Time Required to Lower Liquid Surface using Bazins Formula Solution

STEP 0: Pre-Calculation Summary
Formula Used
Time Interval = ((2*Cross-Sectional Area of Reservoir)/(Bazins Coefficient*sqrt(2*Acceleration due to Gravity)))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))
Δt = ((2*AR)/(m*sqrt(2*g)))*(1/sqrt(h2)-1/sqrt(HUpstream))
This formula uses 1 Functions, 6 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Time Interval - (Measured in Second) - Time interval is the time duration between two events/entities of interest.
Cross-Sectional Area of Reservoir - (Measured in Square Meter) - Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.
Bazins Coefficient - Bazins Coefficient is the constant value obtained by Head.
Acceleration due to Gravity - (Measured in Meter per Square Second) - The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.
Head on Downstream of Weir - (Measured in Meter) - Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.
Head on Upstream of Weir - (Measured in Meter) - Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.
STEP 1: Convert Input(s) to Base Unit
Cross-Sectional Area of Reservoir: 13 Square Meter --> 13 Square Meter No Conversion Required
Bazins Coefficient: 0.407 --> No Conversion Required
Acceleration due to Gravity: 9.8 Meter per Square Second --> 9.8 Meter per Square Second No Conversion Required
Head on Downstream of Weir: 5.1 Meter --> 5.1 Meter No Conversion Required
Head on Upstream of Weir: 10.1 Meter --> 10.1 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Δt = ((2*AR)/(m*sqrt(2*g)))*(1/sqrt(h2)-1/sqrt(HUpstream)) --> ((2*13)/(0.407*sqrt(2*9.8)))*(1/sqrt(5.1)-1/sqrt(10.1))
Evaluating ... ...
Δt = 1.8491251736168
STEP 3: Convert Result to Output's Unit
1.8491251736168 Second --> No Conversion Required
FINAL ANSWER
1.8491251736168 1.849125 Second <-- Time Interval
(Calculation completed in 00.004 seconds)

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National Institute of Technology (NIT), Warangal
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National Institute of Technology Karnataka (NITK), Surathkal
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Time Required to Empty a Reservoir with Rectangular Weir Calculators

Coefficient of Discharge for Time Required to Lower Liquid Surface
​ LaTeX ​ Go Coefficient of Discharge = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Time Interval*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))
Length of Crest for time required to Lower Liquid Surface
​ LaTeX ​ Go Length of Weir Crest = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Time Interval))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))
Time Required to Lower Liquid Surface
​ LaTeX ​ Go Time Interval = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))
Cross Sectional Area given Time required to Lower Liquid Surface
​ LaTeX ​ Go Cross-Sectional Area of Reservoir = (Time Interval*(2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest)/(2*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)))

Time Required to Lower Liquid Surface using Bazins Formula Formula

​LaTeX ​Go
Time Interval = ((2*Cross-Sectional Area of Reservoir)/(Bazins Coefficient*sqrt(2*Acceleration due to Gravity)))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))
Δt = ((2*AR)/(m*sqrt(2*g)))*(1/sqrt(h2)-1/sqrt(HUpstream))

What does Acceleration due to Gravity mean?

Acceleration due to gravity is defined as the acceleration of a body in free fall under the influence of earth's gravity.

How to Calculate Time Required to Lower Liquid Surface using Bazins Formula?

Time Required to Lower Liquid Surface using Bazins Formula calculator uses Time Interval = ((2*Cross-Sectional Area of Reservoir)/(Bazins Coefficient*sqrt(2*Acceleration due to Gravity)))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)) to calculate the Time Interval, The Time Required to Lower Liquid Surface using Bazins Formula is defined as amount of time taken by lowering water surface from Head1 to Head2. Time Interval is denoted by Δt symbol.

How to calculate Time Required to Lower Liquid Surface using Bazins Formula using this online calculator? To use this online calculator for Time Required to Lower Liquid Surface using Bazins Formula, enter Cross-Sectional Area of Reservoir (AR), Bazins Coefficient (m), Acceleration due to Gravity (g), Head on Downstream of Weir (h2) & Head on Upstream of Weir (HUpstream) and hit the calculate button. Here is how the Time Required to Lower Liquid Surface using Bazins Formula calculation can be explained with given input values -> 1.849125 = ((2*13)/(0.407*sqrt(2*9.8)))*(1/sqrt(5.1)-1/sqrt(10.1)).

FAQ

What is Time Required to Lower Liquid Surface using Bazins Formula?
The Time Required to Lower Liquid Surface using Bazins Formula is defined as amount of time taken by lowering water surface from Head1 to Head2 and is represented as Δt = ((2*AR)/(m*sqrt(2*g)))*(1/sqrt(h2)-1/sqrt(HUpstream)) or Time Interval = ((2*Cross-Sectional Area of Reservoir)/(Bazins Coefficient*sqrt(2*Acceleration due to Gravity)))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)). Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point, Bazins Coefficient is the constant value obtained by Head, The Acceleration due to Gravity is acceleration gained by an object because of gravitational force, Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures & Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.
How to calculate Time Required to Lower Liquid Surface using Bazins Formula?
The Time Required to Lower Liquid Surface using Bazins Formula is defined as amount of time taken by lowering water surface from Head1 to Head2 is calculated using Time Interval = ((2*Cross-Sectional Area of Reservoir)/(Bazins Coefficient*sqrt(2*Acceleration due to Gravity)))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)). To calculate Time Required to Lower Liquid Surface using Bazins Formula, you need Cross-Sectional Area of Reservoir (AR), Bazins Coefficient (m), Acceleration due to Gravity (g), Head on Downstream of Weir (h2) & Head on Upstream of Weir (HUpstream). With our tool, you need to enter the respective value for Cross-Sectional Area of Reservoir, Bazins Coefficient, Acceleration due to Gravity, Head on Downstream of Weir & Head on Upstream of Weir and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Time Interval?
In this formula, Time Interval uses Cross-Sectional Area of Reservoir, Bazins Coefficient, Acceleration due to Gravity, Head on Downstream of Weir & Head on Upstream of Weir. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Time Interval = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))
  • Time Interval = (((2/3)*Cross-Sectional Area of Reservoir)/((8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2)))*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2)))
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