Series Field Copper Loss in DC Generator Solution

STEP 0: Pre-Calculation Summary
Formula Used
Series Field Loss = Series Field Current^2*Series Field Resistance
Pse = Ise^2*Rse
This formula uses 3 Variables
Variables Used
Series Field Loss - (Measured in Watt) - Series Field Loss is defined as the power dissipated by the series field of a generator due to current flowing through it.
Series Field Current - (Measured in Ampere) - Series field current is the current due to series field windings in a dc generator.
Series Field Resistance - (Measured in Ohm) - Series field resistance refers to the electrical resistance of the field winding in a series-wound DC motor or generator.
STEP 1: Convert Input(s) to Base Unit
Series Field Current: 0.832 Ampere --> 0.832 Ampere No Conversion Required
Series Field Resistance: 123.5 Ohm --> 123.5 Ohm No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Pse = Ise^2*Rse --> 0.832^2*123.5
Evaluating ... ...
Pse = 85.489664
STEP 3: Convert Result to Output's Unit
85.489664 Watt --> No Conversion Required
FINAL ANSWER
85.489664 85.48966 Watt <-- Series Field Loss
(Calculation completed in 00.004 seconds)

Credits

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Created by Urvi Rathod
Vishwakarma Government Engineering College (VGEC), Ahmedabad
Urvi Rathod has created this Calculator and 1500+ more calculators!
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Losses Calculators

Mechanical Losses of Series DC Generator given Converted Power
​ LaTeX ​ Go Mechanical Losses = Input Power-Core Loss-Stray Loss-Converted Power
Series Field Copper Loss in DC Generator
​ LaTeX ​ Go Series Field Loss = Series Field Current^2*Series Field Resistance

Series Field Copper Loss in DC Generator Formula

​LaTeX ​Go
Series Field Loss = Series Field Current^2*Series Field Resistance
Pse = Ise^2*Rse

What is copper loss?

Copper loss is the term often given to heat produced by electrical currents in the conductors of transformer windings, or other electrical devices. Copper losses are an undesirable transfer of energy, as are core losses, which result from induced currents in adjacent components.

How to Calculate Series Field Copper Loss in DC Generator?

Series Field Copper Loss in DC Generator calculator uses Series Field Loss = Series Field Current^2*Series Field Resistance to calculate the Series Field Loss, Series Field Copper Loss in DC Generator is variable and depends upon the amount of loading of the machine. Copper loss is the term often given to heat produced by electrical currents. Series Field Loss is denoted by Pse symbol.

How to calculate Series Field Copper Loss in DC Generator using this online calculator? To use this online calculator for Series Field Copper Loss in DC Generator, enter Series Field Current (Ise) & Series Field Resistance (Rse) and hit the calculate button. Here is how the Series Field Copper Loss in DC Generator calculation can be explained with given input values -> 85.48966 = 0.832^2*123.5.

FAQ

What is Series Field Copper Loss in DC Generator?
Series Field Copper Loss in DC Generator is variable and depends upon the amount of loading of the machine. Copper loss is the term often given to heat produced by electrical currents and is represented as Pse = Ise^2*Rse or Series Field Loss = Series Field Current^2*Series Field Resistance. Series field current is the current due to series field windings in a dc generator & Series field resistance refers to the electrical resistance of the field winding in a series-wound DC motor or generator.
How to calculate Series Field Copper Loss in DC Generator?
Series Field Copper Loss in DC Generator is variable and depends upon the amount of loading of the machine. Copper loss is the term often given to heat produced by electrical currents is calculated using Series Field Loss = Series Field Current^2*Series Field Resistance. To calculate Series Field Copper Loss in DC Generator, you need Series Field Current (Ise) & Series Field Resistance (Rse). With our tool, you need to enter the respective value for Series Field Current & Series Field Resistance and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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