Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US) Calculator

✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US) [V]

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Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2
V = A*L*2
This formula uses 3 Variables

Variables Used

Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V = A*L*2 --> 1.28*24*2

Evaluating ... ...

V = 61.44

STEP 3: Convert Result to Output's Unit

61.44 Cubic Meter --> No Conversion Required

FINAL ANSWER

61.44 Cubic Meter <-- Volume Of Conductor

(Calculation completed in 00.004 seconds)

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< Wire Parameters Calculators

Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)

Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))

Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))

Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))

Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US) Formula

LaTeX Go

Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2
V = A*L*2

What is the volume of conductor material in 1-phase 2-wire mid-point earthed system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US)?

Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US) calculator uses Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2 to calculate the Volume Of Conductor, The Volume of Conductor Material using Area and Length(1-phase 2-wire Mid-point US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire mid-point earthed system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US) using this online calculator? To use this online calculator for Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US), enter Area of Underground AC Wire (A) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US) calculation can be explained with given input values -> 61.44 = 1.28*24*2.

FAQ

What is Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US)?

The Volume of Conductor Material using Area and Length(1-phase 2-wire Mid-point US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire mid-point earthed system and is represented as V = A*L*2 or Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2. Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system & Length of Underground AC Wire is the total length of the wire from one end to other end.

How to calculate Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US)?

The Volume of Conductor Material using Area and Length(1-phase 2-wire Mid-point US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 1-phase 2-wire mid-point earthed system is calculated using Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2. To calculate Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US), you need Area of Underground AC Wire (A) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Area of Underground AC Wire & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Volume Of Conductor?

In this formula, Volume Of Conductor uses Area of Underground AC Wire & Length of Underground AC Wire. We can use 3 other way(s) to calculate the same, which is/are as follows -

Volume Of Conductor = 8*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)
Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses

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