Pressure Drop in Square Duct Solution

STEP 0: Pre-Calculation Summary
Formula Used
Pressure Drop in Square Duct = (0.6*Friction Factor in Duct*Length of Duct*Mean Velocity of Air^2)/((Side^2)/(2*(Side+Side)))
ΔPs = (0.6*f*L*Vm^2)/((S^2)/(2*(S+S)))
This formula uses 5 Variables
Variables Used
Pressure Drop in Square Duct - (Measured in Pascal) - Pressure Drop in Square Duct due to friction is the decrease in the value of the pressure due to the influence of friction.
Friction Factor in Duct - Friction Factor in Duct is dimensionless number depending upon the surface of the duct.
Length of Duct - (Measured in Meter) - Length of Duct is defined as the measurement or extent of something from end to end of ducts.
Mean Velocity of Air - (Measured in Meter per Second) - Mean Velocity of Air is defined as the time average of the velocity of a fluid at a fixed point, over a somewhat arbitrary time interval T counted from some fixed time t0.
Side - (Measured in Meter) - Side is an upright or sloping surface of a structure or object that is not the top or bottom and generally not the front or back.
STEP 1: Convert Input(s) to Base Unit
Friction Factor in Duct: 0.8 --> No Conversion Required
Length of Duct: 0.0654 Meter --> 0.0654 Meter No Conversion Required
Mean Velocity of Air: 15 Meter per Second --> 15 Meter per Second No Conversion Required
Side: 9 Meter --> 9 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ΔPs = (0.6*f*L*Vm^2)/((S^2)/(2*(S+S))) --> (0.6*0.8*0.0654*15^2)/((9^2)/(2*(9+9)))
Evaluating ... ...
ΔPs = 3.1392
STEP 3: Convert Result to Output's Unit
3.1392 Pascal -->0.32 Millimeter Water (4 °C) (Check conversion ​here)
FINAL ANSWER
0.32 Millimeter Water (4 °C) <-- Pressure Drop in Square Duct
(Calculation completed in 00.004 seconds)

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Pressure Calculators

Dynamic Loss Coefficient given Equivalent Additional Length
​ LaTeX ​ Go Dynamic Loss Coefficient = (Friction Factor in Duct*Equivalent Additional Length)/Hydraulic Mean Depth
Pressure Loss due to Sudden Enlargement
​ LaTeX ​ Go Pressure Loss due to Sudden Enlargement = 0.6*(Velocity of Air at Section 1-Velocity of Air at Section 2)^2
Dynamic Loss Coefficient given Dynamic Pressure Loss
​ LaTeX ​ Go Dynamic Loss Coefficient = Dynamic Pressure Loss/(0.6*Velocity of Air^2)
Dynamic Pressure Loss
​ LaTeX ​ Go Dynamic Pressure Loss = Dynamic Loss Coefficient*0.6*Velocity of Air^2

Pressure Drop in Square Duct Formula

​LaTeX ​Go
Pressure Drop in Square Duct = (0.6*Friction Factor in Duct*Length of Duct*Mean Velocity of Air^2)/((Side^2)/(2*(Side+Side)))
ΔPs = (0.6*f*L*Vm^2)/((S^2)/(2*(S+S)))

Pressure drop in ducts

Pressure loss in ductwork has three components, frictional losses along duct walls and dynamic losses in fittings, and component losses in duct-mounted equipment. Due to physical items with known pressure drops, such as hoods, filters, louvers, or dampers.

How to Calculate Pressure Drop in Square Duct?

Pressure Drop in Square Duct calculator uses Pressure Drop in Square Duct = (0.6*Friction Factor in Duct*Length of Duct*Mean Velocity of Air^2)/((Side^2)/(2*(Side+Side))) to calculate the Pressure Drop in Square Duct, Pressure Drop in Square Duct formula is defined as a measure of the loss of pressure that occurs in a square duct due to frictional forces, which is an important parameter in designing and optimizing duct systems, particularly in heating, ventilation, and air conditioning applications. Pressure Drop in Square Duct is denoted by ΔPs symbol.

How to calculate Pressure Drop in Square Duct using this online calculator? To use this online calculator for Pressure Drop in Square Duct, enter Friction Factor in Duct (f), Length of Duct (L), Mean Velocity of Air (Vm) & Side (S) and hit the calculate button. Here is how the Pressure Drop in Square Duct calculation can be explained with given input values -> 0.03262 = (0.6*0.8*0.0654*15^2)/((9^2)/(2*(9+9))).

FAQ

What is Pressure Drop in Square Duct?
Pressure Drop in Square Duct formula is defined as a measure of the loss of pressure that occurs in a square duct due to frictional forces, which is an important parameter in designing and optimizing duct systems, particularly in heating, ventilation, and air conditioning applications and is represented as ΔPs = (0.6*f*L*Vm^2)/((S^2)/(2*(S+S))) or Pressure Drop in Square Duct = (0.6*Friction Factor in Duct*Length of Duct*Mean Velocity of Air^2)/((Side^2)/(2*(Side+Side))). Friction Factor in Duct is dimensionless number depending upon the surface of the duct, Length of Duct is defined as the measurement or extent of something from end to end of ducts, Mean Velocity of Air is defined as the time average of the velocity of a fluid at a fixed point, over a somewhat arbitrary time interval T counted from some fixed time t0 & Side is an upright or sloping surface of a structure or object that is not the top or bottom and generally not the front or back.
How to calculate Pressure Drop in Square Duct?
Pressure Drop in Square Duct formula is defined as a measure of the loss of pressure that occurs in a square duct due to frictional forces, which is an important parameter in designing and optimizing duct systems, particularly in heating, ventilation, and air conditioning applications is calculated using Pressure Drop in Square Duct = (0.6*Friction Factor in Duct*Length of Duct*Mean Velocity of Air^2)/((Side^2)/(2*(Side+Side))). To calculate Pressure Drop in Square Duct, you need Friction Factor in Duct (f), Length of Duct (L), Mean Velocity of Air (Vm) & Side (S). With our tool, you need to enter the respective value for Friction Factor in Duct, Length of Duct, Mean Velocity of Air & Side and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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