Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' Calculator

✖Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure.ⓘ Molar Volume [V_m]			+10% -10%
✖Redlich–Kwong parameter b is an empirical parameter characteristic to equation obtained from Redlich–Kwong model of real gas.ⓘ Redlich–Kwong parameter b [b]			+10% -10%

✖Reduced Molar Volume of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.ⓘ Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' [V_m,r]

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Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' Solution

STEP 0: Pre-Calculation Summary

Formula Used

Reduced Molar Volume = Molar Volume/(Redlich–Kwong parameter b/((2^(1/3))-1))
V_m,r = V_m/(b/((2^(1/3))-1))
This formula uses 3 Variables

Variables Used

Reduced Molar Volume - Reduced Molar Volume of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.
Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure.
Redlich–Kwong parameter b - Redlich–Kwong parameter b is an empirical parameter characteristic to equation obtained from Redlich–Kwong model of real gas.

STEP 1: Convert Input(s) to Base Unit

Molar Volume: 22.4 Cubic Meter per Mole --> 22.4 Cubic Meter per Mole No Conversion Required
Redlich–Kwong parameter b: 0.1 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V_m,r = V_m/(b/((2^(1/3))-1)) --> 22.4/(0.1/((2^(1/3))-1))

Evaluating ... ...

V_m,r = 58.2223151764516

STEP 3: Convert Result to Output's Unit

58.2223151764516 --> No Conversion Required

FINAL ANSWER

58.2223151764516 ≈ 58.22232 <-- Reduced Molar Volume

(Calculation completed in 00.004 seconds)

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< Redlich Kwong Model of Real Gas Calculators

Molar Volume of Real Gas using Redlich Kwong Equation

LaTeX Go Molar Volume = ((1/Pressure)+(Redlich–Kwong parameter b/([R]*Temperature)))/((1/([R]*Temperature))-((sqrt(Temperature)*Redlich–Kwong parameter b)/Redlich–Kwong Parameter a))

Pressure of Real Gas using Redlich Kwong Equation

LaTeX Go Pressure = (([R]*Temperature)/(Molar Volume-Redlich–Kwong parameter b))-(Redlich–Kwong Parameter a)/(sqrt(Temperature)*Molar Volume*(Molar Volume+Redlich–Kwong parameter b))

Critical Pressure of Real Gas using Redlich Kwong Equation given 'a' and 'b'

LaTeX Go Critical Pressure = (((2^(1/3))-1)^(7/3)*([R]^(1/3))*(Redlich–Kwong Parameter a^(2/3)))/((3^(1/3))*(Redlich–Kwong parameter b^(5/3)))

Critical Molar Volume of Real Gas using Redlich Kwong Equation given 'a' and 'b'

LaTeX Go Critical Molar Volume = Redlich–Kwong parameter b/((2^(1/3))-1)

Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' Formula

LaTeX Go

Reduced Molar Volume = Molar Volume/(Redlich–Kwong parameter b/((2^(1/3))-1))
V_m,r = V_m/(b/((2^(1/3))-1))

What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b'?

Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' calculator uses Reduced Molar Volume = Molar Volume/(Redlich–Kwong parameter b/((2^(1/3))-1)) to calculate the Reduced Molar Volume, The Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' formula of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume per mole. Reduced Molar Volume is denoted by V_m,r symbol.

How to calculate Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' using this online calculator? To use this online calculator for Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b', enter Molar Volume (V_m) & Redlich–Kwong parameter b (b) and hit the calculate button. Here is how the Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' calculation can be explained with given input values -> 58.22232 = 22.4/(0.1/((2^(1/3))-1)).

FAQ

What is Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b'?

The Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' formula of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume per mole and is represented as V_m,r = V_m/(b/((2^(1/3))-1)) or Reduced Molar Volume = Molar Volume/(Redlich–Kwong parameter b/((2^(1/3))-1)). Molar Volume is the volume occupied by one mole of a real gas at standard temperature and pressure & Redlich–Kwong parameter b is an empirical parameter characteristic to equation obtained from Redlich–Kwong model of real gas.

How to calculate Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b'?

The Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b' formula of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume per mole is calculated using Reduced Molar Volume = Molar Volume/(Redlich–Kwong parameter b/((2^(1/3))-1)). To calculate Reduced Molar Volume using Redlich Kwong Equation given 'a' and 'b', you need Molar Volume (V_m) & Redlich–Kwong parameter b (b). With our tool, you need to enter the respective value for Molar Volume & Redlich–Kwong parameter b and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Reduced Molar Volume?

In this formula, Reduced Molar Volume uses Molar Volume & Redlich–Kwong parameter b. We can use 1 other way(s) to calculate the same, which is/are as follows -

Reduced Molar Volume = ((1/Reduced Pressure)+(0.26/(3*Reduced Temperature)))/((1/(3*Reduced Temperature))-(0.26*sqrt(Reduced Temperature)))

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