Vertex Diagonal of Frame given Inner and Outer Lengths Calculator

✖The Outer Length of Frame is the length or longest side of the outer rectangle of the Frame.ⓘ Outer Length of Frame [l_Outer]			+10% -10%
✖The Inner Length of Frame is the length or longest side of the inner rectangle of the Frame.ⓘ Inner Length of Frame [l_Inner]			+10% -10%

✖The Vertex Diagonal of Frame is the linear distance between any pair adjacent vertices of inner and outer rectangles of Frame.ⓘ Vertex Diagonal of Frame given Inner and Outer Lengths [d_Vertex]

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Vertex Diagonal of Frame given Inner and Outer Lengths Solution

STEP 0: Pre-Calculation Summary

Formula Used

Vertex Diagonal of Frame = 1/sqrt(2)*(Outer Length of Frame-Inner Length of Frame)
d_Vertex = 1/sqrt(2)*(l_Outer-l_Inner)
This formula uses 1 Functions, 3 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Vertex Diagonal of Frame - (Measured in Meter) - The Vertex Diagonal of Frame is the linear distance between any pair adjacent vertices of inner and outer rectangles of Frame.
Outer Length of Frame - (Measured in Meter) - The Outer Length of Frame is the length or longest side of the outer rectangle of the Frame.
Inner Length of Frame - (Measured in Meter) - The Inner Length of Frame is the length or longest side of the inner rectangle of the Frame.

STEP 1: Convert Input(s) to Base Unit

Outer Length of Frame: 15 Meter --> 15 Meter No Conversion Required
Inner Length of Frame: 9 Meter --> 9 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

d_Vertex = 1/sqrt(2)*(l_Outer-l_Inner) --> 1/sqrt(2)*(15-9)

Evaluating ... ...

d_Vertex = 4.24264068711928

STEP 3: Convert Result to Output's Unit

4.24264068711928 Meter --> No Conversion Required

FINAL ANSWER

4.24264068711928 ≈ 4.242641 Meter <-- Vertex Diagonal of Frame

(Calculation completed in 00.008 seconds)

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Walchand College of Engineering (WCE), Sangli

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Vertex Diagonal of Frame given Inner and Outer Lengths

LaTeX Go Vertex Diagonal of Frame = 1/sqrt(2)*(Outer Length of Frame-Inner Length of Frame)

Vertex Diagonal of Frame given Inner and Outer Widths

LaTeX Go Vertex Diagonal of Frame = 1/sqrt(2)*(Outer Width of Frame-Inner Width of Frame)

Vertex Diagonal of Frame

LaTeX Go Vertex Diagonal of Frame = sqrt(2)*Thickness of Frame

Vertex Diagonal of Frame given Inner and Outer Lengths Formula

LaTeX Go

Vertex Diagonal of Frame = 1/sqrt(2)*(Outer Length of Frame-Inner Length of Frame)
d_Vertex = 1/sqrt(2)*(l_Outer-l_Inner)

What is a Frame?

A Frame is a rectangle, from which a smaller rectangle is removed centrally, whose length and width are an equal value shorter than that of the larger one. The actual rectangle is called outer rectangle and the removed smaller rectangle is called inner rectangle.

How to Calculate Vertex Diagonal of Frame given Inner and Outer Lengths?

Vertex Diagonal of Frame given Inner and Outer Lengths calculator uses Vertex Diagonal of Frame = 1/sqrt(2)*(Outer Length of Frame-Inner Length of Frame) to calculate the Vertex Diagonal of Frame, The Vertex Diagonal of Frame given Inner and Outer Lengths formula is defined as the linear distance between any pair of adjacent vertices of inner and outer rectangles of the Frame and calculated using the inner and outer lengths of the Frame. Vertex Diagonal of Frame is denoted by d_Vertex symbol.

How to calculate Vertex Diagonal of Frame given Inner and Outer Lengths using this online calculator? To use this online calculator for Vertex Diagonal of Frame given Inner and Outer Lengths, enter Outer Length of Frame (l_Outer) & Inner Length of Frame (l_Inner) and hit the calculate button. Here is how the Vertex Diagonal of Frame given Inner and Outer Lengths calculation can be explained with given input values -> 4.242641 = 1/sqrt(2)*(15-9).

FAQ

What is Vertex Diagonal of Frame given Inner and Outer Lengths?

The Vertex Diagonal of Frame given Inner and Outer Lengths formula is defined as the linear distance between any pair of adjacent vertices of inner and outer rectangles of the Frame and calculated using the inner and outer lengths of the Frame and is represented as d_Vertex = 1/sqrt(2)*(l_Outer-l_Inner) or Vertex Diagonal of Frame = 1/sqrt(2)*(Outer Length of Frame-Inner Length of Frame). The Outer Length of Frame is the length or longest side of the outer rectangle of the Frame & The Inner Length of Frame is the length or longest side of the inner rectangle of the Frame.

How to calculate Vertex Diagonal of Frame given Inner and Outer Lengths?

The Vertex Diagonal of Frame given Inner and Outer Lengths formula is defined as the linear distance between any pair of adjacent vertices of inner and outer rectangles of the Frame and calculated using the inner and outer lengths of the Frame is calculated using Vertex Diagonal of Frame = 1/sqrt(2)*(Outer Length of Frame-Inner Length of Frame). To calculate Vertex Diagonal of Frame given Inner and Outer Lengths, you need Outer Length of Frame (l_Outer) & Inner Length of Frame (l_Inner). With our tool, you need to enter the respective value for Outer Length of Frame & Inner Length of Frame and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Vertex Diagonal of Frame?

In this formula, Vertex Diagonal of Frame uses Outer Length of Frame & Inner Length of Frame. We can use 2 other way(s) to calculate the same, which is/are as follows -

Vertex Diagonal of Frame = sqrt(2)*Thickness of Frame
Vertex Diagonal of Frame = 1/sqrt(2)*(Outer Width of Frame-Inner Width of Frame)

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