Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution Calculator

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✖The number of Moles of Solute is the total number of representative particles present in the solute.ⓘ Number of Moles of Solute [n]			+10% -10%
✖Number of Moles of Solvent is the total number of representative particles present in the solvent.ⓘ Number of Moles of Solvent [N]			+10% -10%

✖The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.ⓘ Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution [Δp]

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Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution Solution

STEP 0: Pre-Calculation Summary

Formula Used

Relative Lowering of Vapour Pressure = Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent)
Δp = n/(n+N)
This formula uses 3 Variables

Variables Used

Relative Lowering of Vapour Pressure - The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.
Number of Moles of Solute - (Measured in Mole) - The number of Moles of Solute is the total number of representative particles present in the solute.
Number of Moles of Solvent - (Measured in Mole) - Number of Moles of Solvent is the total number of representative particles present in the solvent.

STEP 1: Convert Input(s) to Base Unit

Number of Moles of Solute: 0.52 Mole --> 0.52 Mole No Conversion Required
Number of Moles of Solvent: 10 Mole --> 10 Mole No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

Δp = n/(n+N) --> 0.52/(0.52+10)

Evaluating ... ...

Δp = 0.0494296577946768

STEP 3: Convert Result to Output's Unit

0.0494296577946768 --> No Conversion Required

FINAL ANSWER

0.0494296577946768 ≈ 0.04943 <-- Relative Lowering of Vapour Pressure

(Calculation completed in 00.007 seconds)

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< Relative Lowering of Vapour Pressure Calculators

Molecular Mass of Solvent given Relative Lowering of Vapour Pressure

LaTeX Go Molecular Mass Solvent = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molality*Vapour Pressure of Pure Solvent)

Relative Lowering of Vapour Pressure

LaTeX Go Relative Lowering of Vapour Pressure = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent

Mole Fraction of Solute given Vapour Pressure

LaTeX Go Mole Fraction of Solute = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent

Mole Fraction of Solvent given Vapour Pressure

LaTeX Go Mole Fraction of Solvent = Vapour Pressure of Solvent in Solution/Vapour Pressure of Pure Solvent

< Important Formulas of Colligative Properties Calculators

Osmotic Pressure given Depression in Freezing Point

LaTeX Go Osmotic Pressure = (Molar Enthalpy of Fusion*Depression in Freezing Point*Temperature)/(Molar Volume*(Solvent Freezing Point^2))

Osmotic Pressure given Concentration of Two Substances

LaTeX Go Osmotic Pressure = (Concentration of Particle 1+Concentration of Particle 2)*[R]*Temperature

Osmotic Pressure for Non Electrolyte

LaTeX Go Osmotic Pressure = Molar Concentration of Solute*[R]*Temperature

Osmotic Pressure given Density of Solution

LaTeX Go Osmotic Pressure = Density of Solution*[g]*Equilibrium Height

Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution Formula

LaTeX Go

Relative Lowering of Vapour Pressure = Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent)
Δp = n/(n+N)

What causes the Relative Lowering Of Vapour Pressure?

This lowering in vapour pressure is due to the fact that after the solute was added to the pure liquid (solvent), the liquid surface now had molecules of both, the pure liquid and the solute. The number of solvent molecules escaping into vapour phase gets reduced and as a result the pressure exerted by the vapour phase is also reduced. This is known as relative lowering of vapour pressure. This decrease in vapour pressure depends on the amount of non-volatile solute added in the solution irrespective of its nature and hence it is one of the colligative properties.

How to Calculate Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution?

Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution calculator uses Relative Lowering of Vapour Pressure = Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent) to calculate the Relative Lowering of Vapour Pressure, The Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution is equal to the mole fraction of solute present in the solution. Relative Lowering of Vapour Pressure is denoted by Δp symbol.

How to calculate Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution using this online calculator? To use this online calculator for Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution, enter Number of Moles of Solute (n) & Number of Moles of Solvent (N) and hit the calculate button. Here is how the Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution calculation can be explained with given input values -> 0.090909 = 0.52/(0.52+10).

FAQ

What is Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution?

The Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution is equal to the mole fraction of solute present in the solution and is represented as Δp = n/(n+N) or Relative Lowering of Vapour Pressure = Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent). The number of Moles of Solute is the total number of representative particles present in the solute & Number of Moles of Solvent is the total number of representative particles present in the solvent.

How to calculate Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution?

The Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution is equal to the mole fraction of solute present in the solution is calculated using Relative Lowering of Vapour Pressure = Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent). To calculate Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution, you need Number of Moles of Solute (n) & Number of Moles of Solvent (N). With our tool, you need to enter the respective value for Number of Moles of Solute & Number of Moles of Solvent and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Relative Lowering of Vapour Pressure?

In this formula, Relative Lowering of Vapour Pressure uses Number of Moles of Solute & Number of Moles of Solvent. We can use 3 other way(s) to calculate the same, which is/are as follows -

Relative Lowering of Vapour Pressure = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent
Relative Lowering of Vapour Pressure = Number of Moles of Solute/Number of Moles of Solvent
Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000

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