Tide-generating Attractive Force Potential for Sun Solution

STEP 0: Pre-Calculation Summary
Formula Used
Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of Point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the Distance of Point)/Distance^2))
Vs = (f*Msun)*((1/rS/MX)-(1/rs)-(RM*cos(θm/s)/rs^2))
This formula uses 1 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Attractive Force Potentials for Sun - Attractive Force Potentials for Sun is referred to the gravitational force exerted by the Sun on an object and can be described by the gravitational potential.
Universal Constant - Universal Constant is a physical constant that is thought to be universal in its application in terms of Radius of the Earth and Acceleration of Gravity.
Mass of the Sun - (Measured in Kilogram) - Mass of the Sun defined as the total amount of matter that the Sun contains. This includes all of its components, such as hydrogen, helium, and trace amounts of heavier elements.
Distance of Point - (Measured in Meter) - Distance of Point refers to the point located on the surface of the Earth to the center of the Sun or the Moon.
Distance - (Measured in Meter) - Distance from the center of the Earth to the center of the Sun is called an astronomical unit (AU). One astronomical unit is approximately 149,597,870.7 kilometers.
Mean Radius of the Earth - (Measured in Meter) - Mean Radius of the Earth is defined as the arithmetic average of the Earth's equatorial and polar radii.
Angle made by the Distance of Point - (Measured in Radian) - Angle made by the Distance of Point referred to the angle between the line connecting the centers of the Earth and the Moon and the line perpendicular to the Earth's surface at the point of interest.
STEP 1: Convert Input(s) to Base Unit
Universal Constant: 2 --> No Conversion Required
Mass of the Sun: 1.989E+30 Kilogram --> 1.989E+30 Kilogram No Conversion Required
Distance of Point: 256 Kilometer --> 256000 Meter (Check conversion ​here)
Distance: 150000000 Kilometer --> 150000000000 Meter (Check conversion ​here)
Mean Radius of the Earth: 6371 Kilometer --> 6371000 Meter (Check conversion ​here)
Angle made by the Distance of Point: 12.5 Degree --> 0.21816615649925 Radian (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vs = (f*Msun)*((1/rS/MX)-(1/rs)-(RM*cos(θm/s)/rs^2)) --> (2*1.989E+30)*((1/256000)-(1/150000000000)-(6371000*cos(0.21816615649925)/150000000000^2))
Evaluating ... ...
Vs = 1.55390359789003E+25
STEP 3: Convert Result to Output's Unit
1.55390359789003E+25 --> No Conversion Required
FINAL ANSWER
1.55390359789003E+25 1.6E+25 <-- Attractive Force Potentials for Sun
(Calculation completed in 00.004 seconds)

Credits

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Created by Mithila Muthamma PA
Coorg Institute of Technology (CIT), Coorg
Mithila Muthamma PA has created this Calculator and 2000+ more calculators!
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Verified by M Naveen
National Institute of Technology (NIT), Warangal
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Attractive Force Potentials Calculators

Attractive Force Potentials per unit Mass for Moon
​ LaTeX ​ Go Attractive Force Potentials for Moon = (Universal Constant*Mass of the Moon)/Distance of Point
Mass of Moon given Attractive Force Potentials
​ LaTeX ​ Go Mass of the Moon = (Attractive Force Potentials for Moon*Distance of Point)/Universal Constant
Attractive Force Potentials per unit Mass for Sun
​ LaTeX ​ Go Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of Point
Mass of Sun given Attractive Force Potentials
​ LaTeX ​ Go Mass of the Sun = (Attractive Force Potentials for Sun*Distance of Point)/Universal Constant

Tide-generating Attractive Force Potential for Sun Formula

​LaTeX ​Go
Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of Point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the Distance of Point)/Distance^2))
Vs = (f*Msun)*((1/rS/MX)-(1/rs)-(RM*cos(θm/s)/rs^2))

What do you mean by Tidal Force?

