Time in Hours with Base 10 given Fine Sand Calculator

✖Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head [h_d]			+10% -10%
✖Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.ⓘ Depression Head in Well 2 [h_w2]			+10% -10%

✖Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time in Hours with Base 10 given Fine Sand [t]

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Time in Hours with Base 10 given Fine Sand Solution

STEP 0: Pre-Calculation Summary

Formula Used

Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)
t = (2.303/0.5)*log((h_d/h_w2),10)
This formula uses 1 Functions, 3 Variables

Functions Used

log - Logarithmic function is an inverse function to exponentiation., log(Base, Number)

Variables Used

Time - (Measured in Hour) - Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Depression Head - (Measured in Meter) - Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head in Well 2 - (Measured in Meter) - Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

STEP 1: Convert Input(s) to Base Unit

Depression Head: 27 Meter --> 27 Meter No Conversion Required
Depression Head in Well 2: 10 Meter --> 10 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

t = (2.303/0.5)*log((h_d/h_w2),10) --> (2.303/0.5)*log((27/10),10)

Evaluating ... ...

t = 10.6777629061637

STEP 3: Convert Result to Output's Unit

38439.9464621895 Second -->10.6777629061637 Hour (Check conversion here)

FINAL ANSWER

10.6777629061637 ≈ 10.67776 Hour <-- Time

(Calculation completed in 00.020 seconds)

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

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Meerut Institute of Engineering and Technology (MIET), Meerut

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< Recuperate Time Calculators

Time in Hours given Clay Soil

LaTeX Go Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)

Time in Hours given Fine Sand

LaTeX Go Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e)

Time in Hours given Coarse Sand

LaTeX Go Time = log((Depression Head/Depression Head in Well 2),e)

Time in Hours with Base 10 given Fine Sand

LaTeX Go Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)

Time in Hours with Base 10 given Fine Sand Formula

LaTeX Go

Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)
t = (2.303/0.5)*log((h_d/h_w2),10)

What is Fine Soil?

A Fine soil refers to a type of soil with small particle sizes, typically ranging from 0.075 to 0.425 millimeters in diameter. It is part of the soil classification system, where sand is divided into different grades based on particle size. Fine sand is finer than medium and coarse sand but coarser than silt. In the context of wells or groundwater systems, fine sand can influence water flow and percolation rates. If a well is drilled in fine sand, water might flow more slowly compared to wells in coarser materials like gravel.

How to Calculate Time in Hours with Base 10 given Fine Sand?

Time in Hours with Base 10 given Fine Sand calculator uses Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10) to calculate the Time, The Time in Hours with Base 10 given Fine Sand formula is defined as the calculation of the value of time in hours when we have prior information of other parameters used. Time is denoted by t symbol.

How to calculate Time in Hours with Base 10 given Fine Sand using this online calculator? To use this online calculator for Time in Hours with Base 10 given Fine Sand, enter Depression Head (h_d) & Depression Head in Well 2 (h_w2) and hit the calculate button. Here is how the Time in Hours with Base 10 given Fine Sand calculation can be explained with given input values -> 0.002966 = (2.303/0.5)*log((27/10),10).

FAQ

What is Time in Hours with Base 10 given Fine Sand?

The Time in Hours with Base 10 given Fine Sand formula is defined as the calculation of the value of time in hours when we have prior information of other parameters used and is represented as t = (2.303/0.5)*log((h_d/h_w2),10) or Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10). Depression Head is the difference of level of waters table and the water level in the well when pumping stopped & Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

How to calculate Time in Hours with Base 10 given Fine Sand?

The Time in Hours with Base 10 given Fine Sand formula is defined as the calculation of the value of time in hours when we have prior information of other parameters used is calculated using Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10). To calculate Time in Hours with Base 10 given Fine Sand, you need Depression Head (h_d) & Depression Head in Well 2 (h_w2). With our tool, you need to enter the respective value for Depression Head & Depression Head in Well 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Time?

In this formula, Time uses Depression Head & Depression Head in Well 2. We can use 3 other way(s) to calculate the same, which is/are as follows -

Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)
Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e)
Time = log((Depression Head/Depression Head in Well 2),e)

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