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Ultimate BOD given Oxygen Required in Aeration Tank Calculator

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Ultimate BOD Important Formulas of Oxygen Requirement of the Aeration Tank BOD to Ultimate BOD BOD5 More >>

✖5 Days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.ⓘ 5 Days BOD [BOD5]			+10% -10%
✖Sewage Discharge is the flow rate of sewage when it is being discharged in the river.ⓘ Sewage Discharge [Q_s]			+10% -10%
✖Influent BOD is the total amount of BOD which is present in the incoming sewage.ⓘ Influent BOD [Q_i]			+10% -10%
✖Effluent BOD is the amount of BOD present in the outing sewage.ⓘ Effluent BOD [Q]			+10% -10%
✖Theoretical Oxygen Requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.ⓘ Theoretical Oxygen Requirement [O₂]			+10% -10%
✖Volume of Wasted Sludge per day is the amount of sludge that is removed or wasted from a wastewater treatment process on a daily basis.ⓘ Volume of Wasted Sludge per day [Q_w]			+10% -10%
✖MLSS in Returned or Wasted Sludge is the mixed liquor suspended solids in returned sludge in terms of mg per liter.ⓘ MLSS in Returned or Wasted Sludge [X^R]			+10% -10%

✖Ultimate BOD given Oxygen Required is represents the total amount of oxygen consumed by microorganisms during the biochemical oxidation of organic matter in a water sample.ⓘ Ultimate BOD given Oxygen Required in Aeration Tank [BOD_uo]

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Ultimate BOD given Oxygen Required in Aeration Tank Solution

STEP 0: Pre-Calculation Summary

Formula Used

Ultimate BOD given Oxygen Required = 5 Days BOD/(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in Returned or Wasted Sludge))
BOD_uo = BOD5/(Q_s*(Q_i-Q))/(O₂+(1.42*Q_w*X^R))
This formula uses 8 Variables

Variables Used

Ultimate BOD given Oxygen Required - (Measured in Milligram per Liter) - Ultimate BOD given Oxygen Required is represents the total amount of oxygen consumed by microorganisms during the biochemical oxidation of organic matter in a water sample.
5 Days BOD - (Measured in Milligram per Liter) - 5 Days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.
Sewage Discharge - (Measured in Cubic Meter per Second) - Sewage Discharge is the flow rate of sewage when it is being discharged in the river.
Influent BOD - (Measured in Milligram per Liter) - Influent BOD is the total amount of BOD which is present in the incoming sewage.
Effluent BOD - (Measured in Milligram per Liter) - Effluent BOD is the amount of BOD present in the outing sewage.
Theoretical Oxygen Requirement - (Measured in Kilogram per Second) - Theoretical Oxygen Requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.
Volume of Wasted Sludge per day - (Measured in Cubic Meter per Second) - Volume of Wasted Sludge per day is the amount of sludge that is removed or wasted from a wastewater treatment process on a daily basis.
MLSS in Returned or Wasted Sludge - (Measured in Milligram per Liter) - MLSS in Returned or Wasted Sludge is the mixed liquor suspended solids in returned sludge in terms of mg per liter.

STEP 1: Convert Input(s) to Base Unit

5 Days BOD: 1.36 Milligram per Liter --> 1.36 Milligram per Liter No Conversion Required
Sewage Discharge: 10 Cubic Meter per Second --> 10 Cubic Meter per Second No Conversion Required
Influent BOD: 13.2 Milligram per Liter --> 13.2 Milligram per Liter No Conversion Required
Effluent BOD: 0.4 Milligram per Liter --> 0.4 Milligram per Liter No Conversion Required
Theoretical Oxygen Requirement: 2.5 Milligram per Day --> 2.89351851851852E-11 Kilogram per Second (Check conversion here)
Volume of Wasted Sludge per day: 9.5 Cubic Meter per Second --> 9.5 Cubic Meter per Second No Conversion Required
MLSS in Returned or Wasted Sludge: 1.4 Milligram per Liter --> 1.4 Milligram per Liter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

BOD_uo = BOD5/(Q_s*(Q_i-Q))/(O₂+(1.42*Q_w*X^R)) --> 1.36/(10*(13.2-0.4))/(2.89351851851852E-11+(1.42*9.5*1.4))

Evaluating ... ...

