Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters Calculator

✖Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.ⓘ Reduced Temperature [T_r]			+10% -10%
✖Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor.ⓘ Critical Temperature For Clausius Model [T'_c]			+10% -10%
✖Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.ⓘ Reduced Molar Volume for Real Gas [V'_m,r]			+10% -10%
✖The Critical Volume is the volume occupied by the unit mass of gas at critical temperature and pressure.ⓘ Critical Volume [V_c]			+10% -10%
✖Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter b for Real Gas [b']			+10% -10%
✖Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter a [a]			+10% -10%
✖Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter c [c]			+10% -10%
✖Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.ⓘ Critical Pressure of Real Gas [P'_c]			+10% -10%

✖Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.ⓘ Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters [P_r]

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Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters Solution

STEP 0: Pre-Calculation Summary

Formula Used

Reduced Pressure = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Molar Volume for Real Gas*Critical Volume)-Clausius Parameter b for Real Gas))-(Clausius Parameter a/((Reduced Temperature*Critical Temperature For Clausius Model)*(((Reduced Molar Volume for Real Gas*Critical Volume)+Clausius Parameter c)^2))))/Critical Pressure of Real Gas
P_r = ((([R]*(T_r*T'_c))/((V'_m,r*V_c)-b'))-(a/((T_r*T'_c)*(((V'_m,r*V_c)+c)^2))))/P'_c
This formula uses 1 Constants, 9 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Reduced Pressure - Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.
Reduced Temperature - Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.
Critical Temperature For Clausius Model - (Measured in Kelvin) - Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor.
Reduced Molar Volume for Real Gas - Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.
Critical Volume - (Measured in Cubic Meter) - The Critical Volume is the volume occupied by the unit mass of gas at critical temperature and pressure.
Clausius Parameter b for Real Gas - Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Clausius Parameter a - Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Clausius Parameter c - Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Critical Pressure of Real Gas - (Measured in Pascal) - Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.

STEP 1: Convert Input(s) to Base Unit

Reduced Temperature: 10 --> No Conversion Required
Critical Temperature For Clausius Model: 154.4 Kelvin --> 154.4 Kelvin No Conversion Required
Reduced Molar Volume for Real Gas: 8.96 --> No Conversion Required
Critical Volume: 10 Liter --> 0.01 Cubic Meter (Check conversion here)
Clausius Parameter b for Real Gas: 0.00243 --> No Conversion Required
Clausius Parameter a: 0.1 --> No Conversion Required
Clausius Parameter c: 0.0002 --> No Conversion Required
Critical Pressure of Real Gas: 4600000 Pascal --> 4600000 Pascal No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P_r = ((([R]*(T_r*T'_c))/((V'_m,r*V_c)-b'))-(a/((T_r*T'_c)*(((V'_m,r*V_c)+c)^2))))/P'_c --> ((([R]*(10*154.4))/((8.96*0.01)-0.00243))-(0.1/((10*154.4)*(((8.96*0.01)+0.0002)^2))))/4600000

Evaluating ... ...

P_r = 0.0320152265745528

STEP 3: Convert Result to Output's Unit

0.0320152265745528 --> No Conversion Required

FINAL ANSWER

0.0320152265745528 ≈ 0.032015 <-- Reduced Pressure

(Calculation completed in 00.020 seconds)

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< Reduced Pressure of Real Gas Calculators

Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters

LaTeX Go Reduced Pressure = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Molar Volume for Real Gas*Critical Volume)-Clausius Parameter b for Real Gas))-(Clausius Parameter a/((Reduced Temperature*Critical Temperature For Clausius Model)*(((Reduced Molar Volume for Real Gas*Critical Volume)+Clausius Parameter c)^2))))/Critical Pressure of Real Gas

Reduced Pressure of Real Gas using Clausius Equation given Critical and Actual Parameters

LaTeX Go Reduced Pressure = ((([R]*Temperature of Real Gas)/(Molar Volume of Real Gas-Clausius Parameter b for Real Gas))-(Clausius Parameter a/(Temperature of Real Gas*((Molar Volume of Real Gas+Clausius Parameter c)^2))))/Critical Pressure of Real Gas

Reduced Pressure of Real Gas using Clausius Equation given Reduced and Actual Parameters

LaTeX Go Reduced Pressure given CM = ((([R]*Temperature of Real Gas)/(Molar Volume of Real Gas-Clausius Parameter b for Real Gas))-(Clausius Parameter a/(Temperature of Real Gas*((Molar Volume of Real Gas+Clausius Parameter c)^2))))/Pressure

Reduced Pressure of Real Gas given Clausius Parameter and Actual Parameters

LaTeX Go Reduced Pressure = Pressure/((27*([R]^2)*(Critical Temperature For Clausius Model^3))/(64*Clausius Parameter a))

Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula

LaTeX Go

What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters?

Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters calculator uses Reduced Pressure = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Molar Volume for Real Gas*Critical Volume)-Clausius Parameter b for Real Gas))-(Clausius Parameter a/((Reduced Temperature*Critical Temperature For Clausius Model)*(((Reduced Molar Volume for Real Gas*Critical Volume)+Clausius Parameter c)^2))))/Critical Pressure of Real Gas to calculate the Reduced Pressure, The Reduced Pressure of real gas using Clausius equation given reduced and critical parameters formula is defined as the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless. Reduced Pressure is denoted by P_r symbol.

How to calculate Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters using this online calculator? To use this online calculator for Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters, enter Reduced Temperature (T_r), Critical Temperature For Clausius Model (T'_c), Reduced Molar Volume for Real Gas (V'_m,r), Critical Volume (V_c), Clausius Parameter b for Real Gas (b'), Clausius Parameter a (a), Clausius Parameter c (c) & Critical Pressure of Real Gas (P'_c) and hit the calculate button. Here is how the Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters calculation can be explained with given input values -> 0.02547 = ((([R]*(10*154.4))/((8.96*0.01)-0.00243))-(0.1/((10*154.4)*(((8.96*0.01)+0.0002)^2))))/4600000.

FAQ

What is Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters?

The Reduced Pressure of real gas using Clausius equation given reduced and critical parameters formula is defined as the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless and is represented as P_r = ((([R]*(T_r*T'_c))/((V'_m,r*V_c)-b'))-(a/((T_r*T'_c)*(((V'_m,r*V_c)+c)^2))))/P'_c or Reduced Pressure = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Molar Volume for Real Gas*Critical Volume)-Clausius Parameter b for Real Gas))-(Clausius Parameter a/((Reduced Temperature*Critical Temperature For Clausius Model)*(((Reduced Molar Volume for Real Gas*Critical Volume)+Clausius Parameter c)^2))))/Critical Pressure of Real Gas. Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless, Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor, Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole, The Critical Volume is the volume occupied by the unit mass of gas at critical temperature and pressure, Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas, Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas, Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas & Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.

How to calculate Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters?

The Reduced Pressure of real gas using Clausius equation given reduced and critical parameters formula is defined as the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless is calculated using Reduced Pressure = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Molar Volume for Real Gas*Critical Volume)-Clausius Parameter b for Real Gas))-(Clausius Parameter a/((Reduced Temperature*Critical Temperature For Clausius Model)*(((Reduced Molar Volume for Real Gas*Critical Volume)+Clausius Parameter c)^2))))/Critical Pressure of Real Gas. To calculate Reduced Pressure of Real Gas using Clausius Equation given Reduced and Critical Parameters, you need Reduced Temperature (T_r), Critical Temperature For Clausius Model (T'_c), Reduced Molar Volume for Real Gas (V'_m,r), Critical Volume (V_c), Clausius Parameter b for Real Gas (b'), Clausius Parameter a (a), Clausius Parameter c (c) & Critical Pressure of Real Gas (P'_c). With our tool, you need to enter the respective value for Reduced Temperature, Critical Temperature For Clausius Model, Reduced Molar Volume for Real Gas, Critical Volume, Clausius Parameter b for Real Gas, Clausius Parameter a, Clausius Parameter c & Critical Pressure of Real Gas and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Reduced Pressure?

In this formula, Reduced Pressure uses Reduced Temperature, Critical Temperature For Clausius Model, Reduced Molar Volume for Real Gas, Critical Volume, Clausius Parameter b for Real Gas, Clausius Parameter a, Clausius Parameter c & Critical Pressure of Real Gas. We can use 3 other way(s) to calculate the same, which is/are as follows -

Reduced Pressure = ((([R]*Temperature of Real Gas)/(Molar Volume of Real Gas-Clausius Parameter b for Real Gas))-(Clausius Parameter a/(Temperature of Real Gas*((Molar Volume of Real Gas+Clausius Parameter c)^2))))/Critical Pressure of Real Gas
Reduced Pressure = Pressure/((27*([R]^2)*(Critical Temperature For Clausius Model^3))/(64*Clausius Parameter a))
Reduced Pressure = Pressure/((27*([R]^2)*((Temperature of Real Gas/Reduced Temperature)^3))/(64*Clausius Parameter a))

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