Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume of Conductor = 16*Resistivity*(Current Overhead AC*Length of Overhead AC Wire)^2/(Line Losses)
V = 16*ρ*(I*L)^2/(Ploss)
This formula uses 5 Variables
Variables Used
Volume of Conductor - (Measured in Cubic Meter) - Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Current Overhead AC - (Measured in Ampere) - Current Overhead AC is defined as the current flowing through the overhead ac supply wire.
Length of Overhead AC Wire - (Measured in Meter) - Length of Overhead AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Overhead AC line when in use.
STEP 1: Convert Input(s) to Base Unit
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Current Overhead AC: 6.9 Ampere --> 6.9 Ampere No Conversion Required
Length of Overhead AC Wire: 10.63 Meter --> 10.63 Meter No Conversion Required
Line Losses: 8.23 Watt --> 8.23 Watt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = 16*ρ*(I*L)^2/(Ploss) --> 16*1.7E-05*(6.9*10.63)^2/(8.23)
Evaluating ... ...
V = 0.177800828098177
STEP 3: Convert Result to Output's Unit
0.177800828098177 Cubic Meter --> No Conversion Required
FINAL ANSWER
0.177800828098177 0.177801 Cubic Meter <-- Volume of Conductor
(Calculation completed in 00.004 seconds)

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Wire Parameters Calculators

Area of X-Section(2-Phase 4-Wire OS)
​ LaTeX ​ Go Area of Overhead AC Wire = (Power Transmitted^2)*Resistivity*Length of Overhead AC Wire/(((cos(Phase Difference))^2)*Line Losses*(Maximum Voltage Overhead AC^2)*2)
Constant(2-Phase 4-Wire OS)
​ LaTeX ​ Go Constant Overhead AC = (4*(Power Transmitted^2)*Resistivity*Length of Overhead AC Wire)/(Line Losses*(Voltage Overhead AC^2))
Volume of Conductor Material(2-Phase 4-Wire OS)
​ LaTeX ​ Go Volume of Conductor = (4)*Area of Overhead AC Wire*Length of Overhead AC Wire
Line Losses(2-Phase 4-Wire OS)
​ LaTeX ​ Go Line Losses = (4)*((Current Overhead AC)^2)*Resistance Overhead AC

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Formula

​LaTeX ​Go
Volume of Conductor = 16*Resistivity*(Current Overhead AC*Length of Overhead AC Wire)^2/(Line Losses)
V = 16*ρ*(I*L)^2/(Ploss)

What is the value of maximum voltage and volume of conductor material in 2-phase 4-wire system?

The volume of conductor material required in this system is 1/2cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is 2vm so that r.m.s. value of voltage between them is √2/vm.

How to Calculate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) calculator uses Volume of Conductor = 16*Resistivity*(Current Overhead AC*Length of Overhead AC Wire)^2/(Line Losses) to calculate the Volume of Conductor, The Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire overhead system. Volume of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) using this online calculator? To use this online calculator for Volume of Conductor Material using Load Current (2-Phase 4-Wire OS), enter Resistivity (ρ), Current Overhead AC (I), Length of Overhead AC Wire (L) & Line Losses (Ploss) and hit the calculate button. Here is how the Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) calculation can be explained with given input values -> 0.177801 = 16*1.7E-05*(6.9*10.63)^2/(8.23).

FAQ

What is Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?
The Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire overhead system and is represented as V = 16*ρ*(I*L)^2/(Ploss) or Volume of Conductor = 16*Resistivity*(Current Overhead AC*Length of Overhead AC Wire)^2/(Line Losses). Resistivity is the measure of how strongly a material opposes the flow of current through them, Current Overhead AC is defined as the current flowing through the overhead ac supply wire, Length of Overhead AC Wire is the total length of the wire from one end to other end & Line Losses is defined as the total losses occurring in an Overhead AC line when in use.
How to calculate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?
The Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire overhead system is calculated using Volume of Conductor = 16*Resistivity*(Current Overhead AC*Length of Overhead AC Wire)^2/(Line Losses). To calculate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS), you need Resistivity (ρ), Current Overhead AC (I), Length of Overhead AC Wire (L) & Line Losses (Ploss). With our tool, you need to enter the respective value for Resistivity, Current Overhead AC, Length of Overhead AC Wire & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume of Conductor?
In this formula, Volume of Conductor uses Resistivity, Current Overhead AC, Length of Overhead AC Wire & Line Losses. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Volume of Conductor = (4)*Area of Overhead AC Wire*Length of Overhead AC Wire
  • Volume of Conductor = (4)*Area of Overhead AC Wire*Length of Overhead AC Wire
  • Volume of Conductor = 2*Resistivity*(Power Transmitted*Length of Overhead AC Wire)^2/(Line Losses*(Maximum Voltage Overhead AC*cos(Phase Difference))^2)
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