Total Moles at Equilibrium using Number of Moles and Initial Total Moles Solution

STEP 0: Pre-Calculation Summary
Formula Used
Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1))
M = ninitial/(1+𝝰*(Nmoles-1))
This formula uses 4 Variables
Variables Used
Total Moles at Equilibrium - Total Moles at Equilibrium is the complete moles which are present at the equilibrium stage of the chemical reaction.
Initial Number of Moles - (Measured in Mole) - Initial Number of Moles is the amount of gas present in moles at the primary stage of reaction at equilibrium.
Degree of Dissociation - The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.
Number of Moles - Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.
STEP 1: Convert Input(s) to Base Unit
Initial Number of Moles: 17 Mole --> 17 Mole No Conversion Required
Degree of Dissociation: 0.35 --> No Conversion Required
Number of Moles: 2 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
M = ninitial/(1+𝝰*(Nmoles-1)) --> 17/(1+0.35*(2-1))
Evaluating ... ...
M = 12.5925925925926
STEP 3: Convert Result to Output's Unit
12.5925925925926 --> No Conversion Required
FINAL ANSWER
12.5925925925926 12.59259 <-- Total Moles at Equilibrium
(Calculation completed in 00.004 seconds)

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Created by Akshada Kulkarni
National Institute of Information Technology (NIIT), Neemrana
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Relation between Vapour Density and Degree of Dissociation Calculators

Initial Vapour Density
​ LaTeX ​ Go Initial Vapour Density = (Total Moles at Equilibrium*Equilibrium Vapour Density)/Initial Number of Moles
Molecular Weight of Substance given Initial Vapour Density
​ LaTeX ​ Go Molecular Weight = Initial Vapour Density*Volume of Solution
Volume of Solution given Initial Vapour Density
​ LaTeX ​ Go Volume of Solution = Molecular Weight/Initial Vapour Density
Initial Vapour Density given Molecular Weight
​ LaTeX ​ Go Initial Vapour Density = Molecular Weight/Volume of Solution

Total Moles at Equilibrium using Number of Moles and Initial Total Moles Formula

​LaTeX ​Go
Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1))
M = ninitial/(1+𝝰*(Nmoles-1))

What is Degree of Dissociation?

The fraction of the initial molecules that are converted at equilibrium is called the degree of Dissociation/ionization. It is unit less. The degree of dissociation is the phenomenon of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.

How to Calculate Total Moles at Equilibrium using Number of Moles and Initial Total Moles?

Total Moles at Equilibrium using Number of Moles and Initial Total Moles calculator uses Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1)) to calculate the Total Moles at Equilibrium, The Total moles at equilibrium using number of moles and initial total moles formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction. Total Moles at Equilibrium is denoted by M symbol.

How to calculate Total Moles at Equilibrium using Number of Moles and Initial Total Moles using this online calculator? To use this online calculator for Total Moles at Equilibrium using Number of Moles and Initial Total Moles, enter Initial Number of Moles (ninitial), Degree of Dissociation (𝝰) & Number of Moles (Nmoles) and hit the calculate button. Here is how the Total Moles at Equilibrium using Number of Moles and Initial Total Moles calculation can be explained with given input values -> 12.59259 = 17/(1+0.35*(2-1)).

FAQ

What is Total Moles at Equilibrium using Number of Moles and Initial Total Moles?
The Total moles at equilibrium using number of moles and initial total moles formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction and is represented as M = ninitial/(1+𝝰*(Nmoles-1)) or Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1)). Initial Number of Moles is the amount of gas present in moles at the primary stage of reaction at equilibrium, The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration & Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.
How to calculate Total Moles at Equilibrium using Number of Moles and Initial Total Moles?
The Total moles at equilibrium using number of moles and initial total moles formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction is calculated using Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1)). To calculate Total Moles at Equilibrium using Number of Moles and Initial Total Moles, you need Initial Number of Moles (ninitial), Degree of Dissociation (𝝰) & Number of Moles (Nmoles). With our tool, you need to enter the respective value for Initial Number of Moles, Degree of Dissociation & Number of Moles and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Total Moles at Equilibrium?
In this formula, Total Moles at Equilibrium uses Initial Number of Moles, Degree of Dissociation & Number of Moles. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Total Moles at Equilibrium = (Initial Vapour Density*Initial Number of Moles)/Equilibrium Vapour Density
  • Total Moles at Equilibrium = Initial Number of Moles*(1+Degree of Dissociation)
  • Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1))
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