Total Pressure of Mixture of Water with Liquid given Vapour Pressure Solution

STEP 0: Pre-Calculation Summary
Formula Used
Total Pressure of Mixture of Liquid with Water = Vapor Pressure of Pure Component B+((Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water))
Ptot = PB°+((Wwater*PB°*MB)/(WB*Mwater))
This formula uses 6 Variables
Variables Used
Total Pressure of Mixture of Liquid with Water - (Measured in Pascal) - The Total Pressure of mixture of Liquid with Water is the sum of their pure state partial pressures since mole fraction of each is 1.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Weight of Water in Immiscible Mixture - (Measured in Kilogram) - The Weight of Water in Immiscible Mixture with another liquid.
Molecular Mass of Liquid B - (Measured in Kilogram) - The Molecular Mass of Liquid B in a mixture of immiscible liquids.
Weight of Liquid B - (Measured in Kilogram) - The Weight of Liquid B in a mixture of immiscible liquids.
Molecular Mass of Water - (Measured in Kilogram) - The Molecular Mass of Water is equal to 18g per mole.
STEP 1: Convert Input(s) to Base Unit
Vapor Pressure of Pure Component B: 0.25 Pascal --> 0.25 Pascal No Conversion Required
Weight of Water in Immiscible Mixture: 0.12 Gram --> 0.00012 Kilogram (Check conversion ​here)
Molecular Mass of Liquid B: 31.8 Gram --> 0.0318 Kilogram (Check conversion ​here)
Weight of Liquid B: 0.1 Gram --> 0.0001 Kilogram (Check conversion ​here)
Molecular Mass of Water: 18 Gram --> 0.018 Kilogram (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Ptot = PB°+((Wwater*PB°*MB)/(WB*Mwater)) --> 0.25+((0.00012*0.25*0.0318)/(0.0001*0.018))
Evaluating ... ...
Ptot = 0.78
STEP 3: Convert Result to Output's Unit
0.78 Pascal --> No Conversion Required
FINAL ANSWER
0.78 Pascal <-- Total Pressure of Mixture of Liquid with Water
(Calculation completed in 00.004 seconds)

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Immiscible Liquids Calculators

Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid
​ LaTeX ​ Go Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B)
Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass
​ LaTeX ​ Go Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)
Total Pressure of Mixture of Two Immiscible Liquids
​ LaTeX ​ Go Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B
Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles
​ LaTeX ​ Go Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B

Total Pressure of Mixture of Water with Liquid given Vapour Pressure Formula

​LaTeX ​Go
Total Pressure of Mixture of Liquid with Water = Vapor Pressure of Pure Component B+((Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water))
Ptot = PB°+((Wwater*PB°*MB)/(WB*Mwater))

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Total Pressure of Mixture of Water with Liquid given Vapour Pressure?

Total Pressure of Mixture of Water with Liquid given Vapour Pressure calculator uses Total Pressure of Mixture of Liquid with Water = Vapor Pressure of Pure Component B+((Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water)) to calculate the Total Pressure of Mixture of Liquid with Water, The Total Pressure of Mixture of Water with Liquid given Vapour Pressure considering A as water and B as other liquids for corresponding parameters. Total Pressure of Mixture of Liquid with Water is denoted by Ptot symbol.

How to calculate Total Pressure of Mixture of Water with Liquid given Vapour Pressure using this online calculator? To use this online calculator for Total Pressure of Mixture of Water with Liquid given Vapour Pressure, enter Vapor Pressure of Pure Component B (PB°), Weight of Water in Immiscible Mixture (Wwater), Molecular Mass of Liquid B (MB), Weight of Liquid B (WB) & Molecular Mass of Water (Mwater) and hit the calculate button. Here is how the Total Pressure of Mixture of Water with Liquid given Vapour Pressure calculation can be explained with given input values -> 0.78 = 0.25+((0.00012*0.25*0.0318)/(0.0001*0.018)).

FAQ

What is Total Pressure of Mixture of Water with Liquid given Vapour Pressure?
The Total Pressure of Mixture of Water with Liquid given Vapour Pressure considering A as water and B as other liquids for corresponding parameters and is represented as Ptot = PB°+((Wwater*PB°*MB)/(WB*Mwater)) or Total Pressure of Mixture of Liquid with Water = Vapor Pressure of Pure Component B+((Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water)). Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase, The Weight of Water in Immiscible Mixture with another liquid, The Molecular Mass of Liquid B in a mixture of immiscible liquids, The Weight of Liquid B in a mixture of immiscible liquids & The Molecular Mass of Water is equal to 18g per mole.
How to calculate Total Pressure of Mixture of Water with Liquid given Vapour Pressure?
The Total Pressure of Mixture of Water with Liquid given Vapour Pressure considering A as water and B as other liquids for corresponding parameters is calculated using Total Pressure of Mixture of Liquid with Water = Vapor Pressure of Pure Component B+((Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water)). To calculate Total Pressure of Mixture of Water with Liquid given Vapour Pressure, you need Vapor Pressure of Pure Component B (PB°), Weight of Water in Immiscible Mixture (Wwater), Molecular Mass of Liquid B (MB), Weight of Liquid B (WB) & Molecular Mass of Water (Mwater). With our tool, you need to enter the respective value for Vapor Pressure of Pure Component B, Weight of Water in Immiscible Mixture, Molecular Mass of Liquid B, Weight of Liquid B & Molecular Mass of Water and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Total Pressure of Mixture of Liquid with Water?
In this formula, Total Pressure of Mixture of Liquid with Water uses Vapor Pressure of Pure Component B, Weight of Water in Immiscible Mixture, Molecular Mass of Liquid B, Weight of Liquid B & Molecular Mass of Water. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Total Pressure of Mixture of Liquid with Water = Partial Pressure of Pure Water+((Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Weight of Water in Immiscible Mixture*Molecular Mass of Liquid B))
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