Volume of Atoms in FCC Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume of Atoms in Unit Cell = 16/3*pi*Atomic Radius^3
Va = 16/3*pi*r^3
This formula uses 1 Constants, 2 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Variables Used
Volume of Atoms in Unit Cell - (Measured in Cubic Meter) - Volume of Atoms in Unit Cell is the total volume of atoms present in the unit cell.
Atomic Radius - (Measured in Meter) - Atomic Radius is the radius of the atom which forms the metallic crystal.
STEP 1: Convert Input(s) to Base Unit
Atomic Radius: 1.35 Angstrom --> 1.35E-10 Meter (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Va = 16/3*pi*r^3 --> 16/3*pi*1.35E-10^3
Evaluating ... ...
Va = 4.12239788004053E-29
STEP 3: Convert Result to Output's Unit
4.12239788004053E-29 Cubic Meter -->41.2239788004053 Cubic Angstrom (Check conversion ​here)
FINAL ANSWER
41.2239788004053 41.22398 Cubic Angstrom <-- Volume of Atoms in Unit Cell
(Calculation completed in 00.004 seconds)

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Created by Sanjay Krishna
Amrita School of Engineering (ASE), Vallikavu
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K J Somaiya College of Engineering (K J Somaiya), Mumbai
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Face Centered Crystal Calculators

Volume of Atoms in FCC
​ LaTeX ​ Go Volume of Atoms in Unit Cell = 16/3*pi*Atomic Radius^3
Atomic Radius in FCC
​ LaTeX ​ Go Atomic Radius = Lattice Parameter of FCC/(2*sqrt(2))
Lattice Constant of FCC
​ LaTeX ​ Go Lattice Parameter of FCC = 2*sqrt(2)*Atomic Radius

Volume of Atoms in FCC Formula

​LaTeX ​Go
Volume of Atoms in Unit Cell = 16/3*pi*Atomic Radius^3
Va = 16/3*pi*r^3

Calculator for finding the volume of atoms in unit cell of FCC.

This volume can be calculated using the formula of volume of a sphere that is: (4/3)*pi*r^3 and 4 atoms are multiplied to it , where r is the radius of one atom. The volume is mainly used for studying the atomic packing factor of the FCC structure and the atomic radius is varied for different structures

How to Calculate Volume of Atoms in FCC?

Volume of Atoms in FCC calculator uses Volume of Atoms in Unit Cell = 16/3*pi*Atomic Radius^3 to calculate the Volume of Atoms in Unit Cell, Volume of Atoms in FCC (FCC) unit cell is the total space occupied by the 4 atoms within the unit cell. In an FCC structure, each unit cell contains 4 atoms, and the volume occupied by these atoms is approximately 74% of the total volume of the unit cell. Volume of Atoms in Unit Cell is denoted by Va symbol.

How to calculate Volume of Atoms in FCC using this online calculator? To use this online calculator for Volume of Atoms in FCC, enter Atomic Radius (r) and hit the calculate button. Here is how the Volume of Atoms in FCC calculation can be explained with given input values -> 4.1E+31 = 16/3*pi*1.35E-10^3.

FAQ

What is Volume of Atoms in FCC?
Volume of Atoms in FCC (FCC) unit cell is the total space occupied by the 4 atoms within the unit cell. In an FCC structure, each unit cell contains 4 atoms, and the volume occupied by these atoms is approximately 74% of the total volume of the unit cell and is represented as Va = 16/3*pi*r^3 or Volume of Atoms in Unit Cell = 16/3*pi*Atomic Radius^3. Atomic Radius is the radius of the atom which forms the metallic crystal.
How to calculate Volume of Atoms in FCC?
Volume of Atoms in FCC (FCC) unit cell is the total space occupied by the 4 atoms within the unit cell. In an FCC structure, each unit cell contains 4 atoms, and the volume occupied by these atoms is approximately 74% of the total volume of the unit cell is calculated using Volume of Atoms in Unit Cell = 16/3*pi*Atomic Radius^3. To calculate Volume of Atoms in FCC, you need Atomic Radius (r). With our tool, you need to enter the respective value for Atomic Radius and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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