Resistivity using Line Losses (2-Phase 3-Wire US) Calculator

✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%
✖Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.ⓘ Phase Difference [Φ]			+10% -10%
✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted [P]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity using Line Losses (2-Phase 3-Wire US) [ρ]

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Resistivity using Line Losses (2-Phase 3-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Resistivity = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted)^2*Length of Underground AC Wire)
ρ = P_loss*A*(V_m*cos(Φ))^2/((2+sqrt(2))*(P)^2*L)
This formula uses 2 Functions, 7 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

ρ = P_loss*A*(V_m*cos(Φ))^2/((2+sqrt(2))*(P)^2*L) --> 2.67*1.28*(230*cos(0.5235987755982))^2/((2+sqrt(2))*(300)^2*24)

Evaluating ... ...

ρ = 0.0183862741799415

STEP 3: Convert Result to Output's Unit

0.0183862741799415 Ohm Meter --> No Conversion Required

FINAL ANSWER

0.0183862741799415 ≈ 0.018386 Ohm Meter <-- Resistivity

(Calculation completed in 00.004 seconds)

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< Resistance and Resistivity Calculators

Resistivity using Line Losses (2-Phase 3-Wire US)

LaTeX Go Resistivity = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted)^2*Length of Underground AC Wire)

Resistivity using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(((2+sqrt(2))*Power Transmitted*Length of Underground AC Wire)^2)

Resistance using Line Losses (2-Phase 3-Wire US)

LaTeX Go Resistance Underground AC = Line Losses/((2+sqrt(2))*(Current Underground AC)^2)

Resistance of Neutral Wire (2-Phase 3-Wire US)

LaTeX Go Resistance of Neutral Wire = Resistance Underground AC/sqrt(2)

Resistivity using Line Losses (2-Phase 3-Wire US) Formula

LaTeX Go

What is the value of maximum voltage and volume of conductor material in 2-phase 3-wire system?

The volume of conductor material required in this system is 2.914/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m/√2 so that r.m.s. value of voltage between them is v_m/2.

How to Calculate Resistivity using Line Losses (2-Phase 3-Wire US)?

Resistivity using Line Losses (2-Phase 3-Wire US) calculator uses Resistivity = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted)^2*Length of Underground AC Wire) to calculate the Resistivity, The Resistivity using Line Losses (2-Phase 3-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to calculate Resistivity using Line Losses (2-Phase 3-Wire US) using this online calculator? To use this online calculator for Resistivity using Line Losses (2-Phase 3-Wire US), enter Line Losses (P_loss), Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m), Phase Difference (Φ), Power Transmitted (P) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Resistivity using Line Losses (2-Phase 3-Wire US) calculation can be explained with given input values -> 0.018386 = 2.67*1.28*(230*cos(0.5235987755982))^2/((2+sqrt(2))*(300)^2*24).

FAQ

What is Resistivity using Line Losses (2-Phase 3-Wire US)?

The Resistivity using Line Losses (2-Phase 3-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors and is represented as ρ = P_loss*A*(V_m*cos(Φ))^2/((2+sqrt(2))*(P)^2*L) or Resistivity = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted)^2*Length of Underground AC Wire). Line Losses is defined as the total losses occurring in an Underground AC line when in use, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire, Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work & Length of Underground AC Wire is the total length of the wire from one end to other end.

How to calculate Resistivity using Line Losses (2-Phase 3-Wire US)?

The Resistivity using Line Losses (2-Phase 3-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors is calculated using Resistivity = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted)^2*Length of Underground AC Wire). To calculate Resistivity using Line Losses (2-Phase 3-Wire US), you need Line Losses (P_loss), Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m), Phase Difference (Φ), Power Transmitted (P) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Line Losses, Area of Underground AC Wire, Maximum Voltage Underground AC, Phase Difference, Power Transmitted & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Resistivity?

In this formula, Resistivity uses Line Losses, Area of Underground AC Wire, Maximum Voltage Underground AC, Phase Difference, Power Transmitted & Length of Underground AC Wire. We can use 2 other way(s) to calculate the same, which is/are as follows -

Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(((2+sqrt(2))*Power Transmitted*Length of Underground AC Wire)^2)
Resistivity = Resistance Underground AC*sqrt(2)*Area of Underground AC Wire/(Length of Underground AC Wire)

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