Short Diagonal of Octagon given Perimeter Calculator

✖The Perimeter of Octagon is the total length of all the boundary lines of the Regular Octagon.ⓘ Perimeter of Octagon [P]

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✖The Short Diagonal of Octagon is the length of smallest diagonals or the line joining a vertex and any one of the vertices that coming next to the adjacent vertices of the first vertex of the Octagon.ⓘ Short Diagonal of Octagon given Perimeter [d_Short]

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Short Diagonal of Octagon given Perimeter Solution

STEP 0: Pre-Calculation Summary

Formula Used

Short Diagonal of Octagon = sqrt(2+sqrt(2))*Perimeter of Octagon/8
d_Short = sqrt(2+sqrt(2))*P/8
This formula uses 1 Functions, 2 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Short Diagonal of Octagon - (Measured in Meter) - The Short Diagonal of Octagon is the length of smallest diagonals or the line joining a vertex and any one of the vertices that coming next to the adjacent vertices of the first vertex of the Octagon.
Perimeter of Octagon - (Measured in Meter) - The Perimeter of Octagon is the total length of all the boundary lines of the Regular Octagon.

STEP 1: Convert Input(s) to Base Unit

Perimeter of Octagon: 80 Meter --> 80 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

d_Short = sqrt(2+sqrt(2))*P/8 --> sqrt(2+sqrt(2))*80/8

Evaluating ... ...

d_Short = 18.4775906502257

STEP 3: Convert Result to Output's Unit

18.4775906502257 Meter --> No Conversion Required

FINAL ANSWER

18.4775906502257 ≈ 18.47759 Meter <-- Short Diagonal of Octagon

(Calculation completed in 00.006 seconds)

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Created by Mona Gladys

St Joseph's College (SJC), Bengaluru

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Walchand College of Engineering (WCE), Sangli

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< Short Diagonal of Octagon Calculators

Short Diagonal of Octagon given Medium Diagonal

LaTeX Go Short Diagonal of Octagon = sqrt(2-sqrt(2))*Medium Diagonal of Octagon

Short Diagonal of Octagon

LaTeX Go Short Diagonal of Octagon = sqrt(2+sqrt(2))*Edge Length of Octagon

Short Diagonal of Octagon given Height

LaTeX Go Short Diagonal of Octagon = sqrt(2-sqrt(2))*Height of Octagon

Short Diagonal of Octagon given Long Diagonal

LaTeX Go Short Diagonal of Octagon = Long Diagonal of Octagon/(sqrt(2))

Short Diagonal of Octagon given Perimeter Formula

LaTeX Go

Short Diagonal of Octagon = sqrt(2+sqrt(2))*Perimeter of Octagon/8
d_Short = sqrt(2+sqrt(2))*P/8

What is an Octagon?

Octagon is a polygon in geometry, which has 8 sides and 8 angles. That means the number of vertices is 8 and the number of edges is 8. All the sides are joined with each other end-to-end to form a shape. These sides are in a straight line form; they are not curved or disjoint with each other. Each interior angle of a regular octagon is 135° and each exterior angle will be 45°.

How to Calculate Short Diagonal of Octagon given Perimeter?

Short Diagonal of Octagon given Perimeter calculator uses Short Diagonal of Octagon = sqrt(2+sqrt(2))*Perimeter of Octagon/8 to calculate the Short Diagonal of Octagon, The Short Diagonal of Octagon given Perimeter formula is defined as the length of the smallest diagonals or the line joining a vertex and any of the vertices that come next to the adjacent vertices of the first vertex of the Octagon and calculated using the perimeter of the Octagon. Short Diagonal of Octagon is denoted by d_Short symbol.

How to calculate Short Diagonal of Octagon given Perimeter using this online calculator? To use this online calculator for Short Diagonal of Octagon given Perimeter, enter Perimeter of Octagon (P) and hit the calculate button. Here is how the Short Diagonal of Octagon given Perimeter calculation can be explained with given input values -> 18.47759 = sqrt(2+sqrt(2))*80/8.

FAQ

What is Short Diagonal of Octagon given Perimeter?

The Short Diagonal of Octagon given Perimeter formula is defined as the length of the smallest diagonals or the line joining a vertex and any of the vertices that come next to the adjacent vertices of the first vertex of the Octagon and calculated using the perimeter of the Octagon and is represented as d_Short = sqrt(2+sqrt(2))*P/8 or Short Diagonal of Octagon = sqrt(2+sqrt(2))*Perimeter of Octagon/8. The Perimeter of Octagon is the total length of all the boundary lines of the Regular Octagon.

How to calculate Short Diagonal of Octagon given Perimeter?

The Short Diagonal of Octagon given Perimeter formula is defined as the length of the smallest diagonals or the line joining a vertex and any of the vertices that come next to the adjacent vertices of the first vertex of the Octagon and calculated using the perimeter of the Octagon is calculated using Short Diagonal of Octagon = sqrt(2+sqrt(2))*Perimeter of Octagon/8. To calculate Short Diagonal of Octagon given Perimeter, you need Perimeter of Octagon (P). With our tool, you need to enter the respective value for Perimeter of Octagon and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Short Diagonal of Octagon?

In this formula, Short Diagonal of Octagon uses Perimeter of Octagon. We can use 3 other way(s) to calculate the same, which is/are as follows -

Short Diagonal of Octagon = sqrt(2+sqrt(2))*Edge Length of Octagon
Short Diagonal of Octagon = Long Diagonal of Octagon/(sqrt(2))
Short Diagonal of Octagon = sqrt(2-sqrt(2))*Medium Diagonal of Octagon

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