Relative Lowering of Vapour Pressure given Molecular Mass and Molality Solution

STEP 0: Pre-Calculation Summary
Formula Used
Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000
Δp = (m*M)/1000
This formula uses 3 Variables
Variables Used
Relative Lowering of Vapour Pressure - The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.
Molality - (Measured in Mole per Kilogram) - Molality is defined as the total number of moles of solute per kilograms of solvent present in the solution.
Molecular Mass Solvent - (Measured in Kilogram) - The Molecular Mass Solvent is sum of the atomic masses of all atoms in a molecule, based on a scale in which the atomic masses.
STEP 1: Convert Input(s) to Base Unit
Molality: 1.79 Mole per Kilogram --> 1.79 Mole per Kilogram No Conversion Required
Molecular Mass Solvent: 18 Gram --> 0.018 Kilogram (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Δp = (m*M)/1000 --> (1.79*0.018)/1000
Evaluating ... ...
Δp = 3.222E-05
STEP 3: Convert Result to Output's Unit
3.222E-05 --> No Conversion Required
FINAL ANSWER
3.222E-05 3.2E-5 <-- Relative Lowering of Vapour Pressure
(Calculation completed in 00.006 seconds)

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University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA
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National Institute of Information Technology (NIIT), Neemrana
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Relative Lowering of Vapour Pressure Calculators

Molecular Mass of Solvent given Relative Lowering of Vapour Pressure
​ LaTeX ​ Go Molecular Mass Solvent = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molality*Vapour Pressure of Pure Solvent)
Relative Lowering of Vapour Pressure
​ LaTeX ​ Go Relative Lowering of Vapour Pressure = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent
Mole Fraction of Solute given Vapour Pressure
​ LaTeX ​ Go Mole Fraction of Solute = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent
Mole Fraction of Solvent given Vapour Pressure
​ LaTeX ​ Go Mole Fraction of Solvent = Vapour Pressure of Solvent in Solution/Vapour Pressure of Pure Solvent

Relative Lowering of Vapour Pressure given Molecular Mass and Molality Formula

​LaTeX ​Go
Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000
Δp = (m*M)/1000

What causes the Relative Lowering Of Vapour Pressure?

This lowering in vapour pressure is due to the fact that after the solute was added to the pure liquid (solvent), the liquid surface now had molecules of both, the pure liquid and the solute. The number of solvent molecules escaping into vapour phase gets reduced and as a result the pressure exerted by the vapour phase is also reduced. This is known as relative lowering of vapour pressure. This decrease in vapour pressure depends on the amount of non-volatile solute added in the solution irrespective of its nature and hence it is one of the colligative properties.

How to Calculate Relative Lowering of Vapour Pressure given Molecular Mass and Molality?

Relative Lowering of Vapour Pressure given Molecular Mass and Molality calculator uses Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000 to calculate the Relative Lowering of Vapour Pressure, The Relative Lowering of Vapour Pressure given Molecular Mass and Molality is the relative measure of lowering of vapour pressure on addition of solute to solvent. Relative Lowering of Vapour Pressure is denoted by Δp symbol.

How to calculate Relative Lowering of Vapour Pressure given Molecular Mass and Molality using this online calculator? To use this online calculator for Relative Lowering of Vapour Pressure given Molecular Mass and Molality, enter Molality (m) & Molecular Mass Solvent (M) and hit the calculate button. Here is how the Relative Lowering of Vapour Pressure given Molecular Mass and Molality calculation can be explained with given input values -> 3.2E-5 = (1.79*0.018)/1000.

FAQ

What is Relative Lowering of Vapour Pressure given Molecular Mass and Molality?
The Relative Lowering of Vapour Pressure given Molecular Mass and Molality is the relative measure of lowering of vapour pressure on addition of solute to solvent and is represented as Δp = (m*M)/1000 or Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000. Molality is defined as the total number of moles of solute per kilograms of solvent present in the solution & The Molecular Mass Solvent is sum of the atomic masses of all atoms in a molecule, based on a scale in which the atomic masses.
How to calculate Relative Lowering of Vapour Pressure given Molecular Mass and Molality?
The Relative Lowering of Vapour Pressure given Molecular Mass and Molality is the relative measure of lowering of vapour pressure on addition of solute to solvent is calculated using Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000. To calculate Relative Lowering of Vapour Pressure given Molecular Mass and Molality, you need Molality (m) & Molecular Mass Solvent (M). With our tool, you need to enter the respective value for Molality & Molecular Mass Solvent and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Relative Lowering of Vapour Pressure?
In this formula, Relative Lowering of Vapour Pressure uses Molality & Molecular Mass Solvent. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Relative Lowering of Vapour Pressure = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent
  • Relative Lowering of Vapour Pressure = Number of Moles of Solute/Number of Moles of Solvent
  • Relative Lowering of Vapour Pressure = Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent)
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