The Tidal Force is a gravitational effect that stretches a body along the line towards the center of mass of another body due to a gradient (difference in strength) in gravitational field from the other body; it is responsible for diverse phenomena, including tides, tidal locking, breaking apart of celestial bodies.

How to Calculate Tide-generating Attractive Force Potential for Sun?

Tide-generating Attractive Force Potential for Sun calculator uses Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of Point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the Distance of Point)/Distance^2)) to calculate the Attractive Force Potentials for Sun, The Tide-generating Attractive Force Potential for Sun formula is defined as the earth's surface is result from combination of force of gravitation exerted by moon (and sun) upon earth; and centrifugal forces produced by revolutions of earth and moon (and earth and sun) around their common center-of-gravity. Attractive Force Potentials for Sun is denoted by Vs symbol.

How to calculate Tide-generating Attractive Force Potential for Sun using this online calculator? To use this online calculator for Tide-generating Attractive Force Potential for Sun, enter Universal Constant (f), Mass of the Sun (Msun), Distance of Point (rS/MX), Distance (rs), Mean Radius of the Earth (RM) & Angle made by the Distance of Point m/s) and hit the calculate button. Here is how the Tide-generating Attractive Force Potential for Sun calculation can be explained with given input values -> 1.6E+25 = (2*1.989E+30)*((1/256000)-(1/150000000000)-(6371000*cos(0.21816615649925)/150000000000^2)).

FAQ

What is Tide-generating Attractive Force Potential for Sun?
The Tide-generating Attractive Force Potential for Sun formula is defined as the earth's surface is result from combination of force of gravitation exerted by moon (and sun) upon earth; and centrifugal forces produced by revolutions of earth and moon (and earth and sun) around their common center-of-gravity and is represented as Vs = (f*Msun)*((1/rS/MX)-(1/rs)-(RM*cos(θm/s)/rs^2)) or Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of Point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the Distance of Point)/Distance^2)). Universal Constant is a physical constant that is thought to be universal in its application in terms of Radius of the Earth and Acceleration of Gravity, Mass of the Sun defined as the total amount of matter that the Sun contains. This includes all of its components, such as hydrogen, helium, and trace amounts of heavier elements, Distance of Point refers to the point located on the surface of the Earth to the center of the Sun or the Moon, Distance from the center of the Earth to the center of the Sun is called an astronomical unit (AU). One astronomical unit is approximately 149,597,870.7 kilometers, Mean Radius of the Earth is defined as the arithmetic average of the Earth's equatorial and polar radii & Angle made by the Distance of Point referred to the angle between the line connecting the centers of the Earth and the Moon and the line perpendicular to the Earth's surface at the point of interest.
How to calculate Tide-generating Attractive Force Potential for Sun?
The Tide-generating Attractive Force Potential for Sun formula is defined as the earth's surface is result from combination of force of gravitation exerted by moon (and sun) upon earth; and centrifugal forces produced by revolutions of earth and moon (and earth and sun) around their common center-of-gravity is calculated using Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of Point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the Distance of Point)/Distance^2)). To calculate Tide-generating Attractive Force Potential for Sun, you need Universal Constant (f), Mass of the Sun (Msun), Distance of Point (rS/MX), Distance (rs), Mean Radius of the Earth (RM) & Angle made by the Distance of Point m/s). With our tool, you need to enter the respective value for Universal Constant, Mass of the Sun, Distance of Point, Distance, Mean Radius of the Earth & Angle made by the Distance of Point and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Attractive Force Potentials for Sun?
In this formula, Attractive Force Potentials for Sun uses Universal Constant, Mass of the Sun, Distance of Point, Distance, Mean Radius of the Earth & Angle made by the Distance of Point. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of Point
  • Attractive Force Potentials for Sun = Universal Constant*Mass of the Sun*(Mean Radius of the Earth^2/Distance^3)*Harmonic Polynomial Expansion Terms for Sun
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