Time in Hours given Constant Depression Head and Area of Well Calculator

✖Cross-Sectional Area of Well is the the surface area of the interior opening of the well.ⓘ Cross-Sectional Area of Well [A_csw]			+10% -10%
✖Constant Depression Head is the constant value of head in the well.ⓘ Constant Depression Head [H']			+10% -10%
✖Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head [h_d]			+10% -10%
✖Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.ⓘ Depression Head in Well 2 [h_w2]			+10% -10%
✖Discharge in Well is the rate of flow of a liquid in well.ⓘ Discharge in Well [Q]			+10% -10%

✖Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time in Hours given Constant Depression Head and Area of Well [t]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download Recuperation Test Formulas PDF PDF Image

Time in Hours given Constant Depression Head and Area of Well Solution

STEP 0: Pre-Calculation Summary

Formula Used

Time = (2.303*Cross-Sectional Area of Well*Constant Depression Head*log((Depression Head/Depression Head in Well 2),10))/Discharge in Well
t = (2.303*A_csw*H'*log((h_d/h_w2),10))/Q
This formula uses 1 Functions, 6 Variables

Functions Used

log - Logarithmic function is an inverse function to exponentiation., log(Base, Number)

Variables Used

Time - (Measured in Hour) - Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Cross-Sectional Area of Well - (Measured in Square Meter) - Cross-Sectional Area of Well is the the surface area of the interior opening of the well.
Constant Depression Head - Constant Depression Head is the constant value of head in the well.
Depression Head - (Measured in Meter) - Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head in Well 2 - (Measured in Meter) - Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.
Discharge in Well - (Measured in Cubic Meter per Second) - Discharge in Well is the rate of flow of a liquid in well.

STEP 1: Convert Input(s) to Base Unit

Cross-Sectional Area of Well: 13 Square Meter --> 13 Square Meter No Conversion Required
Constant Depression Head: 0.038 --> No Conversion Required
Depression Head: 27 Meter --> 27 Meter No Conversion Required
Depression Head in Well 2: 10 Meter --> 10 Meter No Conversion Required
Discharge in Well: 0.99 Cubic Meter per Second --> 0.99 Cubic Meter per Second No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

t = (2.303*A_csw*H'*log((h_d/h_w2),10))/Q --> (2.303*13*0.038*log((27/10),10))/0.99

Evaluating ... ...

t = 2.66404791699237

STEP 3: Convert Result to Output's Unit

9590.57250117253 Second -->2.66404791699237 Hour (Check conversion here)

FINAL ANSWER

2.66404791699237 ≈ 2.664048 Hour <-- Time

(Calculation completed in 00.004 seconds)

You are here -

Home » Engineering » Civil » Environmental Engineering » Water Resources Ground Water » Yield of an Open Well » Recuperation Test » Recuperate Time » Time in Hours given Constant Depression Head and Area of Well

Credits

Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

Suraj Kumar has created this Calculator and 2100+ more calculators!

Verified by Ishita Goyal

Meerut Institute of Engineering and Technology (MIET), Meerut

Ishita Goyal has verified this Calculator and 2600+ more calculators!

< Recuperate Time Calculators

Time in Hours given Clay Soil

LaTeX Go Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)

Time in Hours given Fine Sand

LaTeX Go Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e)

Time in Hours given Coarse Sand

LaTeX Go Time = log((Depression Head/Depression Head in Well 2),e)

Time in Hours with Base 10 given Fine Sand

LaTeX Go Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)

Time in Hours given Constant Depression Head and Area of Well Formula

LaTeX Go

Time = (2.303*Cross-Sectional Area of Well*Constant Depression Head*log((Depression Head/Depression Head in Well 2),10))/Discharge in Well
t = (2.303*A_csw*H'*log((h_d/h_w2),10))/Q

What is Cross-Sectional Area?

Cross-sectional area refers to the area of an object or fluid flow, as viewed or cut through at a particular section perpendicular to its length or flow direction. In simpler terms, it's the surface area exposed when an object is sliced across a particular plane. In fluid dynamics and well systems, the cross-sectional area plays a key role in determining flow rates, as it is used in calculating discharge (flow rate). For example, when water flows through a pipe or well, the cross-sectional area of the pipe or well impacts how much water can flow through it at any given time.

How to Calculate Time in Hours given Constant Depression Head and Area of Well?

Time in Hours given Constant Depression Head and Area of Well calculator uses Time = (2.303*Cross-Sectional Area of Well*Constant Depression Head*log((Depression Head/Depression Head in Well 2),10))/Discharge in Well to calculate the Time, The Time in Hours given Constant Depression Head and Area of Well formula is defined as the calculation of the value of time in hours when we have prior information of constant depression head and area of well. Time is denoted by t symbol.

How to calculate Time in Hours given Constant Depression Head and Area of Well using this online calculator? To use this online calculator for Time in Hours given Constant Depression Head and Area of Well, enter Cross-Sectional Area of Well (A_csw), Constant Depression Head (H'), Depression Head (h_d), Depression Head in Well 2 (h_w2) & Discharge in Well (Q) and hit the calculate button. Here is how the Time in Hours given Constant Depression Head and Area of Well calculation can be explained with given input values -> 0.000725 = (2.303*13*0.038*log((27/10),10))/0.99.

FAQ

What is Time in Hours given Constant Depression Head and Area of Well?

The Time in Hours given Constant Depression Head and Area of Well formula is defined as the calculation of the value of time in hours when we have prior information of constant depression head and area of well and is represented as t = (2.303*A_csw*H'*log((h_d/h_w2),10))/Q or Time = (2.303*Cross-Sectional Area of Well*Constant Depression Head*log((Depression Head/Depression Head in Well 2),10))/Discharge in Well. Cross-Sectional Area of Well is the the surface area of the interior opening of the well, Constant Depression Head is the constant value of head in the well, Depression Head is the difference of level of waters table and the water level in the well when pumping stopped, Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped & Discharge in Well is the rate of flow of a liquid in well.

How to calculate Time in Hours given Constant Depression Head and Area of Well?

The Time in Hours given Constant Depression Head and Area of Well formula is defined as the calculation of the value of time in hours when we have prior information of constant depression head and area of well is calculated using Time = (2.303*Cross-Sectional Area of Well*Constant Depression Head*log((Depression Head/Depression Head in Well 2),10))/Discharge in Well. To calculate Time in Hours given Constant Depression Head and Area of Well, you need Cross-Sectional Area of Well (A_csw), Constant Depression Head (H'), Depression Head (h_d), Depression Head in Well 2 (h_w2) & Discharge in Well (Q). With our tool, you need to enter the respective value for Cross-Sectional Area of Well, Constant Depression Head, Depression Head, Depression Head in Well 2 & Discharge in Well and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Time?

In this formula, Time uses Cross-Sectional Area of Well, Constant Depression Head, Depression Head, Depression Head in Well 2 & Discharge in Well. We can use 3 other way(s) to calculate the same, which is/are as follows -

Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)
Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e)
Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)

Home

FREE PDFs

🔍 Search