BOD_uo = 0.000562586042570355

STEP 3: Convert Result to Output's Unit

5.62586042570355E-07 Kilogram per Cubic Meter -->0.000562586042570355 Milligram per Liter (Check conversion here)

FINAL ANSWER

0.000562586042570355 ≈ 0.000563 Milligram per Liter <-- Ultimate BOD given Oxygen Required

(Calculation completed in 00.004 seconds)

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< Ultimate BOD Calculators

Ultimate BOD given Oxygen Required in Aeration Tank

LaTeX Go Ultimate BOD given Oxygen Required = 5 Days BOD/(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in Returned or Wasted Sludge))

Ultimate BOD given Ratio of BOD to Ultimate BOD

LaTeX Go Ultimate BOD given Ratio of BOD to Ultimate BOD = 5 Days BOD/Ratio of BOD to Ultimate BOD

Ultimate Biochemical Oxygen Demand

LaTeX Go Ultimate BOD = 5 Days BOD/0.68

Ultimate BOD given Oxygen Required in Aeration Tank Formula

LaTeX Go

What is Ultimate BOD?

The ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time. This is usually simply calculated by conducting the experiment over a 20thday period.

How to Calculate Ultimate BOD given Oxygen Required in Aeration Tank?

Ultimate BOD given Oxygen Required in Aeration Tank calculator uses Ultimate BOD given Oxygen Required = 5 Days BOD/(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in Returned or Wasted Sludge)) to calculate the Ultimate BOD given Oxygen Required, The Ultimate BOD given Oxygen Required in Aeration Tank formula is defined as the calculation of ultimate BOD when we have prior information of oxygen required in aeration tank. Ultimate BOD given Oxygen Required is denoted by BOD_uo symbol.

How to calculate Ultimate BOD given Oxygen Required in Aeration Tank using this online calculator? To use this online calculator for Ultimate BOD given Oxygen Required in Aeration Tank, enter 5 Days BOD (BOD5), Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q), Theoretical Oxygen Requirement (O₂), Volume of Wasted Sludge per day (Q_w) & MLSS in Returned or Wasted Sludge (X^R) and hit the calculate button. Here is how the Ultimate BOD given Oxygen Required in Aeration Tank calculation can be explained with given input values -> 0.562586 = 0.00136/(10*(0.0132-0.0004))/(2.89351851851852E-11+(1.42*9.5*0.0014)).

FAQ

What is Ultimate BOD given Oxygen Required in Aeration Tank?

The Ultimate BOD given Oxygen Required in Aeration Tank formula is defined as the calculation of ultimate BOD when we have prior information of oxygen required in aeration tank and is represented as BOD_uo = BOD5/(Q_s*(Q_i-Q))/(O₂+(1.42*Q_w*X^R)) or Ultimate BOD given Oxygen Required = 5 Days BOD/(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in Returned or Wasted Sludge)). 5 Days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C, Sewage Discharge is the flow rate of sewage when it is being discharged in the river, Influent BOD is the total amount of BOD which is present in the incoming sewage, Effluent BOD is the amount of BOD present in the outing sewage, Theoretical Oxygen Requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products, Volume of Wasted Sludge per day is the amount of sludge that is removed or wasted from a wastewater treatment process on a daily basis & MLSS in Returned or Wasted Sludge is the mixed liquor suspended solids in returned sludge in terms of mg per liter.

How to calculate Ultimate BOD given Oxygen Required in Aeration Tank?

The Ultimate BOD given Oxygen Required in Aeration Tank formula is defined as the calculation of ultimate BOD when we have prior information of oxygen required in aeration tank is calculated using Ultimate BOD given Oxygen Required = 5 Days BOD/(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in Returned or Wasted Sludge)). To calculate Ultimate BOD given Oxygen Required in Aeration Tank, you need 5 Days BOD (BOD5), Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q), Theoretical Oxygen Requirement (O₂), Volume of Wasted Sludge per day (Q_w) & MLSS in Returned or Wasted Sludge (X^R). With our tool, you need to enter the respective value for 5 Days BOD, Sewage Discharge, Influent BOD, Effluent BOD, Theoretical Oxygen Requirement, Volume of Wasted Sludge per day & MLSS in Returned or Wasted Sludge and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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