Resistivity using Load Current (3 Phase 4 Wire US) Calculator

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume Of Conductor [V]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Current Underground AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Underground AC [I]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity using Load Current (3 Phase 4 Wire US) [ρ]

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Resistivity using Load Current (3 Phase 4 Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Resistivity = (Volume Of Conductor*Line Losses/(3.5*3*(Current Underground AC^2)*(Length of Underground AC Wire^2)))
ρ = (V*P_loss/(3.5*3*(I^2)*(L^2)))
This formula uses 5 Variables

Variables Used

Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Volume Of Conductor: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

ρ = (V*P_loss/(3.5*3*(I^2)*(L^2))) --> (60*2.67/(3.5*3*(9^2)*(24^2)))

Evaluating ... ...

ρ = 0.000327013521457966

STEP 3: Convert Result to Output's Unit

0.000327013521457966 Ohm Meter --> No Conversion Required

FINAL ANSWER

0.000327013521457966 ≈ 0.000327 Ohm Meter <-- Resistivity

(Calculation completed in 00.004 seconds)

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< Resistance and Resistivity Calculators

Resistivity using Area of X-Section (3 Phase 4 Wire US)

LaTeX Go Resistivity = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)/(4*Length of Underground AC Wire*(Power Transmitted^2))

Resistivity using Volume of Conductor Material (3 Phase 4 Wire US)

LaTeX Go Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(6*(Power Transmitted*Length of Underground AC Wire)^2)

Resistivity using Load Current (3 Phase 4 Wire US)

LaTeX Go Resistivity = (Volume Of Conductor*Line Losses/(3.5*3*(Current Underground AC^2)*(Length of Underground AC Wire^2)))

Resistivity using Line Losses (3 Phase 4 Wire US)

LaTeX Go Resistivity = Line Losses*Area of Underground AC Wire/(3*(Current Underground AC^2)*Length of Underground AC Wire)

Resistivity using Load Current (3 Phase 4 Wire US) Formula

LaTeX Go

Resistivity = (Volume Of Conductor*Line Losses/(3.5*3*(Current Underground AC^2)*(Length of Underground AC Wire^2)))
ρ = (V*P_loss/(3.5*3*(I^2)*(L^2)))

Does resistivity change with length?

Resistivity is an intrinsic property of any material. It stays the same, no matter how long or thick your conductor is. Temperature coefficient*original resistivity*change in temperature. So there is no change with length in resistivity but resistance changes in direct proportion with the length of the conductor.

How to Calculate Resistivity using Load Current (3 Phase 4 Wire US)?

Resistivity using Load Current (3 Phase 4 Wire US) calculator uses Resistivity = (Volume Of Conductor*Line Losses/(3.5*3*(Current Underground AC^2)*(Length of Underground AC Wire^2))) to calculate the Resistivity, The Resistivity using Load Current (3 phase 4 wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to calculate Resistivity using Load Current (3 Phase 4 Wire US) using this online calculator? To use this online calculator for Resistivity using Load Current (3 Phase 4 Wire US), enter Volume Of Conductor (V), Line Losses (P_loss), Current Underground AC (I) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Resistivity using Load Current (3 Phase 4 Wire US) calculation can be explained with given input values -> 0.000327 = (60*2.67/(3.5*3*(9^2)*(24^2))).

FAQ

What is Resistivity using Load Current (3 Phase 4 Wire US)?

The Resistivity using Load Current (3 phase 4 wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors and is represented as ρ = (V*P_loss/(3.5*3*(I^2)*(L^2))) or Resistivity = (Volume Of Conductor*Line Losses/(3.5*3*(Current Underground AC^2)*(Length of Underground AC Wire^2))). Volume Of Conductor the 3-dimensional space enclosed by a conductor material, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Current Underground AC is defined as the current flowing through the overhead ac supply wire & Length of Underground AC Wire is the total length of the wire from one end to other end.

How to calculate Resistivity using Load Current (3 Phase 4 Wire US)?

The Resistivity using Load Current (3 phase 4 wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors is calculated using Resistivity = (Volume Of Conductor*Line Losses/(3.5*3*(Current Underground AC^2)*(Length of Underground AC Wire^2))). To calculate Resistivity using Load Current (3 Phase 4 Wire US), you need Volume Of Conductor (V), Line Losses (P_loss), Current Underground AC (I) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Volume Of Conductor, Line Losses, Current Underground AC & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Resistivity?

In this formula, Resistivity uses Volume Of Conductor, Line Losses, Current Underground AC & Length of Underground AC Wire. We can use 3 other way(s) to calculate the same, which is/are as follows -

Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(6*(Power Transmitted*Length of Underground AC Wire)^2)
Resistivity = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)/(4*Length of Underground AC Wire*(Power Transmitted^2))
Resistivity = Line Losses*Area of Underground AC Wire/(3*(Current Underground AC^2)*Length of Underground AC Wire)

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