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Volume of Box having Gas Molecule given Pressure Calculator

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✖The Mass per Molecule is defined as the molar mass of the molecule divided by the Avogadro number.ⓘ Mass per Molecule [m]			+10% -10%
✖The Speed of Particle is the amount of distance travelled by the particle per unit time.ⓘ Speed of Particle [u]			+10% -10%
✖The pressure of Gas is the force that the gas exerts on the walls of its container.ⓘ Pressure of Gas [P_gas]			+10% -10%

✖Volume of Rectangular Box given P is the product of length, breadth, and height.ⓘ Volume of Box having Gas Molecule given Pressure [V_{box_P}]

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Volume of Box having Gas Molecule given Pressure Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas
V_{box_P} = (m*(u)^2)/P_gas
This formula uses 4 Variables

Variables Used

Volume of Rectangular Box given P - (Measured in Cubic Meter) - Volume of Rectangular Box given P is the product of length, breadth, and height.
Mass per Molecule - (Measured in Kilogram) - The Mass per Molecule is defined as the molar mass of the molecule divided by the Avogadro number.
Speed of Particle - (Measured in Meter per Second) - The Speed of Particle is the amount of distance travelled by the particle per unit time.
Pressure of Gas - (Measured in Pascal) - The pressure of Gas is the force that the gas exerts on the walls of its container.

STEP 1: Convert Input(s) to Base Unit

Mass per Molecule: 0.2 Gram --> 0.0002 Kilogram (Check conversion here)
Speed of Particle: 15 Meter per Second --> 15 Meter per Second No Conversion Required
Pressure of Gas: 0.215 Pascal --> 0.215 Pascal No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V_{box_P} = (m*(u)^2)/P_gas --> (0.0002*(15)^2)/0.215

Evaluating ... ...

V_{box_P} = 0.209302325581395

STEP 3: Convert Result to Output's Unit

0.209302325581395 Cubic Meter -->209.302325581395 Liter (Check conversion here)

FINAL ANSWER

209.302325581395 ≈ 209.3023 Liter <-- Volume of Rectangular Box given P

(Calculation completed in 00.004 seconds)

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Force by Gas Molecule on Wall of Box

LaTeX Go Force on a wall = (Mass per Molecule*(Speed of Particle)^2)/Length of Rectangular Section

Speed of Particle in 3D Box

LaTeX Go Speed of Particle given in 3D = (2*Length of Rectangular Section)/Time between Collision

Length of Rectangular Box given Time of Collision

LaTeX Go Length of Rectangular box given T = (Time between Collision*Speed of Particle)/2

Time between Collisions of Particle and Walls

LaTeX Go Time of Collision = (2*Length of Rectangular Section)/Speed of Particle

Volume of Box having Gas Molecule given Pressure Formula

LaTeX Go

Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas
V_{box_P} = (m*(u)^2)/P_gas

What are postulates of Kinetic molecular theory of gas?

1) Actual volume of gas molecules is negligible in comparison to the total volume of the gas.
2) no force of attraction between the gas molecules.
3) Particles of gas are in constant random motion.
4) Particles of gas collide with each other and with the walls of the container.
5)Collisions are perfectly elastic.
6) Different particles of the gas, have different speeds.
7) The average kinetic energy of the gas molecule is directly proportional to the absolute temperature.

How to Calculate Volume of Box having Gas Molecule given Pressure?

Volume of Box having Gas Molecule given Pressure calculator uses Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas to calculate the Volume of Rectangular Box given P, The volume of box having gas molecule given pressure formula is defined as product of the mass of particle and square of the speed of the particle per pressure of the gas in the box. Volume of Rectangular Box given P is denoted by V_{box_P} symbol.

How to calculate Volume of Box having Gas Molecule given Pressure using this online calculator? To use this online calculator for Volume of Box having Gas Molecule given Pressure, enter Mass per Molecule (m), Speed of Particle (u) & Pressure of Gas (P_gas) and hit the calculate button. Here is how the Volume of Box having Gas Molecule given Pressure calculation can be explained with given input values -> 209302.3 = (0.0002*(15)^2)/0.215.

FAQ

What is Volume of Box having Gas Molecule given Pressure?

The volume of box having gas molecule given pressure formula is defined as product of the mass of particle and square of the speed of the particle per pressure of the gas in the box and is represented as V_{box_P} = (m*(u)^2)/P_gas or Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas. The Mass per Molecule is defined as the molar mass of the molecule divided by the Avogadro number, The Speed of Particle is the amount of distance travelled by the particle per unit time & The pressure of Gas is the force that the gas exerts on the walls of its container.

How to calculate Volume of Box having Gas Molecule given Pressure?

The volume of box having gas molecule given pressure formula is defined as product of the mass of particle and square of the speed of the particle per pressure of the gas in the box is calculated using Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas. To calculate Volume of Box having Gas Molecule given Pressure, you need Mass per Molecule (m), Speed of Particle (u) & Pressure of Gas (P_gas). With our tool, you need to enter the respective value for Mass per Molecule, Speed of Particle & Pressure of Gas and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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