✖The Area of Triangle is the amount of region or space occupied by the Triangle.ⓘ Area of Triangle [A]			+10% -10%
✖The Side A of Triangle is the length of the side A, of the three sides of the triangle. In other words, the side A of the Triangle is the side opposite to the angle A.ⓘ Side A of Triangle [S_a]			+10% -10%
✖The Side C of Triangle is the length of the side C of the three sides. In other words, side C of the Triangle is the side opposite to angle C.ⓘ Side C of Triangle [S_c]			+10% -10%
✖Cos (B/2) is the value of the trigonometric cosine function of half of the given angle B of the triangle.ⓘ Cos (B/2) [cos_(B/2)]			+10% -10%

✖Sin (B/2) is the value of the trigonometric sine function of half of the given angle A of the triangle.ⓘ Sin (B/2) given Sides A and C and Cos (B/2) [sin_(B/2)]

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Formula

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Sin (B/2) given Sides A and C and Cos (B/2)

Formula

`"sin"_{"(B/2)"} = "A"/("S"_{"a"}*"S"_{"c"}*"cos"_{"(B/2)"})`

Example

`"0.346113"="65m²"/("10m"*"20m"*"0.939")`

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Sin (B/2) given Sides A and C and Cos (B/2) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Sin (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Cos (B/2))
sin_(B/2) = A/(S_a*S_c*cos_(B/2))
This formula uses 5 Variables

Variables Used

Sin (B/2) - Sin (B/2) is the value of the trigonometric sine function of half of the given angle A of the triangle.
Area of Triangle - (Measured in Square Meter) - The Area of Triangle is the amount of region or space occupied by the Triangle.
Side A of Triangle - (Measured in Meter) - The Side A of Triangle is the length of the side A, of the three sides of the triangle. In other words, the side A of the Triangle is the side opposite to the angle A.
Side C of Triangle - (Measured in Meter) - The Side C of Triangle is the length of the side C of the three sides. In other words, side C of the Triangle is the side opposite to angle C.
Cos (B/2) - Cos (B/2) is the value of the trigonometric cosine function of half of the given angle B of the triangle.

STEP 1: Convert Input(s) to Base Unit

Area of Triangle: 65 Square Meter --> 65 Square Meter No Conversion Required
Side A of Triangle: 10 Meter --> 10 Meter No Conversion Required
Side C of Triangle: 20 Meter --> 20 Meter No Conversion Required
Cos (B/2): 0.939 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

sin_(B/2) = A/(S_a*S_c*cos_(B/2)) --> 65/(10*20*0.939)

Evaluating ... ...

sin_(B/2) = 0.346112886048988

STEP 3: Convert Result to Output's Unit

0.346112886048988 --> No Conversion Required

FINAL ANSWER

0.346112886048988 ≈ 0.346113 <-- Sin (B/2)

(Calculation completed in 00.004 seconds)

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< 9 Trigonometric Ratios of Half Angles using Area of the Triangle Calculators

Sin (A/2) given Sides B and C and Sec (A/2)

Go Sin (A/2) = (Area of Triangle*Sec (A/2))/(Side B of Triangle*Side C of Triangle)

Sin (B/2) given Sides A and C and Sec (B/2)

Go Sin (B/2) = (Area of Triangle*Sec (B/2))/(Side A of Triangle*Side C of Triangle)

Sin (C/2) given Sides A and B and Sec (C/2)

Go Sin (C/2) = (Area of Triangle*Sec (C/2))/(Side A of Triangle*Side B of Triangle)

Sin (A/2) given Sides B and C and Cos (A/2)

Go Sin (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Cos (A/2))

Sin (B/2) given Sides A and C and Cos (B/2)

Go Sin (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Cos (B/2))

Sin (C/2) given Sides A and B and Cos (C/2)

Go Sin (C/2) = Area of Triangle/(Side A of Triangle*Side B of Triangle*Cos (C/2))

Cos (A/2) given Sides B and C and Sin (A/2)

Go Cos (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Sin (A/2))

Cos (B/2) given Sides A and C and Sin (B/2)

Go Cos (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Sin (B/2))

Cos (C/2) given Sides A and B and Sin (C/2)

Go Cos (C/2) = Area of Triangle/(Side A of Triangle*Side B of Triangle*Sin (C/2))

Sin (B/2) given Sides A and C and Cos (B/2) Formula

Sin (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Cos (B/2))
sin_(B/2) = A/(S_a*S_c*cos_(B/2))

What is a Triangle?

The Triangle is the type of polygon, which have three sides and three vertices. This is a two-dimensional figure with three straight sides. A triangle is considered a 3-sided polygon. The sum of all the three angles of a triangle is equal to 180°. The triangle is contained in a single plane. Based on its sides and angle measurement, the triangle has six types.

How to Calculate Sin (B/2) given Sides A and C and Cos (B/2)?

Sin (B/2) given Sides A and C and Cos (B/2) calculator uses Sin (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Cos (B/2)) to calculate the Sin (B/2), The Sin (B/2) given Sides A and C and Cos (B/2) formula is defined as value of sin B/2 using area of the triangle, the sides A & C and the trigonometric half ratio Cos B/2. Sin (B/2) is denoted by sin_(B/2) symbol.

How to calculate Sin (B/2) given Sides A and C and Cos (B/2) using this online calculator? To use this online calculator for Sin (B/2) given Sides A and C and Cos (B/2), enter Area of Triangle (A), Side A of Triangle (S_a), Side C of Triangle (S_c) & Cos (B/2) (cos_(B/2)) and hit the calculate button. Here is how the Sin (B/2) given Sides A and C and Cos (B/2) calculation can be explained with given input values -> 0.346113 = 65/(10*20*0.939).

FAQ

What is Sin (B/2) given Sides A and C and Cos (B/2)?

The Sin (B/2) given Sides A and C and Cos (B/2) formula is defined as value of sin B/2 using area of the triangle, the sides A & C and the trigonometric half ratio Cos B/2 and is represented as sin_(B/2) = A/(S_a*S_c*cos_(B/2)) or Sin (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Cos (B/2)). The Area of Triangle is the amount of region or space occupied by the Triangle, The Side A of Triangle is the length of the side A, of the three sides of the triangle. In other words, the side A of the Triangle is the side opposite to the angle A, The Side C of Triangle is the length of the side C of the three sides. In other words, side C of the Triangle is the side opposite to angle C & Cos (B/2) is the value of the trigonometric cosine function of half of the given angle B of the triangle.

How to calculate Sin (B/2) given Sides A and C and Cos (B/2)?

The Sin (B/2) given Sides A and C and Cos (B/2) formula is defined as value of sin B/2 using area of the triangle, the sides A & C and the trigonometric half ratio Cos B/2 is calculated using Sin (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Cos (B/2)). To calculate Sin (B/2) given Sides A and C and Cos (B/2), you need Area of Triangle (A), Side A of Triangle (S_a), Side C of Triangle (S_c) & Cos (B/2) (cos_(B/2)). With our tool, you need to enter the respective value for Area of Triangle, Side A of Triangle, Side C of Triangle & Cos (B/2) and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Sin (B/2)?

In this formula, Sin (B/2) uses Area of Triangle, Side A of Triangle, Side C of Triangle & Cos (B/2). We can use 1 other way(s) to calculate the same, which is/are as follows -

Sin (B/2) = (Area of Triangle*Sec (B/2))/(Side A of Triangle*Side C of Triangle)

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