Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid Solution

STEP 0: Pre-Calculation Summary
Formula Used
Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A))
P = PB°+((PB°*WA*MB)/(WB*MA))
This formula uses 6 Variables
Variables Used
Total Pressure of Mixture of Immiscible Liquids - (Measured in Pascal) - The Total Pressure of mixture of immiscible liquids is the sum of their pure state partial pressures since mole fraction of each is 1.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Weight of Liquid A - (Measured in Kilogram) - The Weight of Liquid A in a mixture of immiscible liquids.
Molecular Mass of Liquid B - (Measured in Kilogram) - The Molecular Mass of Liquid B in a mixture of immiscible liquids.
Weight of Liquid B - (Measured in Kilogram) - The Weight of Liquid B in a mixture of immiscible liquids.
Molecular Mass of Liquid A - (Measured in Kilogram) - The Molecular Mass of Liquid A in a mixture of immiscible liquids.
STEP 1: Convert Input(s) to Base Unit
Vapor Pressure of Pure Component B: 0.25 Pascal --> 0.25 Pascal No Conversion Required
Weight of Liquid A: 0.5 Gram --> 0.0005 Kilogram (Check conversion ​here)
Molecular Mass of Liquid B: 31.8 Gram --> 0.0318 Kilogram (Check conversion ​here)
Weight of Liquid B: 0.1 Gram --> 0.0001 Kilogram (Check conversion ​here)
Molecular Mass of Liquid A: 14.72 Gram --> 0.01472 Kilogram (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
P = PB°+((PB°*WA*MB)/(WB*MA)) --> 0.25+((0.25*0.0005*0.0318)/(0.0001*0.01472))
Evaluating ... ...
P = 2.95040760869565
STEP 3: Convert Result to Output's Unit
2.95040760869565 Pascal --> No Conversion Required
FINAL ANSWER
2.95040760869565 2.950408 Pascal <-- Total Pressure of Mixture of Immiscible Liquids
(Calculation completed in 00.008 seconds)

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Immiscible Liquids Calculators

Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid
​ LaTeX ​ Go Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B)
Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass
​ LaTeX ​ Go Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)
Total Pressure of Mixture of Two Immiscible Liquids
​ LaTeX ​ Go Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B
Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles
​ LaTeX ​ Go Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B

Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid Formula

​LaTeX ​Go
Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A))
P = PB°+((PB°*WA*MB)/(WB*MA))

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid?

Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid calculator uses Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)) to calculate the Total Pressure of Mixture of Immiscible Liquids, The Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid considering A as unknown parameter and B as known parameter. Total Pressure of Mixture of Immiscible Liquids is denoted by P symbol.

How to calculate Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid using this online calculator? To use this online calculator for Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid, enter Vapor Pressure of Pure Component B (PB°), Weight of Liquid A (WA), Molecular Mass of Liquid B (MB), Weight of Liquid B (WB) & Molecular Mass of Liquid A (MA) and hit the calculate button. Here is how the Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid calculation can be explained with given input values -> 2.950408 = 0.25+((0.25*0.0005*0.0318)/(0.0001*0.01472)).

FAQ

What is Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid?
The Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid considering A as unknown parameter and B as known parameter and is represented as P = PB°+((PB°*WA*MB)/(WB*MA)) or Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)). Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase, The Weight of Liquid A in a mixture of immiscible liquids, The Molecular Mass of Liquid B in a mixture of immiscible liquids, The Weight of Liquid B in a mixture of immiscible liquids & The Molecular Mass of Liquid A in a mixture of immiscible liquids.
How to calculate Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid?
The Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid considering A as unknown parameter and B as known parameter is calculated using Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)). To calculate Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid, you need Vapor Pressure of Pure Component B (PB°), Weight of Liquid A (WA), Molecular Mass of Liquid B (MB), Weight of Liquid B (WB) & Molecular Mass of Liquid A (MA). With our tool, you need to enter the respective value for Vapor Pressure of Pure Component B, Weight of Liquid A, Molecular Mass of Liquid B, Weight of Liquid B & Molecular Mass of Liquid A and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Total Pressure of Mixture of Immiscible Liquids?
In this formula, Total Pressure of Mixture of Immiscible Liquids uses Vapor Pressure of Pure Component B, Weight of Liquid A, Molecular Mass of Liquid B, Weight of Liquid B & Molecular Mass of Liquid A. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B
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