Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS) Calculator

✖Line Losses is defined as the total losses occurring in an Overhead AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Area of Overhead AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Overhead AC Wire [A]			+10% -10%
✖Current Overhead AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Overhead AC [I]			+10% -10%
✖Length of Overhead AC Wire is the total length of the wire from one end to other end.ⓘ Length of Overhead AC Wire [L]			+10% -10%

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS) [ρ]

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Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Resistivity = Line Losses*Area of Overhead AC Wire/(2*(Current Overhead AC)^2*Length of Overhead AC Wire)
ρ = P_loss*A/(2*(I)^2*L)
This formula uses 5 Variables

Variables Used

Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Overhead AC line when in use.
Area of Overhead AC Wire - (Measured in Square Meter) - Area of Overhead AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Current Overhead AC - (Measured in Ampere) - Current Overhead AC is defined as the current flowing through the overhead ac supply wire.
Length of Overhead AC Wire - (Measured in Meter) - Length of Overhead AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Line Losses: 8.23 Watt --> 8.23 Watt No Conversion Required
Area of Overhead AC Wire: 0.79 Square Meter --> 0.79 Square Meter No Conversion Required
Current Overhead AC: 6.9 Ampere --> 6.9 Ampere No Conversion Required
Length of Overhead AC Wire: 10.63 Meter --> 10.63 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

ρ = P_loss*A/(2*(I)^2*L) --> 8.23*0.79/(2*(6.9)^2*10.63)

Evaluating ... ...

ρ = 0.00642340765347486

STEP 3: Convert Result to Output's Unit

0.00642340765347486 Ohm Meter --> No Conversion Required

FINAL ANSWER

0.00642340765347486 ≈ 0.006423 Ohm Meter <-- Resistivity

(Calculation completed in 00.005 seconds)

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< Resistance and Resistivity Calculators

Resistivity using Area of X-Section(Single-Phase Two-Wire Mid-Point Earthed OS)

LaTeX Go Resistivity = (Area of Overhead AC Wire*Maximum Voltage Overhead AC^2*Line Losses*(cos(Phase Difference))^2)/(Length of Overhead AC Wire*Power Transmitted^2)

Resistance using Line Losses (Single-Phase Two-Wire Mid-Point OS)

LaTeX Go Resistance Overhead AC = (Line Losses*(Maximum Voltage Overhead AC*cos(Phase Difference))^2)/((Power Transmitted)^2)

Resistance(Single-Phase Two-Wire Mid-Point Earthed OS)

LaTeX Go Resistance Overhead AC = (Resistivity*Length of Overhead AC Wire)/Area of Overhead AC Wire

Resistance using Load Current (Single-Phase Two-Wire Mid-Point OS)

LaTeX Go Resistance Overhead AC = Line Losses/(2*(Current Overhead AC)^2)

Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS) Formula

LaTeX Go

Resistivity = Line Losses*Area of Overhead AC Wire/(2*(Current Overhead AC)^2*Length of Overhead AC Wire)
ρ = P_loss*A/(2*(I)^2*L)

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 1/2cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is 2v_m so that r.m.s. value of voltage between them is √2v_m.

How to Calculate Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS)?

Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS) calculator uses Resistivity = Line Losses*Area of Overhead AC Wire/(2*(Current Overhead AC)^2*Length of Overhead AC Wire) to calculate the Resistivity, Resistivity using Load Current (single-Phase two-Wire Mid-Point OS) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to calculate Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS) using this online calculator? To use this online calculator for Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS), enter Line Losses (P_loss), Area of Overhead AC Wire (A), Current Overhead AC (I) & Length of Overhead AC Wire (L) and hit the calculate button. Here is how the Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS) calculation can be explained with given input values -> 0.006423 = 8.23*0.79/(2*(6.9)^2*10.63).

FAQ

What is Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS)?

Resistivity using Load Current (single-Phase two-Wire Mid-Point OS) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors and is represented as ρ = P_loss*A/(2*(I)^2*L) or Resistivity = Line Losses*Area of Overhead AC Wire/(2*(Current Overhead AC)^2*Length of Overhead AC Wire). Line Losses is defined as the total losses occurring in an Overhead AC line when in use, Area of Overhead AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Current Overhead AC is defined as the current flowing through the overhead ac supply wire & Length of Overhead AC Wire is the total length of the wire from one end to other end.

How to calculate Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS)?

Resistivity using Load Current (single-Phase two-Wire Mid-Point OS) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors is calculated using Resistivity = Line Losses*Area of Overhead AC Wire/(2*(Current Overhead AC)^2*Length of Overhead AC Wire). To calculate Resistivity using Load Current (Single-Phase Two-Wire Mid-Point OS), you need Line Losses (P_loss), Area of Overhead AC Wire (A), Current Overhead AC (I) & Length of Overhead AC Wire (L). With our tool, you need to enter the respective value for Line Losses, Area of Overhead AC Wire, Current Overhead AC & Length of Overhead AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Resistivity?

In this formula, Resistivity uses Line Losses, Area of Overhead AC Wire, Current Overhead AC & Length of Overhead AC Wire. We can use 1 other way(s) to calculate the same, which is/are as follows -

Resistivity = (Area of Overhead AC Wire*Maximum Voltage Overhead AC^2*Line Losses*(cos(Phase Difference))^2)/(Length of Overhead AC Wire*Power Transmitted^2)

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