Relative Lowering of Vapour Pressure given Osmotic Pressure Solution

STEP 0: Pre-Calculation Summary
Formula Used
Relative Lowering of Vapour Pressure = (Osmotic Pressure*Molar Volume)/([R]*Temperature)
Δp = (π*Vm)/([R]*T)
This formula uses 1 Constants, 4 Variables
Constants Used
[R] - Universal gas constant Value Taken As 8.31446261815324
Variables Used
Relative Lowering of Vapour Pressure - The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.
Osmotic Pressure - (Measured in Pascal) - The Osmotic Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane.
Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.
Temperature - (Measured in Kelvin) - Temperature is the degree or intensity of heat present in a substance or object.
STEP 1: Convert Input(s) to Base Unit
Osmotic Pressure: 2.5 Pascal --> 2.5 Pascal No Conversion Required
Molar Volume: 51.6 Cubic Meter per Mole --> 51.6 Cubic Meter per Mole No Conversion Required
Temperature: 298 Kelvin --> 298 Kelvin No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Δp = (π*Vm)/([R]*T) --> (2.5*51.6)/([R]*298)
Evaluating ... ...
Δp = 0.0520642073842673
STEP 3: Convert Result to Output's Unit
0.0520642073842673 --> No Conversion Required
FINAL ANSWER
0.0520642073842673 0.052064 <-- Relative Lowering of Vapour Pressure
(Calculation completed in 00.004 seconds)

Credits

Creator Image
Created by Prerana Bakli
University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA
Prerana Bakli has created this Calculator and 800+ more calculators!
Verifier Image
Verified by Akshada Kulkarni
National Institute of Information Technology (NIIT), Neemrana
Akshada Kulkarni has verified this Calculator and 900+ more calculators!

Osmotic Pressure Calculators

Osmotic Pressure given Volume and Osmotic Pressure of Two Substances
​ LaTeX ​ Go Osmotic Pressure = ((Osmotic Pressure of Particle 1*Volume of Particle 1)+(Osmotic Pressure of Particle 2*Volume of Particle 2))/([R]*Temperature)
Moles of Solute given Osmotic Pressure
​ LaTeX ​ Go Number of Moles of Solute = (Osmotic Pressure*Volume of Solution)/([R]*Temperature)
Density of Solution given Osmotic Pressure
​ LaTeX ​ Go Density of Solution = Osmotic Pressure/([g]*Equilibrium Height)
Equilibrium Height given Osmotic Pressure
​ LaTeX ​ Go Equilibrium Height = Osmotic Pressure/([g]*Density of Solution)

Relative Lowering of Vapour Pressure given Osmotic Pressure Formula

​LaTeX ​Go
Relative Lowering of Vapour Pressure = (Osmotic Pressure*Molar Volume)/([R]*Temperature)
Δp = (π*Vm)/([R]*T)

What causes the Relative Lowering Of Vapour Pressure?

This lowering in vapour pressure is due to the fact that after the solute was added to the pure liquid (solvent), the liquid surface now had molecules of both, the pure liquid and the solute. The number of solvent molecules escaping into vapour phase gets reduced and as a result the pressure exerted by the vapour phase is also reduced. This is known as relative lowering of vapour pressure. This decrease in vapour pressure depends on the amount of non-volatile solute added in the solution irrespective of its nature and hence it is one of the colligative properties.

How to Calculate Relative Lowering of Vapour Pressure given Osmotic Pressure?

Relative Lowering of Vapour Pressure given Osmotic Pressure calculator uses Relative Lowering of Vapour Pressure = (Osmotic Pressure*Molar Volume)/([R]*Temperature) to calculate the Relative Lowering of Vapour Pressure, The Relative Lowering of Vapour Pressure given Osmotic Pressure is the relative measure of lowering of vapour pressure on addition of solute to solvent. Relative Lowering of Vapour Pressure is denoted by Δp symbol.

How to calculate Relative Lowering of Vapour Pressure given Osmotic Pressure using this online calculator? To use this online calculator for Relative Lowering of Vapour Pressure given Osmotic Pressure, enter Osmotic Pressure (π), Molar Volume (Vm) & Temperature (T) and hit the calculate button. Here is how the Relative Lowering of Vapour Pressure given Osmotic Pressure calculation can be explained with given input values -> 0.052064 = (2.5*51.6)/([R]*298).

FAQ

What is Relative Lowering of Vapour Pressure given Osmotic Pressure?
The Relative Lowering of Vapour Pressure given Osmotic Pressure is the relative measure of lowering of vapour pressure on addition of solute to solvent and is represented as Δp = (π*Vm)/([R]*T) or Relative Lowering of Vapour Pressure = (Osmotic Pressure*Molar Volume)/([R]*Temperature). The Osmotic Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane, Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure & Temperature is the degree or intensity of heat present in a substance or object.
How to calculate Relative Lowering of Vapour Pressure given Osmotic Pressure?
The Relative Lowering of Vapour Pressure given Osmotic Pressure is the relative measure of lowering of vapour pressure on addition of solute to solvent is calculated using Relative Lowering of Vapour Pressure = (Osmotic Pressure*Molar Volume)/([R]*Temperature). To calculate Relative Lowering of Vapour Pressure given Osmotic Pressure, you need Osmotic Pressure (π), Molar Volume (Vm) & Temperature (T). With our tool, you need to enter the respective value for Osmotic Pressure, Molar Volume & Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
Let Others Know
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!