Time in Hours given Clay Soil Calculator

✖Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head [h_d]			+10% -10%
✖Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.ⓘ Depression Head in Well 2 [h_w2]			+10% -10%

✖Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time in Hours given Clay Soil [t]

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Time in Hours given Clay Soil Solution

STEP 0: Pre-Calculation Summary

Formula Used

Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)
t = (1/0.25)*log((h_d/h_w2),e)
This formula uses 1 Constants, 1 Functions, 3 Variables

Constants Used

e - Napier's constant Value Taken As 2.71828182845904523536028747135266249

Functions Used

log - Logarithmic function is an inverse function to exponentiation., log(Base, Number)

Variables Used

Time - (Measured in Hour) - Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Depression Head - (Measured in Meter) - Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head in Well 2 - (Measured in Meter) - Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

STEP 1: Convert Input(s) to Base Unit

Depression Head: 27 Meter --> 27 Meter No Conversion Required
Depression Head in Well 2: 10 Meter --> 10 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

t = (1/0.25)*log((h_d/h_w2),e) --> (1/0.25)*log((27/10),e)

Evaluating ... ...

t = 4.02717629979865

STEP 3: Convert Result to Output's Unit

14497.8346792751 Second -->4.02717629979865 Hour (Check conversion here)

FINAL ANSWER

4.02717629979865 ≈ 4.027176 Hour <-- Time

(Calculation completed in 00.004 seconds)

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

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Verified by Ishita Goyal

Meerut Institute of Engineering and Technology (MIET), Meerut

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< Recuperate Time Calculators

Time in Hours given Clay Soil

LaTeX Go Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)

Time in Hours given Fine Sand

LaTeX Go Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e)

Time in Hours given Coarse Sand

LaTeX Go Time = log((Depression Head/Depression Head in Well 2),e)

Time in Hours with Base 10 given Fine Sand

LaTeX Go Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)

Time in Hours given Clay Soil Formula

LaTeX Go

Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e)
t = (1/0.25)*log((h_d/h_w2),e)

What is Clay Soil ?

Clay soil is defined by its small particle size, high plasticity, excellent nutrient retention, and poor drainage. While it can be fertile and valuable for agricultural and construction purposes, its characteristics can also pose challenges in managing water and supporting healthy plant growth. Understanding clay soil's properties is essential for effective land management and agricultural practices.

How to Calculate Time in Hours given Clay Soil?

Time in Hours given Clay Soil calculator uses Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e) to calculate the Time, The Time in Hours given Clay Soil formula is defined as the calculation of the value of time in hours when we have prior information of soil available. Time is denoted by t symbol.

How to calculate Time in Hours given Clay Soil using this online calculator? To use this online calculator for Time in Hours given Clay Soil, enter Depression Head (h_d) & Depression Head in Well 2 (h_w2) and hit the calculate button. Here is how the Time in Hours given Clay Soil calculation can be explained with given input values -> 0.001119 = (1/0.25)*log((27/10),e).

FAQ

What is Time in Hours given Clay Soil?

The Time in Hours given Clay Soil formula is defined as the calculation of the value of time in hours when we have prior information of soil available and is represented as t = (1/0.25)*log((h_d/h_w2),e) or Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e). Depression Head is the difference of level of waters table and the water level in the well when pumping stopped & Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

How to calculate Time in Hours given Clay Soil?

The Time in Hours given Clay Soil formula is defined as the calculation of the value of time in hours when we have prior information of soil available is calculated using Time = (1/0.25)*log((Depression Head/Depression Head in Well 2),e). To calculate Time in Hours given Clay Soil, you need Depression Head (h_d) & Depression Head in Well 2 (h_w2). With our tool, you need to enter the respective value for Depression Head & Depression Head in Well 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Time?

In this formula, Time uses Depression Head & Depression Head in Well 2. We can use 3 other way(s) to calculate the same, which is/are as follows -

Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e)
Time = (2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)
Time = log((Depression Head/Depression Head in Well 2),e)

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