Ratio of Molar Heat Capacity of Linear Molecule Solution

STEP 0: Pre-Calculation Summary
Formula Used
Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R])
γ = ((((3*N)-2.5)*[R])+[R])/(((3*N)-2.5)*[R])
This formula uses 1 Constants, 2 Variables
Constants Used
[R] - Universal gas constant Value Taken As 8.31446261815324
Variables Used
Ratio of Molar Heat Capacity - The Ratio of Molar Heat Capacity is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume.
Atomicity - The Atomicity is defined as the total number of atoms present in a molecule or element.
STEP 1: Convert Input(s) to Base Unit
Atomicity: 3 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
γ = ((((3*N)-2.5)*[R])+[R])/(((3*N)-2.5)*[R]) --> ((((3*3)-2.5)*[R])+[R])/(((3*3)-2.5)*[R])
Evaluating ... ...
γ = 1.15384615384615
STEP 3: Convert Result to Output's Unit
1.15384615384615 --> No Conversion Required
FINAL ANSWER
1.15384615384615 1.153846 <-- Ratio of Molar Heat Capacity
(Calculation completed in 00.004 seconds)

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University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA
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Ratio of Molar Heat Capacity Calculators

Ratio of Molar Heat Capacity given Molar Heat Capacity at Constant Pressure
​ LaTeX ​ Go Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/(Molar Specific Heat Capacity at Constant Pressure-[R])
Ratio of Molar Heat Capacity given Molar Heat Capacity at Constant Volume
​ LaTeX ​ Go Ratio of Molar Heat Capacity = (Molar Specific Heat Capacity at Constant Volume+[R])/Molar Specific Heat Capacity at Constant Volume
Ratio of Molar Heat Capacity
​ LaTeX ​ Go Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume
Ratio of Molar Heat Capacity given Degree of Freedom
​ LaTeX ​ Go Ratio of Molar Heat Capacity = 1+(2/Degree of Freedom)

Important Formulae on Equipartition Principle and Heat Capacity Calculators

Average Thermal Energy of Non-linear polyatomic Gas Molecule given Atomicity
​ LaTeX ​ Go Thermal Energy given Atomicity = ((6*Atomicity)-6)*(0.5*[BoltZ]*Temperature)
Average Thermal Energy of Linear Polyatomic Gas Molecule given Atomicity
​ LaTeX ​ Go Thermal Energy given Atomicity = ((6*Atomicity)-5)*(0.5*[BoltZ]*Temperature)
Internal Molar Energy of Non-Linear Molecule given Atomicity
​ LaTeX ​ Go Molar Internal Energy = ((6*Atomicity)-6)*(0.5*[R]*Temperature)
Internal Molar Energy of Linear Molecule given Atomicity
​ LaTeX ​ Go Molar Internal Energy = ((6*Atomicity)-5)*(0.5*[R]*Temperature)

Ratio of Molar Heat Capacity of Linear Molecule Formula

​LaTeX ​Go
Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R])
γ = ((((3*N)-2.5)*[R])+[R])/(((3*N)-2.5)*[R])

What is the statement of Equipartition Theorem?

The original concept of equipartition was that the total kinetic energy of a system is shared equally among all of its independent parts, on the average, once the system has reached thermal equilibrium. Equipartition also makes quantitative predictions for these energies. The key point is that the kinetic energy is quadratic in the velocity. The equipartition theorem shows that in thermal equilibrium, any degree of freedom (such as a component of the position or velocity of a particle) which appears only quadratically in the energy has an average energy of ​1⁄2kBT and therefore contributes ​1⁄2kB to the system's heat capacity.

How to Calculate Ratio of Molar Heat Capacity of Linear Molecule?

Ratio of Molar Heat Capacity of Linear Molecule calculator uses Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R]) to calculate the Ratio of Molar Heat Capacity, The Ratio of Molar Heat Capacity of Linear Molecule is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume. Ratio of Molar Heat Capacity is denoted by γ symbol.

How to calculate Ratio of Molar Heat Capacity of Linear Molecule using this online calculator? To use this online calculator for Ratio of Molar Heat Capacity of Linear Molecule, enter Atomicity (N) and hit the calculate button. Here is how the Ratio of Molar Heat Capacity of Linear Molecule calculation can be explained with given input values -> 1.153846 = ((((3*3)-2.5)*[R])+[R])/(((3*3)-2.5)*[R]).

FAQ

What is Ratio of Molar Heat Capacity of Linear Molecule?
The Ratio of Molar Heat Capacity of Linear Molecule is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume and is represented as γ = ((((3*N)-2.5)*[R])+[R])/(((3*N)-2.5)*[R]) or Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R]). The Atomicity is defined as the total number of atoms present in a molecule or element.
How to calculate Ratio of Molar Heat Capacity of Linear Molecule?
The Ratio of Molar Heat Capacity of Linear Molecule is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume is calculated using Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R]). To calculate Ratio of Molar Heat Capacity of Linear Molecule, you need Atomicity (N). With our tool, you need to enter the respective value for Atomicity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Ratio of Molar Heat Capacity?
In this formula, Ratio of Molar Heat Capacity uses Atomicity. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume
  • Ratio of Molar Heat Capacity = 1+(2/Degree of Freedom)
  • Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/(Molar Specific Heat Capacity at Constant Pressure-[R])
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