Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters Calculator

✖Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.ⓘ Pressure [p]			+10% -10%
✖Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter a [a]			+10% -10%
✖Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure.ⓘ Molar Volume [V_m]			+10% -10%
✖Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter c [c]			+10% -10%
✖Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter b for Real Gas [b']			+10% -10%
✖Temperature of Real Gas is the degree or intensity of heat present in a substance or object.ⓘ Temperature of Real Gas [T_rg]			+10% -10%

✖Reduced Temperature given RP AP is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.ⓘ Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters [T_{r_RP_AP}]

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Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters Solution

STEP 0: Pre-Calculation Summary

Formula Used

Reduced Temperature given RP AP = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Temperature of Real Gas
T_{r_RP_AP} = ((p+(a/(((V_m+c)^2))))*((V_m-b')/[R]))/T_rg
This formula uses 1 Constants, 7 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Reduced Temperature given RP AP - Reduced Temperature given RP AP is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.
Pressure - (Measured in Pascal) - Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
Clausius Parameter a - Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure.
Clausius Parameter c - Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Clausius Parameter b for Real Gas - Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Temperature of Real Gas - (Measured in Kelvin) - Temperature of Real Gas is the degree or intensity of heat present in a substance or object.

STEP 1: Convert Input(s) to Base Unit

Pressure: 800 Pascal --> 800 Pascal No Conversion Required
Clausius Parameter a: 0.1 --> No Conversion Required
Molar Volume: 22.4 Cubic Meter per Mole --> 22.4 Cubic Meter per Mole No Conversion Required
Clausius Parameter c: 0.0002 --> No Conversion Required
Clausius Parameter b for Real Gas: 0.00243 --> No Conversion Required
Temperature of Real Gas: 300 Kelvin --> 300 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

T_{r_RP_AP} = ((p+(a/(((V_m+c)^2))))*((V_m-b')/[R]))/T_rg --> ((800+(0.1/(((22.4+0.0002)^2))))*((22.4-0.00243)/[R]))/300

Evaluating ... ...

T_{r_RP_AP} = 7.18349109923257

STEP 3: Convert Result to Output's Unit

7.18349109923257 --> No Conversion Required

FINAL ANSWER

7.18349109923257 ≈ 7.183491 <-- Reduced Temperature given RP AP

(Calculation completed in 00.020 seconds)

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< Reduced Temperature of Real Gas Calculators

Reduced Temperature of Real Gas given Clausius Parameter c given Reduced and Actual Parameters

LaTeX Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+(Volume of Real Gas/Reduced Volume))*8*(Pressure/Reduced Pressure))/(3*[R]))

Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters

LaTeX Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R]))

Reduced Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters

LaTeX Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))

Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters

LaTeX Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))

< Important Formulae on Clausius Model of Real Gas Calculators

Actual Pressure of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

LaTeX Go Pressure given b = (([R]*(Temperature of Real Gas/Reduced Temperature))/(4*((Volume of Real Gas/Reduced Volume)-Clausius Parameter b for Real Gas)))*Reduced Pressure

Actual Pressure of Real Gas given Clausius Parameter c, Reduced and Actual Parameters

LaTeX Go Pressure given c = ((3*[R]*(Temperature of Real Gas/Reduced Temperature))/(8*(Clausius Parameter c+(Volume of Real Gas/Reduced Volume))))*Reduced Pressure

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters

LaTeX Go Temperature given RP = (((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))*Reduced Temperature

Actual Pressure of Real Gas given Clausius Parameter a, Reduced and Critical Parameters

LaTeX Go Pressure given a = ((27*([R]^2)*(Critical Temperature For Clausius Model^3))/(64*Clausius Parameter a))*Reduced Pressure

Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters Formula

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What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters?

Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters calculator uses Reduced Temperature given RP AP = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Temperature of Real Gas to calculate the Reduced Temperature given RP AP, The Reduced Temperature of real gas using Clausius equation given reduced and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless. Reduced Temperature given RP AP is denoted by T_{r_RP_AP} symbol.

How to calculate Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters using this online calculator? To use this online calculator for Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters, enter Pressure (p), Clausius Parameter a (a), Molar Volume (V_m), Clausius Parameter c (c), Clausius Parameter b for Real Gas (b') & Temperature of Real Gas (T_rg) and hit the calculate button. Here is how the Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters calculation can be explained with given input values -> 25.3535 = ((800+(0.1/(((22.4+0.0002)^2))))*((22.4-0.00243)/[R]))/300.

FAQ

What is Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters?

The Reduced Temperature of real gas using Clausius equation given reduced and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless and is represented as T_{r_RP_AP} = ((p+(a/(((V_m+c)^2))))*((V_m-b')/[R]))/T_rg or Reduced Temperature given RP AP = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Temperature of Real Gas. Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed, Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas, Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure, Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas, Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas & Temperature of Real Gas is the degree or intensity of heat present in a substance or object.

How to calculate Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters?

The Reduced Temperature of real gas using Clausius equation given reduced and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless is calculated using Reduced Temperature given RP AP = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Temperature of Real Gas. To calculate Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters, you need Pressure (p), Clausius Parameter a (a), Molar Volume (V_m), Clausius Parameter c (c), Clausius Parameter b for Real Gas (b') & Temperature of Real Gas (T_rg). With our tool, you need to enter the respective value for Pressure, Clausius Parameter a, Molar Volume, Clausius Parameter c, Clausius Parameter b for Real Gas & Temperature of Real Gas and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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