Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters Calculator

✖Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.ⓘ Pressure [p]			+10% -10%
✖Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor.ⓘ Critical Temperature For Clausius Model [T'_c]			+10% -10%
✖Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter c [c]			+10% -10%
✖The Critical Volume is the volume occupied by the unit mass of gas at critical temperature and pressure.ⓘ Critical Volume [V_c]			+10% -10%

✖Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.ⓘ Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters [P_r]

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Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters Solution

STEP 0: Pre-Calculation Summary

Formula Used

Reduced Pressure = Pressure/((3*[R]*Critical Temperature For Clausius Model)/(8*(Clausius Parameter c+Critical Volume)))
P_r = p/((3*[R]*T'_c)/(8*(c+V_c)))
This formula uses 1 Constants, 5 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Reduced Pressure - Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.
Pressure - (Measured in Pascal) - Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
Critical Temperature For Clausius Model - (Measured in Kelvin) - Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor.
Clausius Parameter c - Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Critical Volume - (Measured in Cubic Meter) - The Critical Volume is the volume occupied by the unit mass of gas at critical temperature and pressure.

STEP 1: Convert Input(s) to Base Unit

Pressure: 800 Pascal --> 800 Pascal No Conversion Required
Critical Temperature For Clausius Model: 154.4 Kelvin --> 154.4 Kelvin No Conversion Required
Clausius Parameter c: 0.0002 --> No Conversion Required
Critical Volume: 10 Liter --> 0.01 Cubic Meter (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P_r = p/((3*[R]*T'_c)/(8*(c+V_c))) --> 800/((3*[R]*154.4)/(8*(0.0002+0.01)))

Evaluating ... ...

P_r = 0.0169503008143117

STEP 3: Convert Result to Output's Unit

0.0169503008143117 --> No Conversion Required

FINAL ANSWER

0.0169503008143117 ≈ 0.01695 <-- Reduced Pressure

(Calculation completed in 00.004 seconds)

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< Reduced Pressure of Real Gas Calculators

Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters

LaTeX Go Reduced Pressure = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Molar Volume for Real Gas*Critical Volume)-Clausius Parameter b for Real Gas))-(Clausius Parameter a/((Reduced Temperature*Critical Temperature For Clausius Model)*(((Reduced Molar Volume for Real Gas*Critical Volume)+Clausius Parameter c)^2))))/Critical Pressure of Real Gas

Reduced Pressure of Real Gas using Clausius Equation given Critical and Actual Parameters

LaTeX Go Reduced Pressure = ((([R]*Temperature of Real Gas)/(Molar Volume of Real Gas-Clausius Parameter b for Real Gas))-(Clausius Parameter a/(Temperature of Real Gas*((Molar Volume of Real Gas+Clausius Parameter c)^2))))/Critical Pressure of Real Gas

Reduced Pressure of Real Gas using Clausius Equation given Reduced and Actual Parameters

LaTeX Go Reduced Pressure given CM = ((([R]*Temperature of Real Gas)/(Molar Volume of Real Gas-Clausius Parameter b for Real Gas))-(Clausius Parameter a/(Temperature of Real Gas*((Molar Volume of Real Gas+Clausius Parameter c)^2))))/Pressure

Reduced Pressure of Real Gas given Clausius Parameter and Actual Parameters

LaTeX Go Reduced Pressure = Pressure/((27*([R]^2)*(Critical Temperature For Clausius Model^3))/(64*Clausius Parameter a))

Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters Formula

LaTeX Go

Reduced Pressure = Pressure/((3*[R]*Critical Temperature For Clausius Model)/(8*(Clausius Parameter c+Critical Volume)))
P_r = p/((3*[R]*T'_c)/(8*(c+V_c)))

What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters?

Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters calculator uses Reduced Pressure = Pressure/((3*[R]*Critical Temperature For Clausius Model)/(8*(Clausius Parameter c+Critical Volume))) to calculate the Reduced Pressure, The Reduced Pressure of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless. Reduced Pressure is denoted by P_r symbol.

How to calculate Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters using this online calculator? To use this online calculator for Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters, enter Pressure (p), Critical Temperature For Clausius Model (T'_c), Clausius Parameter c (c) & Critical Volume (V_c) and hit the calculate button. Here is how the Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters calculation can be explained with given input values -> 0.004045 = 800/((3*[R]*154.4)/(8*(0.0002+0.01))).

FAQ

What is Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters?

The Reduced Pressure of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless and is represented as P_r = p/((3*[R]*T'_c)/(8*(c+V_c))) or Reduced Pressure = Pressure/((3*[R]*Critical Temperature For Clausius Model)/(8*(Clausius Parameter c+Critical Volume))). Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed, Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor, Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas & The Critical Volume is the volume occupied by the unit mass of gas at critical temperature and pressure.

How to calculate Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters?

The Reduced Pressure of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless is calculated using Reduced Pressure = Pressure/((3*[R]*Critical Temperature For Clausius Model)/(8*(Clausius Parameter c+Critical Volume))). To calculate Reduced Pressure of Real Gas given Clausius Parameter c and Actual Parameters, you need Pressure (p), Critical Temperature For Clausius Model (T'_c), Clausius Parameter c (c) & Critical Volume (V_c). With our tool, you need to enter the respective value for Pressure, Critical Temperature For Clausius Model, Clausius Parameter c & Critical Volume and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Reduced Pressure?

In this formula, Reduced Pressure uses Pressure, Critical Temperature For Clausius Model, Clausius Parameter c & Critical Volume. We can use 3 other way(s) to calculate the same, which is/are as follows -

Reduced Pressure = ((([R]*Temperature of Real Gas)/(Molar Volume of Real Gas-Clausius Parameter b for Real Gas))-(Clausius Parameter a/(Temperature of Real Gas*((Molar Volume of Real Gas+Clausius Parameter c)^2))))/Critical Pressure of Real Gas
Reduced Pressure = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Molar Volume for Real Gas*Critical Volume)-Clausius Parameter b for Real Gas))-(Clausius Parameter a/((Reduced Temperature*Critical Temperature For Clausius Model)*(((Reduced Molar Volume for Real Gas*Critical Volume)+Clausius Parameter c)^2))))/Critical Pressure of Real Gas
Reduced Pressure = Pressure/((27*([R]^2)*(Critical Temperature For Clausius Model^3))/(64*Clausius Parameter a))

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