Volume of Conductor Material using Load Current (2 Phase 3 Wire US) Calculator

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Current Underground AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Underground AC [I]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume of Conductor Material using Load Current (2 Phase 3 Wire US) [V]

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Volume of Conductor Material using Load Current (2 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
V = (2+sqrt(2))^2*ρ*(L^2)*(I^2)/P_loss
This formula uses 1 Functions, 5 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.

STEP 1: Convert Input(s) to Base Unit

Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V = (2+sqrt(2))^2*ρ*(L^2)*(I^2)/P_loss --> (2+sqrt(2))^2*1.7E-05*(24^2)*(9^2)/2.67

Evaluating ... ...

V = 3.46279298190763

STEP 3: Convert Result to Output's Unit

3.46279298190763 Cubic Meter --> No Conversion Required

FINAL ANSWER

3.46279298190763 ≈ 3.462793 Cubic Meter <-- Volume Of Conductor

(Calculation completed in 00.004 seconds)

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< Wire Parameters Calculators

Length using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/(Resistivity*((2+sqrt(2))*Power Transmitted^2)))

Line Losses using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)

Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)

Constant using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Constant Underground AC = Volume Of Conductor*((cos(Phase Difference))^2)/(2.914)

Volume of Conductor Material using Load Current (2 Phase 3 Wire US) Formula

LaTeX Go

Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
V = (2+sqrt(2))^2*ρ*(L^2)*(I^2)/P_loss

What is the volume of conductor material in 2-phase 3-wire underground system?

The volume of conductor material required in this system is 2.914/cos²θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Load Current (2 Phase 3 Wire US)?

Volume of Conductor Material using Load Current (2 Phase 3 Wire US) calculator uses Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses to calculate the Volume Of Conductor, The Volume of Conductor Material using Load Current (2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Load Current (2 Phase 3 Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Load Current (2 Phase 3 Wire US), enter Resistivity (ρ), Length of Underground AC Wire (L), Current Underground AC (I) & Line Losses (P_loss) and hit the calculate button. Here is how the Volume of Conductor Material using Load Current (2 Phase 3 Wire US) calculation can be explained with given input values -> 3.462793 = (2+sqrt(2))^2*1.7E-05*(24^2)*(9^2)/2.67.

FAQ

What is Volume of Conductor Material using Load Current (2 Phase 3 Wire US)?

The Volume of Conductor Material using Load Current (2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system and is represented as V = (2+sqrt(2))^2*ρ*(L^2)*(I^2)/P_loss or Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses. Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Current Underground AC is defined as the current flowing through the overhead ac supply wire & Line Losses is defined as the total losses occurring in an Underground AC line when in use.

How to calculate Volume of Conductor Material using Load Current (2 Phase 3 Wire US)?

The Volume of Conductor Material using Load Current (2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system is calculated using Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses. To calculate Volume of Conductor Material using Load Current (2 Phase 3 Wire US), you need Resistivity (ρ), Length of Underground AC Wire (L), Current Underground AC (I) & Line Losses (P_loss). With our tool, you need to enter the respective value for Resistivity, Length of Underground AC Wire, Current Underground AC & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Volume Of Conductor?

In this formula, Volume Of Conductor uses Resistivity, Length of Underground AC Wire, Current Underground AC & Line Losses. We can use 3 other way(s) to calculate the same, which is/are as follows -

Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire)
Volume Of Conductor = 2.194*Constant Underground AC/(cos(Phase Difference)^2)
Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)

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