Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter Calculator

✖Eccentricity of Hyperbola is the ratio of distances of any point on the Hyperbola from focus and the directrix, or it is the ratio of linear eccentricity and semi transverse axis of the Hyperbola.ⓘ Eccentricity of Hyperbola [e]			+10% -10%
✖Focal Parameter of Hyperbola is the shortest distance between any of the foci and directrix of the corresponding wing of the Hyperbola.ⓘ Focal Parameter of Hyperbola [p]			+10% -10%

✖Semi Conjugate Axis of Hyperbola is half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola.ⓘ Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter [b]

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Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter Solution

STEP 0: Pre-Calculation Summary

Formula Used

Semi Conjugate Axis of Hyperbola = (Eccentricity of Hyperbola/sqrt(Eccentricity of Hyperbola^2-1))*Focal Parameter of Hyperbola
b = (e/sqrt(e^2-1))*p
This formula uses 1 Functions, 3 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Semi Conjugate Axis of Hyperbola - (Measured in Meter) - Semi Conjugate Axis of Hyperbola is half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola.
Eccentricity of Hyperbola - (Measured in Meter) - Eccentricity of Hyperbola is the ratio of distances of any point on the Hyperbola from focus and the directrix, or it is the ratio of linear eccentricity and semi transverse axis of the Hyperbola.
Focal Parameter of Hyperbola - (Measured in Meter) - Focal Parameter of Hyperbola is the shortest distance between any of the foci and directrix of the corresponding wing of the Hyperbola.

STEP 1: Convert Input(s) to Base Unit

Eccentricity of Hyperbola: 3 Meter --> 3 Meter No Conversion Required
Focal Parameter of Hyperbola: 11 Meter --> 11 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

b = (e/sqrt(e^2-1))*p --> (3/sqrt(3^2-1))*11

Evaluating ... ...

b = 11.667261889578

STEP 3: Convert Result to Output's Unit

11.667261889578 Meter --> No Conversion Required

FINAL ANSWER

11.667261889578 ≈ 11.66726 Meter <-- Semi Conjugate Axis of Hyperbola

(Calculation completed in 00.004 seconds)

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Indian Institute of Technology, Indian School of Mines, DHANBAD (IIT ISM), Dhanbad, Jharkhand

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< Conjugate Axis of Hyperbola Calculators

Semi Conjugate Axis of Hyperbola given Latus Rectum and Eccentricity

LaTeX Go Semi Conjugate Axis of Hyperbola = sqrt((Latus Rectum of Hyperbola)^2/(Eccentricity of Hyperbola^2-1))/2

Semi Conjugate Axis of Hyperbola given Eccentricity

LaTeX Go Semi Conjugate Axis of Hyperbola = Semi Transverse Axis of Hyperbola*sqrt(Eccentricity of Hyperbola^2-1)

Conjugate Axis of Hyperbola given Latus Rectum and Eccentricity

LaTeX Go Conjugate Axis of Hyperbola = sqrt((Latus Rectum of Hyperbola)^2/(Eccentricity of Hyperbola^2-1))

Conjugate Axis of Hyperbola

LaTeX Go Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola

Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter Formula

LaTeX Go

Semi Conjugate Axis of Hyperbola = (Eccentricity of Hyperbola/sqrt(Eccentricity of Hyperbola^2-1))*Focal Parameter of Hyperbola
b = (e/sqrt(e^2-1))*p

What is Hyperbola?

A Hyperbola is a type of conic section, which is a geometric figure that results from intersecting a cone with a plane. A Hyperbola is defined as the set of all points in a plane, the difference of whose distances from two fixed points (called the foci) is constant. In other words, a Hyperbola is the locus of points where the difference between the distances to two fixed points is a constant value. The standard form of the equation for a Hyperbola is: (x - h)²/a² - (y - k)²/b² = 1

What is Conjugate Axis of the Hyperbola and how is it calculated?

The conjugate axis of Hyperbola is the line perpendicular to the transverse axis and has the co-vertices as its endpoints. It is calculated by the equation c = 2b where c is the length of the conjugate axis of the Hyperbola and b is the semi conjugate axis of the Hyperbola.

How to Calculate Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter?

Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter calculator uses Semi Conjugate Axis of Hyperbola = (Eccentricity of Hyperbola/sqrt(Eccentricity of Hyperbola^2-1))*Focal Parameter of Hyperbola to calculate the Semi Conjugate Axis of Hyperbola, The Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter formula is defined as half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola, and is calculated using the eccentricity and the focal parameter of the Hyperbola. Semi Conjugate Axis of Hyperbola is denoted by b symbol.

How to calculate Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter using this online calculator? To use this online calculator for Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter, enter Eccentricity of Hyperbola (e) & Focal Parameter of Hyperbola (p) and hit the calculate button. Here is how the Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter calculation can be explained with given input values -> 11.66726 = (3/sqrt(3^2-1))*11.

FAQ

What is Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter?

The Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter formula is defined as half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola, and is calculated using the eccentricity and the focal parameter of the Hyperbola and is represented as b = (e/sqrt(e^2-1))*p or Semi Conjugate Axis of Hyperbola = (Eccentricity of Hyperbola/sqrt(Eccentricity of Hyperbola^2-1))*Focal Parameter of Hyperbola. Eccentricity of Hyperbola is the ratio of distances of any point on the Hyperbola from focus and the directrix, or it is the ratio of linear eccentricity and semi transverse axis of the Hyperbola & Focal Parameter of Hyperbola is the shortest distance between any of the foci and directrix of the corresponding wing of the Hyperbola.

How to calculate Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter?

The Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter formula is defined as half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola, and is calculated using the eccentricity and the focal parameter of the Hyperbola is calculated using Semi Conjugate Axis of Hyperbola = (Eccentricity of Hyperbola/sqrt(Eccentricity of Hyperbola^2-1))*Focal Parameter of Hyperbola. To calculate Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter, you need Eccentricity of Hyperbola (e) & Focal Parameter of Hyperbola (p). With our tool, you need to enter the respective value for Eccentricity of Hyperbola & Focal Parameter of Hyperbola and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Semi Conjugate Axis of Hyperbola?

In this formula, Semi Conjugate Axis of Hyperbola uses Eccentricity of Hyperbola & Focal Parameter of Hyperbola. We can use 3 other way(s) to calculate the same, which is/are as follows -

Semi Conjugate Axis of Hyperbola = Semi Transverse Axis of Hyperbola*sqrt(Eccentricity of Hyperbola^2-1)
Semi Conjugate Axis of Hyperbola = sqrt((Latus Rectum of Hyperbola)^2/(Eccentricity of Hyperbola^2-1))/2
Semi Conjugate Axis of Hyperbola = Linear Eccentricity of Hyperbola*sqrt(1-1/Eccentricity of Hyperbola^2)

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