Volume of Conductor Material Main(2 Phase 4 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
V = 8*(P^2)*ρ*(L^2)/(Ploss*(Vm^2)*(cos(Φ)^2))
This formula uses 1 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = 8*(P^2)*ρ*(L^2)/(Ploss*(Vm^2)*(cos(Φ)^2)) --> 8*(300^2)*1.7E-05*(24^2)/(2.67*(230^2)*(cos(0.5235987755982)^2))
Evaluating ... ...
V = 0.066554236316136
STEP 3: Convert Result to Output's Unit
0.066554236316136 Cubic Meter --> No Conversion Required
FINAL ANSWER
0.066554236316136 0.066554 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.004 seconds)

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Wire Parameters Calculators

Length using Area of X-Section (2 Phase 4 Wire US)
​ LaTeX ​ Go Length of Underground AC Wire = (Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)/(4*Resistivity*(Power Transmitted^2))
Line Losses using Area of X-Section (2 Phase 4 Wire US)
​ LaTeX ​ Go Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Length using Line Losses (2 Phase 4 Wire US)
​ LaTeX ​ Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*(Current Underground AC^2)*Resistivity)
Line Losses (2 Phase 4 Wire US)
​ LaTeX ​ Go Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC

Volume of Conductor Material Main(2 Phase 4 Wire US) Formula

​LaTeX ​Go
Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
V = 8*(P^2)*ρ*(L^2)/(Ploss*(Vm^2)*(cos(Φ)^2))

What is the volume of conductor material in 2-phase 4-wire underground system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material Main(2 Phase 4 Wire US)?

Volume of Conductor Material Main(2 Phase 4 Wire US) calculator uses Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)) to calculate the Volume Of Conductor, The Volume of Conductor Material Main(2 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 4-wire underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material Main(2 Phase 4 Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material Main(2 Phase 4 Wire US), enter Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Line Losses (Ploss), Maximum Voltage Underground AC (Vm) & Phase Difference (Φ) and hit the calculate button. Here is how the Volume of Conductor Material Main(2 Phase 4 Wire US) calculation can be explained with given input values -> 0.066554 = 8*(300^2)*1.7E-05*(24^2)/(2.67*(230^2)*(cos(0.5235987755982)^2)).

FAQ

What is Volume of Conductor Material Main(2 Phase 4 Wire US)?
The Volume of Conductor Material Main(2 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 4-wire underground system and is represented as V = 8*(P^2)*ρ*(L^2)/(Ploss*(Vm^2)*(cos(Φ)^2)) or Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
How to calculate Volume of Conductor Material Main(2 Phase 4 Wire US)?
The Volume of Conductor Material Main(2 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 4-wire underground system is calculated using Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). To calculate Volume of Conductor Material Main(2 Phase 4 Wire US), you need Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Line Losses (Ploss), Maximum Voltage Underground AC (Vm) & Phase Difference (Φ). With our tool, you need to enter the respective value for Power Transmitted, Resistivity, Length of Underground AC Wire, Line Losses, Maximum Voltage Underground AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Power Transmitted, Resistivity, Length of Underground AC Wire, Line Losses, Maximum Voltage Underground AC & Phase Difference. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = 2*Area of Underground AC Wire*Length of Underground AC Wire
  • Volume Of Conductor = (Current Underground AC*Length of Underground AC Wire)^2*4*Resistivity/Line Losses
  • Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)
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