Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Calculator

✖Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.ⓘ Reduced Pressure [P_r]			+10% -10%
✖Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.ⓘ Critical Pressure of Real Gas [P'_c]			+10% -10%
✖Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter a [a]			+10% -10%
✖Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.ⓘ Reduced Molar Volume for Real Gas [V'_m,r]			+10% -10%
✖Critical Molar Volume is the volume occupied by gas at critical temperature and pressure per mole.ⓘ Critical Molar Volume [V_m,c]			+10% -10%
✖Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter c [c]			+10% -10%
✖Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter b for Real Gas [b']			+10% -10%

✖Temperature given CE is the degree or intensity of heat present in a substance or object.ⓘ Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters [T_CE]

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Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Solution

STEP 0: Pre-Calculation Summary

Formula Used

Temperature given CE = ((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R])
T_CE = ((P_r*P'_c)+(a/((((V'_m,r*V_m,c)+c)^2))))*(((V'_m,r*V_m,c)-b')/[R])
This formula uses 1 Constants, 8 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Temperature given CE - (Measured in Kelvin) - Temperature given CE is the degree or intensity of heat present in a substance or object.
Reduced Pressure - Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.
Critical Pressure of Real Gas - (Measured in Pascal) - Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.
Clausius Parameter a - Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Reduced Molar Volume for Real Gas - Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.
Critical Molar Volume - (Measured in Cubic Meter per Mole) - Critical Molar Volume is the volume occupied by gas at critical temperature and pressure per mole.
Clausius Parameter c - Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Clausius Parameter b for Real Gas - Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

STEP 1: Convert Input(s) to Base Unit

Reduced Pressure: 0.8 --> No Conversion Required
Critical Pressure of Real Gas: 4600000 Pascal --> 4600000 Pascal No Conversion Required
Clausius Parameter a: 0.1 --> No Conversion Required
Reduced Molar Volume for Real Gas: 8.96 --> No Conversion Required
Critical Molar Volume: 11.5 Cubic Meter per Mole --> 11.5 Cubic Meter per Mole No Conversion Required
Clausius Parameter c: 0.0002 --> No Conversion Required
Clausius Parameter b for Real Gas: 0.00243 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

T_CE = ((P_r*P'_c)+(a/((((V'_m,r*V_m,c)+c)^2))))*(((V'_m,r*V_m,c)-b')/[R]) --> ((0.8*4600000)+(0.1/((((8.96*11.5)+0.0002)^2))))*(((8.96*11.5)-0.00243)/[R])

Evaluating ... ...

T_CE = 45604662.0226662

STEP 3: Convert Result to Output's Unit

45604662.0226662 Kelvin --> No Conversion Required

FINAL ANSWER

45604662.0226662 ≈ 4.6E+7 Kelvin <-- Temperature given CE

(Calculation completed in 00.020 seconds)

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< Pressure and Temperature of Real Gas Calculators

Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters

LaTeX Go Pressure = (([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas))-(Clausius Parameter a/((Reduced Temperature*Critical Temperature For Clausius Model)*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2)))

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters

LaTeX Go Temperature given CE = ((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R])

Pressure of Real Gas using Clausius Equation

LaTeX Go Pressure = (([R]*Temperature of Real Gas)/(Molar Volume-Clausius Parameter b for Real Gas))-(Clausius Parameter a/(Temperature of Real Gas*((Molar Volume+Clausius Parameter c)^2)))

Temperature of Real Gas using Clausius Equation

LaTeX Go Temperature given CE = (Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R])

< Important Formulae on Clausius Model of Real Gas Calculators

Actual Pressure of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

LaTeX Go Pressure given b = (([R]*(Temperature of Real Gas/Reduced Temperature))/(4*((Volume of Real Gas/Reduced Volume)-Clausius Parameter b for Real Gas)))*Reduced Pressure

Actual Pressure of Real Gas given Clausius Parameter c, Reduced and Actual Parameters

LaTeX Go Pressure given c = ((3*[R]*(Temperature of Real Gas/Reduced Temperature))/(8*(Clausius Parameter c+(Volume of Real Gas/Reduced Volume))))*Reduced Pressure

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters

LaTeX Go Temperature given RP = (((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))*Reduced Temperature

Actual Pressure of Real Gas given Clausius Parameter a, Reduced and Critical Parameters

LaTeX Go Pressure given a = ((27*([R]^2)*(Critical Temperature For Clausius Model^3))/(64*Clausius Parameter a))*Reduced Pressure

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula

LaTeX Go

What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters calculator uses Temperature given CE = ((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]) to calculate the Temperature given CE, The Temperature of real gas using Clausius equation given reduced and critical parameters formula is defined as the degree or intensity of heat present in a substance or object. Temperature given CE is denoted by T_CE symbol.

How to calculate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters using this online calculator? To use this online calculator for Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters, enter Reduced Pressure (P_r), Critical Pressure of Real Gas (P'_c), Clausius Parameter a (a), Reduced Molar Volume for Real Gas (V'_m,r), Critical Molar Volume (V_m,c), Clausius Parameter c (c) & Clausius Parameter b for Real Gas (b') and hit the calculate button. Here is how the Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters calculation can be explained with given input values -> 5.7E+7 = ((0.8*4600000)+(0.1/((((8.96*11.5)+0.0002)^2))))*(((8.96*11.5)-0.00243)/[R]).

FAQ

What is Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

The Temperature of real gas using Clausius equation given reduced and critical parameters formula is defined as the degree or intensity of heat present in a substance or object and is represented as T_CE = ((P_r*P'_c)+(a/((((V'_m,r*V_m,c)+c)^2))))*(((V'_m,r*V_m,c)-b')/[R]) or Temperature given CE = ((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]). Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless, Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature, Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas, Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole, Critical Molar Volume is the volume occupied by gas at critical temperature and pressure per mole, Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas & Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

How to calculate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

The Temperature of real gas using Clausius equation given reduced and critical parameters formula is defined as the degree or intensity of heat present in a substance or object is calculated using Temperature given CE = ((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]). To calculate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters, you need Reduced Pressure (P_r), Critical Pressure of Real Gas (P'_c), Clausius Parameter a (a), Reduced Molar Volume for Real Gas (V'_m,r), Critical Molar Volume (V_m,c), Clausius Parameter c (c) & Clausius Parameter b for Real Gas (b'). With our tool, you need to enter the respective value for Reduced Pressure, Critical Pressure of Real Gas, Clausius Parameter a, Reduced Molar Volume for Real Gas, Critical Molar Volume, Clausius Parameter c & Clausius Parameter b for Real Gas and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Temperature given CE?

In this formula, Temperature given CE uses Reduced Pressure, Critical Pressure of Real Gas, Clausius Parameter a, Reduced Molar Volume for Real Gas, Critical Molar Volume, Clausius Parameter c & Clausius Parameter b for Real Gas. We can use 2 other way(s) to calculate the same, which is/are as follows -

Temperature given CE = (Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R])
Temperature given CE = (Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R])

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