Volume of Conductor Material (DC Two-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = 4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
V = 4*(P^2)*ρ*(l^2)/(Pline*(Vm^2))
This formula uses 6 Variables
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Wire DC - (Measured in Meter) - Length of Wire DC is the measurement or extent of something from end to end.
Line Losses - (Measured in Watt) - Line Losses is defined as the losses that are produced in the line.
Maximum Voltage - (Measured in Volt) - Maximum Voltage the highest voltage rating for electrical devices.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Wire DC: 3.2 Meter --> 3.2 Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = 4*(P^2)*ρ*(l^2)/(Pline*(Vm^2)) --> 4*(300^2)*1.7E-05*(3.2^2)/(0.6*(60^2))
Evaluating ... ...
V = 0.0290133333333333
STEP 3: Convert Result to Output's Unit
0.0290133333333333 Cubic Meter --> No Conversion Required
FINAL ANSWER
0.0290133333333333 0.029013 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.004 seconds)

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Wire Parameters Calculators

Volume of Conductor Material using Resistance (DC Two-Wire US)
​ LaTeX ​ Go Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2))
Volume of Conductor Material (DC Two-Wire US)
​ LaTeX ​ Go Volume Of Conductor = 4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
Volume of Conductor Material using Load Current (DC Two-Wire US)
​ LaTeX ​ Go Volume Of Conductor = 4*Resistivity*(Length of Wire DC^2)*(Current underground DC^2)/Line Losses
Volume of Conductor Material using Area and Length(DC Two-Wire US)
​ LaTeX ​ Go Volume Of Conductor = Area of underground dc wire*Length of Wire DC*2

Volume of Conductor Material (DC Two-Wire US) Formula

​LaTeX ​Go
Volume Of Conductor = 4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
V = 4*(P^2)*ρ*(l^2)/(Pline*(Vm^2))

What is the volume of conductor material in DC Two-Wire underground system?

The volume of conductor material required in this system is 1 times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material (DC Two-Wire US)?

Volume of Conductor Material (DC Two-Wire US) calculator uses Volume Of Conductor = 4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2)) to calculate the Volume Of Conductor, The Volume of Conductor Material (DC Two-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC Two-Wire underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material (DC Two-Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material (DC Two-Wire US), enter Power Transmitted (P), Resistivity (ρ), Length of Wire DC (l), Line Losses (Pline) & Maximum Voltage (Vm) and hit the calculate button. Here is how the Volume of Conductor Material (DC Two-Wire US) calculation can be explained with given input values -> 0.029013 = 4*(300^2)*1.7E-05*(3.2^2)/(0.6*(60^2)).

FAQ

What is Volume of Conductor Material (DC Two-Wire US)?
The Volume of Conductor Material (DC Two-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC Two-Wire underground system and is represented as V = 4*(P^2)*ρ*(l^2)/(Pline*(Vm^2)) or Volume Of Conductor = 4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2)). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Wire DC is the measurement or extent of something from end to end, Line Losses is defined as the losses that are produced in the line & Maximum Voltage the highest voltage rating for electrical devices.
How to calculate Volume of Conductor Material (DC Two-Wire US)?
The Volume of Conductor Material (DC Two-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC Two-Wire underground system is calculated using Volume Of Conductor = 4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2)). To calculate Volume of Conductor Material (DC Two-Wire US), you need Power Transmitted (P), Resistivity (ρ), Length of Wire DC (l), Line Losses (Pline) & Maximum Voltage (Vm). With our tool, you need to enter the respective value for Power Transmitted, Resistivity, Length of Wire DC, Line Losses & Maximum Voltage and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Power Transmitted, Resistivity, Length of Wire DC, Line Losses & Maximum Voltage. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = Area of underground dc wire*Length of Wire DC*2
  • Volume Of Conductor = 4*Resistivity*(Length of Wire DC^2)*(Current underground DC^2)/Line Losses
  • Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2))
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