Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2)
ρ = V*Ploss*(Vm*(cos(Φ)))^2/(8*(P*L)^2)
This formula uses 1 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
STEP 1: Convert Input(s) to Base Unit
Volume Of Conductor: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion ​here)
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ρ = V*Ploss*(Vm*(cos(Φ)))^2/(8*(P*L)^2) --> 60*2.67*(230*(cos(0.5235987755982)))^2/(8*(300*24)^2)
Evaluating ... ...
ρ = 0.0153258463541667
STEP 3: Convert Result to Output's Unit
0.0153258463541667 Ohm Meter --> No Conversion Required
FINAL ANSWER
0.0153258463541667 0.015326 Ohm Meter <-- Resistivity
(Calculation completed in 00.008 seconds)

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Resistance and Resistivity Calculators

Resistivity using Area of X-Section (1-Phase 2-Wire US)
​ LaTeX ​ Go Resistivity = Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2)/((4)*Length of Underground AC Wire*(Power Transmitted^2))
Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)
​ LaTeX ​ Go Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2)
Resistance (1-Phase 2-Wire US)
​ LaTeX ​ Go Resistance Underground AC = Resistivity*Length of Underground AC Wire/Area of Underground AC Wire
Resistance using Volume of Conductor Material (1-Phase 2-Wire US)
​ LaTeX ​ Go Resistance Underground AC = Volume Of Conductor*Resistivity/(2*(Area of Underground AC Wire^2))

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Formula

​LaTeX ​Go
Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2)
ρ = V*Ploss*(Vm*(cos(Φ)))^2/(8*(P*L)^2)

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) calculator uses Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2) to calculate the Resistivity, The Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to calculate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Resistivity using Volume of Conductor Material (1-Phase 2-Wire US), enter Volume Of Conductor (V), Line Losses (Ploss), Maximum Voltage Underground AC (Vm), Phase Difference (Φ), Power Transmitted (P) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) calculation can be explained with given input values -> 0.015326 = 60*2.67*(230*(cos(0.5235987755982)))^2/(8*(300*24)^2).

FAQ

What is Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?
The Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors and is represented as ρ = V*Ploss*(Vm*(cos(Φ)))^2/(8*(P*L)^2) or Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2). Volume Of Conductor the 3-dimensional space enclosed by a conductor material, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire, Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work & Length of Underground AC Wire is the total length of the wire from one end to other end.
How to calculate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?
The Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors is calculated using Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2). To calculate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US), you need Volume Of Conductor (V), Line Losses (Ploss), Maximum Voltage Underground AC (Vm), Phase Difference (Φ), Power Transmitted (P) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Volume Of Conductor, Line Losses, Maximum Voltage Underground AC, Phase Difference, Power Transmitted & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Resistivity?
In this formula, Resistivity uses Volume Of Conductor, Line Losses, Maximum Voltage Underground AC, Phase Difference, Power Transmitted & Length of Underground AC Wire. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Resistivity = Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2)/((4)*Length of Underground AC Wire*(Power Transmitted^2))
  • Resistivity = Line Losses*Area of Underground AC Wire/(2*(Current Underground AC)^2*Length of Underground AC Wire)
  • Resistivity = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted)^2*Length of Underground AC Wire)
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