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Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass Calculator

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✖The Weight of Liquid A in a mixture of immiscible liquids.ⓘ Weight of Liquid A [W_A]			+10% -10%
✖The Molecular Mass of Liquid B in a mixture of immiscible liquids.ⓘ Molecular Mass of Liquid B [M_B]			+10% -10%
✖The Weight of Liquid B in a mixture of immiscible liquids.ⓘ Weight of Liquid B [W_B]			+10% -10%
✖The Molecular Mass of Liquid A in a mixture of immiscible liquids.ⓘ Molecular Mass of Liquid A [M_A]			+10% -10%

✖The Ratio of Partial Pressures of 2 immiscible liquids in a mixture.ⓘ Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass [P_A:B]

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Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass Solution

STEP 0: Pre-Calculation Summary

Formula Used

Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)
P_A:B = (W_A*M_B)/(W_B*M_A)
This formula uses 5 Variables

Variables Used

Ratio of Partial Pressures of 2 Immiscible Liquids - The Ratio of Partial Pressures of 2 immiscible liquids in a mixture.
Weight of Liquid A - (Measured in Kilogram) - The Weight of Liquid A in a mixture of immiscible liquids.
Molecular Mass of Liquid B - (Measured in Kilogram) - The Molecular Mass of Liquid B in a mixture of immiscible liquids.
Weight of Liquid B - (Measured in Kilogram) - The Weight of Liquid B in a mixture of immiscible liquids.
Molecular Mass of Liquid A - (Measured in Kilogram) - The Molecular Mass of Liquid A in a mixture of immiscible liquids.

STEP 1: Convert Input(s) to Base Unit

Weight of Liquid A: 0.5 Gram --> 0.0005 Kilogram (Check conversion here)
Molecular Mass of Liquid B: 31.8 Gram --> 0.0318 Kilogram (Check conversion here)
Weight of Liquid B: 0.1 Gram --> 0.0001 Kilogram (Check conversion here)
Molecular Mass of Liquid A: 14.72 Gram --> 0.01472 Kilogram (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P_A:B = (W_A*M_B)/(W_B*M_A) --> (0.0005*0.0318)/(0.0001*0.01472)

Evaluating ... ...

P_A:B = 10.8016304347826

STEP 3: Convert Result to Output's Unit

10.8016304347826 --> No Conversion Required

FINAL ANSWER

10.8016304347826 ≈ 10.80163 <-- Ratio of Partial Pressures of 2 Immiscible Liquids

(Calculation completed in 00.004 seconds)

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Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid

LaTeX Go Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B)

Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass

LaTeX Go Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)

Total Pressure of Mixture of Two Immiscible Liquids

LaTeX Go Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B

Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

LaTeX Go Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B

Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass Formula

LaTeX Go

Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)
P_A:B = (W_A*M_B)/(W_B*M_A)

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass?

Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass calculator uses Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A) to calculate the Ratio of Partial Pressures of 2 Immiscible Liquids, The Ratio of partial vapour pressures of 2 Immiscible Liquids given weight and molecular mass are the two liquids forming a mixture of immiscible liquids. Ratio of Partial Pressures of 2 Immiscible Liquids is denoted by P_A:B symbol.

How to calculate Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass using this online calculator? To use this online calculator for Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass, enter Weight of Liquid A (W_A), Molecular Mass of Liquid B (M_B), Weight of Liquid B (W_B) & Molecular Mass of Liquid A (M_A) and hit the calculate button. Here is how the Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass calculation can be explained with given input values -> 10.80163 = (0.0005*0.0318)/(0.0001*0.01472).

FAQ

What is Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass?

The Ratio of partial vapour pressures of 2 Immiscible Liquids given weight and molecular mass are the two liquids forming a mixture of immiscible liquids and is represented as P_A:B = (W_A*M_B)/(W_B*M_A) or Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A). The Weight of Liquid A in a mixture of immiscible liquids, The Molecular Mass of Liquid B in a mixture of immiscible liquids, The Weight of Liquid B in a mixture of immiscible liquids & The Molecular Mass of Liquid A in a mixture of immiscible liquids.

How to calculate Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass?

The Ratio of partial vapour pressures of 2 Immiscible Liquids given weight and molecular mass are the two liquids forming a mixture of immiscible liquids is calculated using Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A). To calculate Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass, you need Weight of Liquid A (W_A), Molecular Mass of Liquid B (M_B), Weight of Liquid B (W_B) & Molecular Mass of Liquid A (M_A). With our tool, you need to enter the respective value for Weight of Liquid A, Molecular Mass of Liquid B, Weight of Liquid B & Molecular Mass of Liquid A and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Ratio of Partial Pressures of 2 Immiscible Liquids?

In this formula, Ratio of Partial Pressures of 2 Immiscible Liquids uses Weight of Liquid A, Molecular Mass of Liquid B, Weight of Liquid B & Molecular Mass of Liquid A. We can use 1 other way(s) to calculate the same, which is/are as follows -

Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B

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