Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters Calculator

✖Volume of Real Gas is the space occupied by that real gas at standard temperature and pressure.ⓘ Volume of Real Gas [V_real]			+10% -10%
✖Critical Temperature is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, and the substance can exist both as a liquid and vapor.ⓘ Critical Temperature [T_c]			+10% -10%
✖Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.ⓘ Critical Pressure of Real Gas [P'_c]			+10% -10%
✖Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter c [c]			+10% -10%

✖Reduced Volume of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume.ⓘ Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters [V_r]

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Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters Solution

STEP 0: Pre-Calculation Summary

Formula Used

Reduced Volume = Volume of Real Gas/(((3*[R]*Critical Temperature)/(8*Critical Pressure of Real Gas))-Clausius Parameter c)
V_r = V_real/(((3*[R]*T_c)/(8*P'_c))-c)
This formula uses 1 Constants, 5 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Reduced Volume - (Measured in Cubic Meter) - Reduced Volume of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume.
Volume of Real Gas - (Measured in Cubic Meter) - Volume of Real Gas is the space occupied by that real gas at standard temperature and pressure.
Critical Temperature - (Measured in Kelvin) - Critical Temperature is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, and the substance can exist both as a liquid and vapor.
Critical Pressure of Real Gas - (Measured in Pascal) - Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.
Clausius Parameter c - Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

STEP 1: Convert Input(s) to Base Unit

Volume of Real Gas: 22 Liter --> 0.022 Cubic Meter (Check conversion here)
Critical Temperature: 647 Kelvin --> 647 Kelvin No Conversion Required
Critical Pressure of Real Gas: 4600000 Pascal --> 4600000 Pascal No Conversion Required
Clausius Parameter c: 0.0002 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V_r = V_real/(((3*[R]*T_c)/(8*P'_c))-c) --> 0.022/(((3*[R]*647)/(8*4600000))-0.0002)

Evaluating ... ...

V_r = 92.2266686082936

STEP 3: Convert Result to Output's Unit

92.2266686082936 Cubic Meter -->92226.6686082936 Liter (Check conversion here)

FINAL ANSWER

92226.6686082936 ≈ 92226.67 Liter <-- Reduced Volume

(Calculation completed in 00.004 seconds)

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< Reduced Volume Calculators

Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters

LaTeX Go Reduced Volume given RP AP = Volume of Real Gas/(((3*[R]*(Real Gas Temperature/Reduced Temperature))/(8*(Real Gas Pressure/Reduced Pressure)))-Clausius Parameter c)

Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

LaTeX Go Reduced Volume = Volume of Real Gas/(Clausius Parameter b for Real Gas+(([R]*(Temperature of Real Gas/Reduced Temperature))/(4*(Pressure/Reduced Pressure))))

Reduced Volume of Real Gas given Clausius Parameter b and Actual Parameters

LaTeX Go Reduced Volume = Volume of Real Gas/(Clausius Parameter b for Real Gas+(([R]*Critical Temperature For Clausius Model)/(4*Critical Pressure of Real Gas)))

Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters

LaTeX Go Reduced Volume = Volume of Real Gas/(((3*[R]*Critical Temperature)/(8*Critical Pressure of Real Gas))-Clausius Parameter c)

Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters Formula

LaTeX Go

Reduced Volume = Volume of Real Gas/(((3*[R]*Critical Temperature)/(8*Critical Pressure of Real Gas))-Clausius Parameter c)
V_r = V_real/(((3*[R]*T_c)/(8*P'_c))-c)

What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters?

Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters calculator uses Reduced Volume = Volume of Real Gas/(((3*[R]*Critical Temperature)/(8*Critical Pressure of Real Gas))-Clausius Parameter c) to calculate the Reduced Volume, The Reduced Volume of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of its actual volume to critical volume. Reduced Volume is denoted by V_r symbol.

How to calculate Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters using this online calculator? To use this online calculator for Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters, enter Volume of Real Gas (V_real), Critical Temperature (T_c), Critical Pressure of Real Gas (P'_c) & Clausius Parameter c (c) and hit the calculate button. Here is how the Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters calculation can be explained with given input values -> 9.2E+7 = 0.022/(((3*[R]*647)/(8*4600000))-0.0002).

FAQ

What is Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters?

The Reduced Volume of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of its actual volume to critical volume and is represented as V_r = V_real/(((3*[R]*T_c)/(8*P'_c))-c) or Reduced Volume = Volume of Real Gas/(((3*[R]*Critical Temperature)/(8*Critical Pressure of Real Gas))-Clausius Parameter c). Volume of Real Gas is the space occupied by that real gas at standard temperature and pressure, Critical Temperature is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, and the substance can exist both as a liquid and vapor, Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature & Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

How to calculate Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters?

The Reduced Volume of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of its actual volume to critical volume is calculated using Reduced Volume = Volume of Real Gas/(((3*[R]*Critical Temperature)/(8*Critical Pressure of Real Gas))-Clausius Parameter c). To calculate Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters, you need Volume of Real Gas (V_real), Critical Temperature (T_c), Critical Pressure of Real Gas (P'_c) & Clausius Parameter c (c). With our tool, you need to enter the respective value for Volume of Real Gas, Critical Temperature, Critical Pressure of Real Gas & Clausius Parameter c and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Reduced Volume?

In this formula, Reduced Volume uses Volume of Real Gas, Critical Temperature, Critical Pressure of Real Gas & Clausius Parameter c. We can use 3 other way(s) to calculate the same, which is/are as follows -

Reduced Volume = Volume of Real Gas/(Clausius Parameter b for Real Gas+(([R]*Critical Temperature For Clausius Model)/(4*Critical Pressure of Real Gas)))
Reduced Volume = Volume of Real Gas/(Clausius Parameter b for Real Gas+(([R]*(Temperature of Real Gas/Reduced Temperature))/(4*(Pressure/Reduced Pressure))))
Reduced Volume = Volume of Real Gas/Critical Volume

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