LCM of two numbers

Total moles at equilibrium given number of moles of reaction Calculator

Chemistry Engineering Financial Health More >>

↳

Equilibrium Analytical chemistry Atmospheric Chemistry Atomic structure More >>

⤿

Chemical equilibrium Ionic equilibrium

⤿

Relation between Vapour Density and Degree of Dissociation Equilibrium Constant Henry's law Properties of Equilibrium Constant More >>

⤿

Degree of Dissociation Vapour Density at Equilibrium

✖Equilibrium Vapour Density is the density of a vapour substance during the stages of reaction at equilibrium.ⓘ Equilibrium Vapour Density [d]			+10% -10%
✖The Volume of Solution gives the volume of the solution in liters.ⓘ Volume of Solution [V]			+10% -10%
✖The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.ⓘ Degree of Dissociation [𝝰]			+10% -10%
✖Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.ⓘ Number of Moles [N_moles]			+10% -10%

✖Total Moles at Equilibrium is the complete moles which are present at the equilibrium stage of the chemical reaction.ⓘ Total moles at equilibrium given number of moles of reaction [M]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download Chemical equilibrium Formula PDF PDF Image

Total moles at equilibrium given number of moles of reaction Solution

STEP 0: Pre-Calculation Summary

Formula Used

Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1))
M = d*V*(1+𝝰*(N_moles-1))
This formula uses 5 Variables

Variables Used

Total Moles at Equilibrium - Total Moles at Equilibrium is the complete moles which are present at the equilibrium stage of the chemical reaction.
Equilibrium Vapour Density - Equilibrium Vapour Density is the density of a vapour substance during the stages of reaction at equilibrium.
Volume of Solution - (Measured in Cubic Meter) - The Volume of Solution gives the volume of the solution in liters.
Degree of Dissociation - The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.
Number of Moles - Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.

STEP 1: Convert Input(s) to Base Unit

Equilibrium Vapour Density: 150 --> No Conversion Required
Volume of Solution: 450 Liter --> 0.45 Cubic Meter (Check conversion here)
Degree of Dissociation: 0.35 --> No Conversion Required
Number of Moles: 2 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

M = d*V*(1+𝝰*(N_moles-1)) --> 150*0.45*(1+0.35*(2-1))

Evaluating ... ...

M = 91.125

STEP 3: Convert Result to Output's Unit

91.125 --> No Conversion Required

FINAL ANSWER

91.125 <-- Total Moles at Equilibrium

(Calculation completed in 00.004 seconds)

You are here -

Home » Chemistry » Equilibrium » Chemical equilibrium » Relation between Vapour Density and Degree of Dissociation » Total moles at equilibrium given number of moles of reaction

Credits

Created by Akshada Kulkarni

National Institute of Information Technology (NIIT), Neemrana

Akshada Kulkarni has created this Calculator and 500+ more calculators!

Verified by Pragati Jaju

College Of Engineering (COEP), Pune

Pragati Jaju has verified this Calculator and 200+ more calculators!

< Relation between Vapour Density and Degree of Dissociation Calculators

Initial Vapour Density

LaTeX Go Initial Vapour Density = (Total Moles at Equilibrium*Equilibrium Vapour Density)/Initial Number of Moles

Molecular Weight of Substance given Initial Vapour Density

LaTeX Go Molecular Weight = Initial Vapour Density*Volume of Solution

Volume of Solution given Initial Vapour Density

LaTeX Go Volume of Solution = Molecular Weight/Initial Vapour Density

Initial Vapour Density given Molecular Weight

LaTeX Go Initial Vapour Density = Molecular Weight/Volume of Solution

Total moles at equilibrium given number of moles of reaction Formula

LaTeX Go

Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1))
M = d*V*(1+𝝰*(N_moles-1))

What is Vapour density?

Vapour density is the weight of a volume of pure vapor or gas compared to an equal volume of dry air at the same temperature and pressure. It is obtained by dividing the molecular weight of the vapor by the average molecular weight of air thus, it is unitless. It is also defined as the fraction of moles dissociated out of 1 mole.

How to Calculate Total moles at equilibrium given number of moles of reaction?

Total moles at equilibrium given number of moles of reaction calculator uses Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1)) to calculate the Total Moles at Equilibrium, The Total moles at equilibrium given number of moles of reaction formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction. Total Moles at Equilibrium is denoted by M symbol.

How to calculate Total moles at equilibrium given number of moles of reaction using this online calculator? To use this online calculator for Total moles at equilibrium given number of moles of reaction, enter Equilibrium Vapour Density (d), Volume of Solution (V), Degree of Dissociation (𝝰) & Number of Moles (N_moles) and hit the calculate button. Here is how the Total moles at equilibrium given number of moles of reaction calculation can be explained with given input values -> 91.125 = 150*0.45*(1+0.35*(2-1)).

FAQ

What is Total moles at equilibrium given number of moles of reaction?

The Total moles at equilibrium given number of moles of reaction formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction and is represented as M = d*V*(1+𝝰*(N_moles-1)) or Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1)). Equilibrium Vapour Density is the density of a vapour substance during the stages of reaction at equilibrium, The Volume of Solution gives the volume of the solution in liters, The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration & Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.

How to calculate Total moles at equilibrium given number of moles of reaction?

The Total moles at equilibrium given number of moles of reaction formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction is calculated using Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1)). To calculate Total moles at equilibrium given number of moles of reaction, you need Equilibrium Vapour Density (d), Volume of Solution (V), Degree of Dissociation (𝝰) & Number of Moles (N_moles). With our tool, you need to enter the respective value for Equilibrium Vapour Density, Volume of Solution, Degree of Dissociation & Number of Moles and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Total Moles at Equilibrium?

In this formula, Total Moles at Equilibrium uses Equilibrium Vapour Density, Volume of Solution, Degree of Dissociation & Number of Moles. We can use 3 other way(s) to calculate the same, which is/are as follows -

Total Moles at Equilibrium = (Initial Vapour Density*Initial Number of Moles)/Equilibrium Vapour Density
Total Moles at Equilibrium = Initial Number of Moles*(1+Degree of Dissociation)
Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1))

Home

FREE PDFs

🔍 Search