ Go Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Length using Line Losses (2 Phase 4 Wire US)
​ LaTeX ​ Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*(Current Underground AC^2)*Resistivity)
Line Losses (2 Phase 4 Wire US)
​ LaTeX ​ Go Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC

Volume of Conductor Material using Load Current (2 Phase 4 Wire US) Formula

​LaTeX ​Go
Volume Of Conductor = (Current Underground AC*Length of Underground AC Wire)^2*4*Resistivity/Line Losses
V = (I*L)^2*4*ρ/Ploss

What is the volume of conductor material in 2-phase 4-wire underground system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Load Current (2 Phase 4 Wire US)?

Volume of Conductor Material using Load Current (2 Phase 4 Wire US) calculator uses Volume Of Conductor = (Current Underground AC*Length of Underground AC Wire)^2*4*Resistivity/Line Losses to calculate the Volume Of Conductor, The Volume of Conductor Material using Load Current (2 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Load Current (2 Phase 4 Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Load Current (2 Phase 4 Wire US), enter Current Underground AC (I), Length of Underground AC Wire (L), Resistivity (ρ) & Line Losses (Ploss) and hit the calculate button. Here is how the Volume of Conductor Material using Load Current (2 Phase 4 Wire US) calculation can be explained with given input values -> 1.188243 = (9*24)^2*4*1.7E-05/2.67.

FAQ

What is Volume of Conductor Material using Load Current (2 Phase 4 Wire US)?
The Volume of Conductor Material using Load Current (2 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire system and is represented as V = (I*L)^2*4*ρ/Ploss or Volume Of Conductor = (Current Underground AC*Length of Underground AC Wire)^2*4*Resistivity/Line Losses. Current Underground AC is defined as the current flowing through the overhead ac supply wire, Length of Underground AC Wire is the total length of the wire from one end to other end, Resistivity is the measure of how strongly a material opposes the flow of current through them & Line Losses is defined as the total losses occurring in an Underground AC line when in use.
How to calculate Volume of Conductor Material using Load Current (2 Phase 4 Wire US)?
The Volume of Conductor Material using Load Current (2 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire system is calculated using Volume Of Conductor = (Current Underground AC*Length of Underground AC Wire)^2*4*Resistivity/Line Losses. To calculate Volume of Conductor Material using Load Current (2 Phase 4 Wire US), you need Current Underground AC (I), Length of Underground AC Wire (L), Resistivity (ρ) & Line Losses (Ploss). With our tool, you need to enter the respective value for Current Underground AC, Length of Underground AC Wire, Resistivity & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Current Underground AC, Length of Underground AC Wire, Resistivity & Line Losses. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = 2*Area of Underground AC Wire*Length of Underground AC Wire
  • Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
  • Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)
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