Volume of Conductor Material using Area and Length(2 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire)
V = (2*A*L)+(sqrt(2)*A*L)
This formula uses 1 Functions, 3 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
STEP 1: Convert Input(s) to Base Unit
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = (2*A*L)+(sqrt(2)*A*L) --> (2*1.28*24)+(sqrt(2)*1.28*24)
Evaluating ... ...
V = 104.884640636101
STEP 3: Convert Result to Output's Unit
104.884640636101 Cubic Meter --> No Conversion Required
FINAL ANSWER
104.884640636101 104.8846 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.013 seconds)

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Wire Parameters Calculators

Length using Volume of Conductor Material (2 Phase 3 Wire US)
​ LaTeX ​ Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/(Resistivity*((2+sqrt(2))*Power Transmitted^2)))
Line Losses using Volume of Conductor Material (2 Phase 3 Wire US)
​ LaTeX ​ Go Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)
Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)
​ LaTeX ​ Go Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)
Constant using Volume of Conductor Material (2 Phase 3 Wire US)
​ LaTeX ​ Go Constant Underground AC = Volume Of Conductor*((cos(Phase Difference))^2)/(2.914)

Volume of Conductor Material using Area and Length(2 Phase 3 Wire US) Formula

​LaTeX ​Go
Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire)
V = (2*A*L)+(sqrt(2)*A*L)

What is the volume of conductor material in 2-phase 3-wire underground system?

The volume of conductor material required in this system is 2.914/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Area and Length(2 Phase 3 Wire US)?

Volume of Conductor Material using Area and Length(2 Phase 3 Wire US) calculator uses Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire) to calculate the Volume Of Conductor, The Volume of Conductor Material using Area and Length(2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Area and Length(2 Phase 3 Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Area and Length(2 Phase 3 Wire US), enter Area of Underground AC Wire (A) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Volume of Conductor Material using Area and Length(2 Phase 3 Wire US) calculation can be explained with given input values -> 104.8846 = (2*1.28*24)+(sqrt(2)*1.28*24).

FAQ

What is Volume of Conductor Material using Area and Length(2 Phase 3 Wire US)?
The Volume of Conductor Material using Area and Length(2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system and is represented as V = (2*A*L)+(sqrt(2)*A*L) or Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire). Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system & Length of Underground AC Wire is the total length of the wire from one end to other end.
How to calculate Volume of Conductor Material using Area and Length(2 Phase 3 Wire US)?
The Volume of Conductor Material using Area and Length(2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system is calculated using Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire). To calculate Volume of Conductor Material using Area and Length(2 Phase 3 Wire US), you need Area of Underground AC Wire (A) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Area of Underground AC Wire & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Area of Underground AC Wire & Length of Underground AC Wire. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = 2.194*Constant Underground AC/(cos(Phase Difference)^2)
  • Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
  • Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)
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