Time in Hours given Constant Depending upon Soil at Base with Base 10 Calculator

✖Cross-Sectional Area of Well is the the surface area of the interior opening of the well.ⓘ Cross-Sectional Area of Well [A_csw]			+10% -10%
✖Constant depending on the soil at the base of the well.ⓘ Constant [K]			+10% -10%
✖Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head [h_d]			+10% -10%
✖Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.ⓘ Depression Head in Well 2 [h_w2]			+10% -10%

✖Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time in Hours given Constant Depending upon Soil at Base with Base 10 [t]

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Formula

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Time in Hours given Constant Depending upon Soil at Base with Base 10

Formula

t = (\frac{A csw \cdot 2.303}{K}) \cdot \log ((\frac{h d}{h w2}), 10)

Example

13.88109 h = (\frac{13 m² \cdot 2.303}{5.0}) \cdot \log ((\frac{27 m}{10 m}), 10)

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Time in Hours given Constant Depending upon Soil at Base with Base 10 Solution

STEP 0: Pre-Calculation Summary

Formula Used

Time = ((Cross-Sectional Area of Well*2.303)/Constant)*log((Depression Head/Depression Head in Well 2),10)
t = ((A_csw*2.303)/K)*log((h_d/h_w2),10)
This formula uses 1 Functions, 5 Variables

Functions Used

log - Logarithmic function is an inverse function to exponentiation., log(Base, Number)

Variables Used

Time - (Measured in Hour) - Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Cross-Sectional Area of Well - (Measured in Square Meter) - Cross-Sectional Area of Well is the the surface area of the interior opening of the well.
Constant - Constant depending on the soil at the base of the well.
Depression Head - (Measured in Meter) - Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head in Well 2 - (Measured in Meter) - Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

STEP 1: Convert Input(s) to Base Unit

Cross-Sectional Area of Well: 13 Square Meter --> 13 Square Meter No Conversion Required
Constant: 5 --> No Conversion Required
Depression Head: 27 Meter --> 27 Meter No Conversion Required
Depression Head in Well 2: 10 Meter --> 10 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

t = ((A_csw*2.303)/K)*log((h_d/h_w2),10) --> ((13*2.303)/5)*log((27/10),10)

Evaluating ... ...

t = 13.8810917780129

STEP 3: Convert Result to Output's Unit

49971.9304008463 Second -->13.8810917780129 Hour (Check conversion here)

FINAL ANSWER

13.8810917780129 ≈ 13.88109 Hour <-- Time

(Calculation completed in 00.004 seconds)

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< Recuperate Time Calculators

Time in Hours given Clay Soil

Go Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)

Time in Hours given Fine Sand

Go Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e)

Time in Hours with Base 10 given Clay Soil

Go Time = (2.303/0.25)*log((Depression Head/Depression Head in Well 2),10)

Time in Hours with Base 10 given Fine Sand

Go Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)

Time in Hours given Constant Depending upon Soil at Base with Base 10 Formula

Time = ((Cross-Sectional Area of Well*2.303)/Constant)*log((Depression Head/Depression Head in Well 2),10)
t = ((A_csw*2.303)/K)*log((h_d/h_w2),10)

What is Specific Capacity?

Specific Capacity refers to the efficiency of a well in producing water. It is a measure of how much water (in volume) a well can yield per unit of drawdown (or drop in water level) over a specific period of time. The specific capacity is typically expressed in units such as gallons per minute per foot (gpm/ft) or liters per second per meter (L/s/m).

How to Calculate Time in Hours given Constant Depending upon Soil at Base with Base 10?

Time in Hours given Constant Depending upon Soil at Base with Base 10 calculator uses Time = ((Cross-Sectional Area of Well*2.303)/Constant)*log((Depression Head/Depression Head in Well 2),10) to calculate the Time, Time in Hours given Constant Depending upon Soil at Base with Base 10 calculates value of time in hours when we have prior information of other parameters used. Time is denoted by t symbol.

How to calculate Time in Hours given Constant Depending upon Soil at Base with Base 10 using this online calculator? To use this online calculator for Time in Hours given Constant Depending upon Soil at Base with Base 10, enter Cross-Sectional Area of Well (A_csw), Constant (K), Depression Head (h_d) & Depression Head in Well 2 (h_w2) and hit the calculate button. Here is how the Time in Hours given Constant Depending upon Soil at Base with Base 10 calculation can be explained with given input values -> 0.003856 = ((13*2.303)/5)*log((27/10),10).

FAQ

What is Time in Hours given Constant Depending upon Soil at Base with Base 10?

Time in Hours given Constant Depending upon Soil at Base with Base 10 calculates value of time in hours when we have prior information of other parameters used and is represented as t = ((A_csw*2.303)/K)*log((h_d/h_w2),10) or Time = ((Cross-Sectional Area of Well*2.303)/Constant)*log((Depression Head/Depression Head in Well 2),10). Cross-Sectional Area of Well is the the surface area of the interior opening of the well, Constant depending on the soil at the base of the well, Depression Head is the difference of level of waters table and the water level in the well when pumping stopped & Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

How to calculate Time in Hours given Constant Depending upon Soil at Base with Base 10?

Time in Hours given Constant Depending upon Soil at Base with Base 10 calculates value of time in hours when we have prior information of other parameters used is calculated using Time = ((Cross-Sectional Area of Well*2.303)/Constant)*log((Depression Head/Depression Head in Well 2),10). To calculate Time in Hours given Constant Depending upon Soil at Base with Base 10, you need Cross-Sectional Area of Well (A_csw), Constant (K), Depression Head (h_d) & Depression Head in Well 2 (h_w2). With our tool, you need to enter the respective value for Cross-Sectional Area of Well, Constant, Depression Head & Depression Head in Well 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Time?

In this formula, Time uses Cross-Sectional Area of Well, Constant, Depression Head & Depression Head in Well 2. We can use 3 other way(s) to calculate the same, which is/are as follows -

Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)
Time = (2.303/0.25)*log((Depression Head/Depression Head in Well 2),10)
Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e)

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