What is a Rhombicuboctahedron?
In geometry, the Rhombicuboctahedron, or small Rhombicuboctahedron, is an Archimedean solid with 8 triangular and 18 square faces. There are 24 identical vertices, with one triangle and three squares meeting at each one. The polyhedron has octahedral symmetry, like the cube and octahedron. Its dual is called the deltoidal icositetrahedron or trapezoidal icositetrahedron, although its faces are not really true trapezoids.
How to Calculate Total Surface Area of Rhombicuboctahedron given Midsphere Radius?
Total Surface Area of Rhombicuboctahedron given Midsphere Radius calculator uses Total Surface Area of Rhombicuboctahedron = 2*(9+sqrt(3))*((2*Midsphere Radius of Rhombicuboctahedron)/(sqrt(4+(2*sqrt(2)))))^2 to calculate the Total Surface Area of Rhombicuboctahedron, Total Surface Area of Rhombicuboctahedron given Midsphere Radius formula is defined as the total quantity of plane enclosed by the entire surface of the Rhombicuboctahedron, and calculated using the midsphere radius of the Rhombicuboctahedron. Total Surface Area of Rhombicuboctahedron is denoted by TSA symbol.
How to calculate Total Surface Area of Rhombicuboctahedron given Midsphere Radius using this online calculator? To use this online calculator for Total Surface Area of Rhombicuboctahedron given Midsphere Radius, enter Midsphere Radius of Rhombicuboctahedron (rm) and hit the calculate button. Here is how the Total Surface Area of Rhombicuboctahedron given Midsphere Radius calculation can be explained with given input values -> 2124.901 = 2*(9+sqrt(3))*((2*13)/(sqrt(4+(2*sqrt(2)))))^2.