Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed) Calculator

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Current Underground AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Underground AC [I]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed) [V]

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Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
V = 16*ρ*(L^2)*(I^2)/P_loss
This formula uses 5 Variables

Variables Used

Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.

STEP 1: Convert Input(s) to Base Unit

Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V = 16*ρ*(L^2)*(I^2)/P_loss --> 16*1.7E-05*(24^2)*(9^2)/2.67

Evaluating ... ...

V = 4.75297078651685

STEP 3: Convert Result to Output's Unit

4.75297078651685 Cubic Meter --> No Conversion Required

FINAL ANSWER

4.75297078651685 ≈ 4.752971 Cubic Meter <-- Volume Of Conductor

(Calculation completed in 00.004 seconds)

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< Wire Parameters Calculators

Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)

Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))

Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))

Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))

Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed) Formula

LaTeX Go

Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
V = 16*ρ*(L^2)*(I^2)/P_loss

What is the volume of conductor material in 1-phase 2-wire Mid-point Earthed system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed) calculator uses Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses to calculate the Volume Of Conductor, The Volume of Conductor Material using Load Current (1-phase 2-wire Mid-point Earthed) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire Mid-point Earthed underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed), enter Resistivity (ρ), Length of Underground AC Wire (L), Current Underground AC (I) & Line Losses (P_loss) and hit the calculate button. Here is how the Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 4.752971 = 16*1.7E-05*(24^2)*(9^2)/2.67.

FAQ

What is Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

The Volume of Conductor Material using Load Current (1-phase 2-wire Mid-point Earthed) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire Mid-point Earthed underground system and is represented as V = 16*ρ*(L^2)*(I^2)/P_loss or Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses. Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Current Underground AC is defined as the current flowing through the overhead ac supply wire & Line Losses is defined as the total losses occurring in an Underground AC line when in use.

How to calculate Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

The Volume of Conductor Material using Load Current (1-phase 2-wire Mid-point Earthed) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire Mid-point Earthed underground system is calculated using Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses. To calculate Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed), you need Resistivity (ρ), Length of Underground AC Wire (L), Current Underground AC (I) & Line Losses (P_loss). With our tool, you need to enter the respective value for Resistivity, Length of Underground AC Wire, Current Underground AC & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Volume Of Conductor?

In this formula, Volume Of Conductor uses Resistivity, Length of Underground AC Wire, Current Underground AC & Line Losses. We can use 3 other way(s) to calculate the same, which is/are as follows -

Volume Of Conductor = 8*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2
Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)

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