LCM of two numbers

Voltage Division in Two Inductors Calculator

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✖Source Voltage, is the difference in electric potential between two points, which is defined as the work needed per unit of charge to move a test charge between the two points.ⓘ Source Voltage [V_s]			+10% -10%
✖Circuit inductance 1 is the inductance 1 in the circuit with a voltage source connected in series with two inductance.ⓘ Circuit Inductance 1 [L₁]			+10% -10%
✖Circuit inductance 2 is the inductance 1 in the circuit with a voltage source connected in series with two inductance.ⓘ Circuit Inductance 2 [L₂]			+10% -10%

✖Inductor 1 Voltage is defined as the voltage across the inductor 1 of a circuit with a voltage source and two inductors connected in series.ⓘ Voltage Division in Two Inductors [V_L1]

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Voltage Division in Two Inductors Solution

STEP 0: Pre-Calculation Summary

Formula Used

Inductor 1 Voltage = Source Voltage*((Circuit Inductance 1)/(Circuit Inductance 1+Circuit Inductance 2))
V_L1 = V_s*((L₁)/(L₁+L₂))
This formula uses 4 Variables

Variables Used

Inductor 1 Voltage - (Measured in Volt) - Inductor 1 Voltage is defined as the voltage across the inductor 1 of a circuit with a voltage source and two inductors connected in series.
Source Voltage - (Measured in Volt) - Source Voltage, is the difference in electric potential between two points, which is defined as the work needed per unit of charge to move a test charge between the two points.
Circuit Inductance 1 - (Measured in Henry) - Circuit inductance 1 is the inductance 1 in the circuit with a voltage source connected in series with two inductance.
Circuit Inductance 2 - (Measured in Henry) - Circuit inductance 2 is the inductance 1 in the circuit with a voltage source connected in series with two inductance.

STEP 1: Convert Input(s) to Base Unit

Source Voltage: 120 Volt --> 120 Volt No Conversion Required
Circuit Inductance 1: 0.3 Henry --> 0.3 Henry No Conversion Required
Circuit Inductance 2: 0.15 Henry --> 0.15 Henry No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V_L1 = V_s*((L₁)/(L₁+L₂)) --> 120*((0.3)/(0.3+0.15))

Evaluating ... ...

V_L1 = 80

STEP 3: Convert Result to Output's Unit

80 Volt --> No Conversion Required

FINAL ANSWER

80 Volt <-- Inductor 1 Voltage

(Calculation completed in 00.004 seconds)

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Created by Parminder Singh

Chandigarh University (CU), Punjab

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Voltage Division in Two Inductors Formula

LaTeX Go

Inductor 1 Voltage = Source Voltage*((Circuit Inductance 1)/(Circuit Inductance 1+Circuit Inductance 2))
V_L1 = V_s*((L₁)/(L₁+L₂))

Explain inductors in series?

Inductors in series are simply “added together” because the number of coil turns is effectively increased, with the total circuit inductance LT being equal to the sum of all the individual inductances added together. The current, ( I ) that flows through the first inductor, L1 has no other way to go but pass through the second inductor and the third and so on. Then, series inductors have a Common Current flowing through them. Then the total inductance of the series chain can be found by simply adding together the individual inductances of the inductors in series just like adding together resistors in series.

How to Calculate Voltage Division in Two Inductors?

Voltage Division in Two Inductors calculator uses Inductor 1 Voltage = Source Voltage*((Circuit Inductance 1)/(Circuit Inductance 1+Circuit Inductance 2)) to calculate the Inductor 1 Voltage, The Voltage Division in Two Inductors formula is defined as the division of voltage in a circuit consisting a voltage source and two inductors connected in series. Inductor 1 Voltage is denoted by V_L1 symbol.

How to calculate Voltage Division in Two Inductors using this online calculator? To use this online calculator for Voltage Division in Two Inductors, enter Source Voltage (V_s), Circuit Inductance 1 (L₁) & Circuit Inductance 2 (L₂) and hit the calculate button. Here is how the Voltage Division in Two Inductors calculation can be explained with given input values -> 80 = 120*((0.3)/(0.3+0.15)).

FAQ

What is Voltage Division in Two Inductors?

The Voltage Division in Two Inductors formula is defined as the division of voltage in a circuit consisting a voltage source and two inductors connected in series and is represented as V_L1 = V_s*((L₁)/(L₁+L₂)) or Inductor 1 Voltage = Source Voltage*((Circuit Inductance 1)/(Circuit Inductance 1+Circuit Inductance 2)). Source Voltage, is the difference in electric potential between two points, which is defined as the work needed per unit of charge to move a test charge between the two points, Circuit inductance 1 is the inductance 1 in the circuit with a voltage source connected in series with two inductance & Circuit inductance 2 is the inductance 1 in the circuit with a voltage source connected in series with two inductance.

How to calculate Voltage Division in Two Inductors?

The Voltage Division in Two Inductors formula is defined as the division of voltage in a circuit consisting a voltage source and two inductors connected in series is calculated using Inductor 1 Voltage = Source Voltage*((Circuit Inductance 1)/(Circuit Inductance 1+Circuit Inductance 2)). To calculate Voltage Division in Two Inductors, you need Source Voltage (V_s), Circuit Inductance 1 (L₁) & Circuit Inductance 2 (L₂). With our tool, you need to enter the respective value for Source Voltage, Circuit Inductance 1 & Circuit Inductance 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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