Total Volume of Atoms in BCC Calculator

✖Atomic Radius is the radius of the atom which forms the metallic crystal.ⓘ Atomic Radius [r]

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✖Volume of Atoms in Unit Cell is the total volume of atoms present in the unit cell.ⓘ Total Volume of Atoms in BCC [V_a]

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Total Volume of Atoms in BCC Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume of Atoms in Unit Cell = 8/3*pi*Atomic Radius^3
V_a = 8/3*pi*r^3
This formula uses 1 Constants, 2 Variables

Constants Used

pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Variables Used

Volume of Atoms in Unit Cell - (Measured in Cubic Meter) - Volume of Atoms in Unit Cell is the total volume of atoms present in the unit cell.
Atomic Radius - (Measured in Meter) - Atomic Radius is the radius of the atom which forms the metallic crystal.

STEP 1: Convert Input(s) to Base Unit

Atomic Radius: 1.35 Angstrom --> 1.35E-10 Meter (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V_a = 8/3*pi*r^3 --> 8/3*pi*1.35E-10^3

Evaluating ... ...

V_a = 2.06119894002026E-29

STEP 3: Convert Result to Output's Unit

2.06119894002026E-29 Cubic Meter -->20.6119894002026 Cubic Angstrom (Check conversion here)

FINAL ANSWER

20.6119894002026 ≈ 20.61199 Cubic Angstrom <-- Volume of Atoms in Unit Cell

(Calculation completed in 00.020 seconds)

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Created by Sanjay Krishna

Amrita School of Engineering (ASE), Vallikavu

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K J Somaiya College of Engineering (K J Somaiya), Mumbai

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Total Volume of Atoms in BCC

LaTeX Go Volume of Atoms in Unit Cell = 8/3*pi*Atomic Radius^3

Atomic Radius in BCC

LaTeX Go Atomic Radius = (sqrt(3))/4*Lattice Parameter of BCC

Lattice Constant of BCC

LaTeX Go Lattice Parameter of BCC = 4/sqrt(3)*Atomic Radius

Total Volume of Atoms in BCC Formula

LaTeX Go

Volume of Atoms in Unit Cell = 8/3*pi*Atomic Radius^3
V_a = 8/3*pi*r^3

Calculator for finding the volume of atoms in unit cell of BCC.

The primitive unit cell for the body-centered cubic crystal structure contains several fractions taken from nine atoms (if the particles in the crystal are atoms): one on each corner of the cube and one atom in the center. Because the volume of each of the eight corner atoms is shared between eight adjacent cells, each BCC cell contains the equivalent volume of two atoms (one central and one on the corner). The total volume of atoms in BCC formula is defined as similar to volume of sphere but the the equation is multiplied by 2 number of atoms and radius value changes since the atomic radius r =(sqrt(3)/4)*a where a is lattice constant

How to Calculate Total Volume of Atoms in BCC?

Total Volume of Atoms in BCC calculator uses Volume of Atoms in Unit Cell = 8/3*pi*Atomic Radius^3 to calculate the Volume of Atoms in Unit Cell, Total Volume of Atoms in BCC (BCC) unit cell is the sum of the volumes of two atoms, since there is one atom at the center and eight corner atoms, each contributing one-eighth, resulting in a total of two whole atoms occupying the cell. Volume of Atoms in Unit Cell is denoted by V_a symbol.

How to calculate Total Volume of Atoms in BCC using this online calculator? To use this online calculator for Total Volume of Atoms in BCC, enter Atomic Radius (r) and hit the calculate button. Here is how the Total Volume of Atoms in BCC calculation can be explained with given input values -> 2.1E+31 = 8/3*pi*1.35E-10^3.

FAQ

What is Total Volume of Atoms in BCC?

Total Volume of Atoms in BCC (BCC) unit cell is the sum of the volumes of two atoms, since there is one atom at the center and eight corner atoms, each contributing one-eighth, resulting in a total of two whole atoms occupying the cell and is represented as V_a = 8/3*pi*r^3 or Volume of Atoms in Unit Cell = 8/3*pi*Atomic Radius^3. Atomic Radius is the radius of the atom which forms the metallic crystal.

How to calculate Total Volume of Atoms in BCC?

Total Volume of Atoms in BCC (BCC) unit cell is the sum of the volumes of two atoms, since there is one atom at the center and eight corner atoms, each contributing one-eighth, resulting in a total of two whole atoms occupying the cell is calculated using Volume of Atoms in Unit Cell = 8/3*pi*Atomic Radius^3. To calculate Total Volume of Atoms in BCC, you need Atomic Radius (r). With our tool, you need to enter the respective value for Atomic Radius and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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